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On Jun 2, 6:33*pm, Keith Dysart wrote:
The voltage and current distribution on a transmission line can be solved with a set of differential equations which satisfy some boundary conditions. I am not interested in voltage and current. Like optical physicists, I am only interested in tracking the RF energy flow. It does not make these waves any more real. Agreed, but the point is that it does not make the traveling waves any LESS real! I bring you back to a previous question which you have never answered... On an ideal line with 100% reflection, there are points where the current and voltage is always 0. Knowing that if either current or voltage is 0, power is also 0, how does energy cross these point? Good grief, I have answered that question at least a dozen times. The net current being zero is just an illusion caused by superposition of two magnetic fields propagating in opposite directions that are equal in magnitude and opposite in phase. The two traveling waves keep on trucking at their relatively constant ExH energy levels in opposite directions. If you want to account for the energy, when the current is zero, all of the energy existing at that point is in the electric field and, sure enough, the voltage is at a maximum at that point- duuuhhhh again. There is absolutely no point on an active transmission line where the net energy level is zero. Again, you guys are never going to convince anyone that the Golden Gate Bridge doesn't need maintenance because the net traffic on the bridge is zero. How the heck can thousands of vehicles traveling one direction while the same number of vehicles are traveling in the opposite direction add up to zero effect in reality? Please get real. And if I cut the line at all the places where the current is zero, it does not alter the energy distribution on the line one iota. How can this be if energy is travelling from end to end on the line? As I told you years ago, when you cut the line, you radically change the impedance and create a reflection that didn't exist before you cut the line. Hint: There are no reflections at a point of constant Z0. There are only reflections at an impedance discontinuity. The alteration of the energy distribution (to which you seem to be blind) can easily be observed in a TV system. PHYSICS has long given up on the idea of waves being an explanation for light. And RF waves are technically light, just not visible light. When I was rummaging through the Texas A&M library, I found a book entitled, "Light". It covered the subject of RF waves. EM waves are analog and in no way encompass the quantum nature of photons. You could become famous if you can prove that EM waves are not quantized. Good luck on that one. No one has claimed that EM waves stand still, ... Please prove your ridiculous assertion that no one has ever claimed that EM waves can stand still. -- 73, Cecil, w5dxp.com |
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