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![]() "Cecil Moore" wrote ... On May 19, 3:55 am, "Szczepan Bialek" wrote: It seems that radio waves are produced from ends of the wire where the voltage is doubled (at least) The quantum electrodynamics process for the generation of EM waves is well understood. The electron carriers in the wire are alternately accelerated and decelerated by the transmit signal energy. During the acceleration process, electrons absorb energy. During the deceleration process, electrons emit photons, the quantum particles associated with the radiated EM waves. Electrons at the ends of a wire dipole are not accelerated as much as the electrons in the middle of the dipole. It was a few weeks ago. Electrons are decelerated at the ands of the dipole. Next they accelerate and in the middle (of the oryginal Hertz dipole) the speed of electrons is constant (no acceleration/deceleration). In textbooks are prsented all theories and hipothesis. It is your choose which one do you prefer: EM, photons, QED or like sound. "QED mathematically describes all phenomena involving electrically charged particles interacting by means of exchange of photons". QED is about Photons, not EM waves. Photons have the analogy in phonons. So radio waves are like the sound. S* |
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