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On Jun 16, 1:48*am, Owen Duffy wrote:
Prs is not simply equal to the 'reflected power'. I don't remember anyone saying that Prs is equal to the reflected power and of course it is not. What you guys are missing are the effects accompanying interference from superposition. There is another mechanism besides the reflection mechanism that can redistribute the reflected power. The power density equation includes an interference term that indicates what happens to the energy. Prs = Pfor + Pref + 2*SQRT(Pfor*Pref)*cos(A) This equation gives the same answer as your equation but it also indicates what happens to the energy components. A is the phase angle between Vfor and Vref. The last term is the *interference* term. If the interference term is zero, there is no interference and all of the reflected power is dissipated in Rs. If the interference term is negative, there exists destructive interference at Rs and power is redistributed toward the load as constructive interference. This is technically not a reflection although the results are the same as a reflection. If the interference term is positive, there exists constructive interference at Rs and excess power is dissipated in Rs. Let's look at your equation, Prs=(Vs/2-Vr)^2/Rs Vfor = Vs/2, so Prs = (Vfor+Vref)^2/Rs (phasor addition) Prs = Vfor^2/Rs + Vref^2/Rs + 2*Vfor*Vref*cos(A)/Rs Prs = Pfor + Pref + 2*SQRT(Pfor*Pref)*cos(A) I just derived the power density equation (with its interference term) from your equation. The power density equation reveals the interference term which tells us exactly where the reflected power goes. I learned about destructive and constructive interference at Texas A&M in the 1950s. -- 73, Cecil, w5dxp.com |
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