Home |
Search |
Today's Posts |
#23
![]() |
|||
|
|||
![]()
On 9/1/2010 9:20 AM, Cecil Moore wrote:
... It seems logical that the highest I^2*R losses would be where the standing-wave current is maximum and the highest dielectric losses wold be where the the standing-wave voltage is maximum. As Owen is fond of pointing out, the locations of those points are very important. If a current maximum point exists at the load and a voltage maximum point exists at the source, the losses at the load are probably higher than the losses at the source on HF. If a voltage maximum point exists at the load and a current maximum point exists at the source, the losses at the load are probably lower than the losses at the source on HF (assuming that losses due to SWR are mostly I^2*R losses on HF). -- 73, Cecil, w5dxp.com Uhhh, sorry to pose this question to you here but, doesn't a "tuner" really just "shorten" and "lengthen" the feed line? I mean, not physically, of course. But, it would seem to me that, this is exactly what my xmitter and ant are "seeing." Regards, JS |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
AM-loop versus whip antennas | Shortwave | |||
Vertical Whip Antennas And Gain Question ? | Antenna | |||
source for replacement whip antennas? | Shortwave | |||
Super-whippy whip antennas | Homebrew | |||
Super-whippy whip antennas | Homebrew |