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![]() "Richard Clark" wrote in message ... On Fri, 20 Nov 2009 18:26:17 -0600, "amdx" wrote: Hi Richard, What do you mean by "lack of driven element symmetry" ? Mike Hi Mike, The driven loop is not symettrical to the plane of the directors and reflector, thus it peers down (or up, or to the side - depending on deployment). Look boresight down the boom. The loop is off-center. 73's Richard Clark, KB7QHC Good, I thought that might be the answer but wanted to check. Glad I added that detail to the drawing, do you think that is engineered to control output impedance? What happens to the impedance if you center it? Could you post your model or send it to me, I have a fellow ham that tried to model the FD and could not get it to work. He would like to see one that does work and find out what he did wrong. Eznec if you have it. Thanks, Mike |
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