On Jun 13, 2:04*pm, Cecil Moore wrote:
On Jun 13, 5:35*am, K1TTT wrote:

On Jun 13, 12:00*am, Cecil Moore wrote:
The answer to that question will reveal exactly what
happens to the reflected energy.

i don't care, i know that the superimposed voltage or current is
zero. *from that i can calculate the power or energy anywhere i
want. why does anyone care about 'energy' anyway, ...

You get exactly the same answers doing it my way but my way yields the
additional information of exactly what happens to the energy
components. When two wavefronts superpose to zero indefinitely, I
would take that as proof of interaction and wave cancellation.

This is what invariably happens to the discussion. After being told
that I am absolutely wrong about energy flow, I introduce the known
laws of EM physics from the field of optics and prove that they
provide exactly the same answers as a conventional RF analysis. After
some discussion, it is asserted that the person (not only you) doesn't
care and it doesn't matter anyway. W7EL says in his food-for-thought
article, "I personally don’t have a compulsion to understand where
this power 'goes'."

A 1/4WL series matching stub is essentially the same function in
concept as a 1/4WL thin-film coating on non-reflective glass. How the
non-reflective glass works is perfectly understood and a 1/4WL series
matching section works the same way. Why not glean some knowledge from
the field of optics if it helps hams to understand "where the power
goes"? Optical physicists were forced to track power density from the
very start of their science because they didn't have the luxury of
tracking the voltage and current.

Here's a brain teaser for you and others. Given a Z01 to Z02 impedance
discontinuity with a power reflection coefficient of 0.25 at the '+'
discontinuity:

------Z01------+------Z02-------load

Pfor1 in the Z01 section is 100 watts. Pref1 in the Z01 section is
zero watts.

What is Pfor2, Pref2, and the SWR in the Z02 section?

so? *what does this special case prove that hundreds of others
doesn't?

The magnitudes of the voltages and currents in the above example are
indeterminate. Can you (or anyone else) solve the problem without
resorting to voltage and current calculations? I am just trying to get
people to think outside of their rigid concrete voltage/current boxes.
--
73, Cecil, w5dxp.com

why are they indeterminate? i can calculate them, why can't you?