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#1
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On Fri, 20 Nov 2009 08:52:25 -0800, Jeff Liebermann
wrote: On Thu, 19 Nov 2009 13:20:01 -0800, Richard Clark wrote: My model shows a more benign mismatch to a 72 Ohm load. Richard Clark, KB7QHC I built several models of the antenna folded dipole assembly. The simple rectangular rod folded dipole yielded about 300 ohms. A slightly better simulation of the rounded ends, but still using a round rod, was about 260 ohms. Converting it to a flat wire ended up about 280 ohms. I never got anything even close to 72 ohms. It's my http://802.11junk.com/jeffl/antennas/mfj1800/ EZNEC shows: Impedance = 73.13 + J 18.78 ohms which, I suppose, could have the reactance driven out if I shift frequency. Show my your NEC2 deck and tell me what I did wrong, and maybe I'll believe that it's 72 ohms. Incidentally, the possibility that I screwed up somewhere in the model is quite real: http://802.11junk.com/jeffl/antennas/mfj1800/mfj1800.txt (I'll convert this mess back to a macro form so it's easier to read maybe this weekend). I don't have an option of NEC2 deck. One thing you might check, and is something I reported about, is does your model have the loop symmetrical to the plane of the directors/reflector? I followed all of Mike's dimensions and I note that your lobe characteristics don't show his lack of driven element symmetry - mine do. Again, I have modeled only the three elements (Ref/Dr/Dir) as the additional directors are unlikely to perturb drive point Z as much as to push it from 73 Ohms up to your high 200s (triple?). Another point, as I have described, I used 1/4 inch diameter wire in place of larger flat sheet metal elements (which I note you try to replecate, but only once). True, 1/4 inch is not as big as any flat dimension, but as Roy reports on equivalence, flat is not the same as diameter, but flat performance is closer to a smaller diameter round wire. Hence the 1/4 inch. 73's Richard Clark, KB7QHC |
#2
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On Fri, 20 Nov 2009 10:46:40 -0800, Richard Clark
wrote: Show my your NEC2 deck and tell me what I did wrong, and maybe I'll believe that it's 72 ohms. Incidentally, the possibility that I screwed up somewhere in the model is quite real: http://802.11junk.com/jeffl/antennas/mfj1800/mfj1800.txt (I'll convert this mess back to a macro form so it's easier to read maybe this weekend). I don't have an option of NEC2 deck. No problem. Just post or email me the .EZ file. 4NEC2 will import it or I'll just switch to EZNEC. (I promise not to complain about your using inches). One thing you might check, and is something I reported about, is does your model have the loop symmetrical to the plane of the directors/reflector? Unfortunately, yes. I got lazy and planted the folded dipole centered about the axis of the other elements. I don't think (guess) it would make much difference, but I'll move it to the correct position this weekend. Got any theory as to why the vertical and horizontal patterns are so different? That only appeared when I switched to the flat wire folded dipole. They were symmetrical with the wire rod driven element. I followed all of Mike's dimensions and I note that your lobe characteristics don't show his lack of driven element symmetry - mine do. Again, I have modeled only the three elements (Ref/Dr/Dir) as the additional directors are unlikely to perturb drive point Z as much as to push it from 73 Ohms up to your high 200s (triple?). Yes, something is different. In past tinkering, I've found that 3 elements is sufficient to characterize the feed impedance, where the additional elements just improve the gain and pattern. Another point, as I have described, I used 1/4 inch diameter wire in place of larger flat sheet metal elements (which I note you try to replecate, but only once). True, 1/4 inch is not as big as any flat dimension, but as Roy reports on equivalence, flat is not the same as diameter, but flat performance is closer to a smaller diameter round wire. Hence the 1/4 inch. Well, I used a rod with the same circumference as the flat (asymetrical) elements. Methinks the element diameter would have an effect on the bandwidth of the antenna, but not on its characteristic impedance. 73's Richard Clark, KB7QHC thanks much... -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#3
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![]() "Richard Clark" wrote in message ... On Fri, 20 Nov 2009 08:52:25 -0800, Jeff Liebermann wrote: On Thu, 19 Nov 2009 13:20:01 -0800, Richard Clark wrote: My model shows a more benign mismatch to a 72 Ohm load. Richard Clark, KB7QHC I built several models of the antenna folded dipole assembly. The simple rectangular rod folded dipole yielded about 300 ohms. A slightly better simulation of the rounded ends, but still using a round rod, was about 260 ohms. Converting it to a flat wire ended up about 280 ohms. I never got anything even close to 72 ohms. It's my http://802.11junk.com/jeffl/antennas/mfj1800/ EZNEC shows: Impedance = 73.13 + J 18.78 ohms which, I suppose, could have the reactance driven out if I shift frequency. Show my your NEC2 deck and tell me what I did wrong, and maybe I'll believe that it's 72 ohms. Incidentally, the possibility that I screwed up somewhere in the model is quite real: http://802.11junk.com/jeffl/antennas/mfj1800/mfj1800.txt (I'll convert this mess back to a macro form so it's easier to read maybe this weekend). I don't have an option of NEC2 deck. One thing you might check, and is something I reported about, is does your model have the loop symmetrical to the plane of the directors/reflector? I followed all of Mike's dimensions and I note that your lobe characteristics don't show his - mine do. 73's Richard Clark, KB7QHC Hi Richard, What do you mean by "lack of driven element symmetry" ? Mike |
#4
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On Fri, 20 Nov 2009 18:26:17 -0600, "amdx" wrote:
Hi Richard, What do you mean by "lack of driven element symmetry" ? Mike Hi Mike, The driven loop is not symettrical to the plane of the directors and reflector, thus it peers down (or up, or to the side - depending on deployment). Look boresight down the boom. The loop is off-center. 73's Richard Clark, KB7QHC |
#5
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![]() "Richard Clark" wrote in message ... On Fri, 20 Nov 2009 18:26:17 -0600, "amdx" wrote: Hi Richard, What do you mean by "lack of driven element symmetry" ? Mike Hi Mike, The driven loop is not symettrical to the plane of the directors and reflector, thus it peers down (or up, or to the side - depending on deployment). Look boresight down the boom. The loop is off-center. 73's Richard Clark, KB7QHC Good, I thought that might be the answer but wanted to check. Glad I added that detail to the drawing, do you think that is engineered to control output impedance? What happens to the impedance if you center it? Could you post your model or send it to me, I have a fellow ham that tried to model the FD and could not get it to work. He would like to see one that does work and find out what he did wrong. Eznec if you have it. Thanks, Mike |
#6
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On Sat, 21 Nov 2009 06:24:49 -0600, "amdx" wrote:
Could you post your model or send it to me, I have a fellow ham that tried to model the FD and could not get it to work. He would like to see one that does work and find out what he did wrong. Eznec if you have it. Thanks, Mike Hi Mike, It has been posted to you as you asked. Jeff also has a copy. Can you tell us what you mean about your buddy's model and how he "could not get it to work?" Did he follow your dimensions? 73's Richard Clark, KB7QHC |
#7
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![]() "Richard Clark" wrote in message ... On Sat, 21 Nov 2009 06:24:49 -0600, "amdx" wrote: Could you post your model or send it to me, I have a fellow ham that tried to model the FD and could not get it to work. He would like to see one that does work and find out what he did wrong. Eznec if you have it. Thanks, Mike Hi Mike, It has been posted to you as you asked. Jeff also has a copy. Can you tell us what you mean about your buddy's model and how he "could not get it to work?" Did he follow your dimensions? 73's Richard Clark, KB7QHC He's out of town for a couple of days, when he returns I'll quiz him. Mike |
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