On 6/25/2010 12:06 PM, Szczepan Bialek wrote:

They must: " In electronic circuit theory, a "ground" is usually idealized
as an
infinite source or sink for charge, which can absorb an unlimited amount of
current without changing its potential."

Your mistake here is to assume that because they can sink current that
the are sinking DC current. The "ground", as you like to think about it
may carry current during the RF cycle, but there is nothing that would
cause an unbalanced charge buildup since it IS symmetrical.

tom
K0TAR

On 6/25/2010 8:37 PM, tom wrote:
On 6/25/2010 12:06 PM, Szczepan Bialek wrote:

They must: " In electronic circuit theory, a "ground" is usually
idealized
as an
infinite source or sink for charge, which can absorb an unlimited
amount of
current without changing its potential."

Your mistake here is to assume that because they can sink current that
the are sinking DC current. The "ground", as you like to think about it
may carry current during the RF cycle, but there is nothing that would
cause an unbalanced charge buildup since it IS symmetrical.

tom
K0TAR

And I forgot to include that there is no field emission, so no charge
could possibly build up.

tom
K0TAR

"tom" wrote
. net...

And I forgot to include that there is no field emission, so no charge
could possibly build up.

Emission is the result of voltage.

If the power is ON the emissin take place.
S*

On 6/26/2010 2:38 AM, Szczepan Bialek wrote:
wrote
. net...

And I forgot to include that there is no field emission, so no charge
could possibly build up.

Emission is the result of voltage.

If the power is ON the emissin take place.
S*



Incorrect.

tom
K0TAR

"tom" wrote
. net...
On 6/26/2010 2:38 AM, Szczepan Bialek wrote:
wrote
. net...

And I forgot to include that there is no field emission, so no charge
could possibly build up.

Emission is the result of voltage.

If the power is ON the emissin take place.

Incorrect.

"(II) Field emission: In this method, a strong electric field (i.e. a high
positive voltage) is applied at the metal surface which pulls the free
electrons out of the metal because of the attraction of positive field. The
strong the electric field, the greater is the electron emission. "

You are incorrect.
S*

On Jun 27, 9:28*am, "Szczepan Bialek" wrote:
*"tom" ouse.net...

On 6/26/2010 2:38 AM, Szczepan Bialek wrote:
*wrote
e.net...

And I forgot to include that there is no field emission, so no charge
could possibly build up.

Emission is the result of voltage.

If the power is ON the emissin take place.

Incorrect.

"(II) Field emission: In this method, a strong electric field (i.e. a high
positive voltage) is applied at the metal surface which pulls the free
electrons out of the metal because of the attraction of positive field. The
strong the electric field, the greater is the electron emission. "

You are incorrect.
S*

that quote is correct... unfortunately the voltages created by most
radio transmitters aren't high enough to overcome the metal work
function so no field emission takes place from antennas. and even if
it did it wouldn't go anywhere because radio waves are symmetric.

"tom" wrote
t...
On 6/25/2010 12:06 PM, Szczepan Bialek wrote:

They must: " In electronic circuit theory, a "ground" is usually
idealized
as an
infinite source or sink for charge, which can absorb an unlimited
amount of
current without changing its potential."

Your mistake here is to assume that because they can sink current that the
are sinking DC current. The "ground", as you like to think about it may
carry current during the RF cycle, but there is nothing that would cause
an unbalanced charge buildup since it IS symmetrical.

Your mistake here is to assume that the RF cycle, IS symmetrical.

Each real wave is asymmetrical. The forward pulse is always stronger than
the return.
For this reason you must have power on.
S*

On 6/26/2010 2:34 AM, Szczepan Bialek wrote:
wrote
t...
On 6/25/2010 12:06 PM, Szczepan Bialek wrote:

They must: " In electronic circuit theory, a "ground" is usually
idealized
as an
infinite source or sink for charge, which can absorb an unlimited
amount of
current without changing its potential."

Your mistake here is to assume that because they can sink current that the
are sinking DC current. The "ground", as you like to think about it may
carry current during the RF cycle, but there is nothing that would cause
an unbalanced charge buildup since it IS symmetrical.

Your mistake here is to assume that the RF cycle, IS symmetrical.

Each real wave is asymmetrical. The forward pulse is always stronger than
the return.
For this reason you must have power on.
S*




Incorrect.

tom
K0TAR