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#1
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On Oct 17, 6:42*am, Alejandro Lieber alejan...@Use-Author-Supplied-
Address.invalid wrote: It appears to me that in the short circuited turns, a very big current must be circulating, adding heat losses and lowering the Q of the circuit.. For a screwdriver antenna, the problem is solved by a conductive sleeve over the outside of the shorted turns that keeps most of the RF on the conductive sleeve instead of in the shorted turns of the coil. -- 73, Cecil, w5dxp.com |
#2
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On Oct 17, 2:36*pm, Cecil Moore wrote:
On Oct 17, 6:42*am, Alejandro Lieber alejan...@Use-Author-Supplied- Address.invalid wrote: It appears to me that in the short circuited turns, a very big current must be circulating, adding heat losses and lowering the Q of the circuit. For a screwdriver antenna, the problem is solved by a conductive sleeve over the outside of the shorted turns that keeps most of the RF on the conductive sleeve instead of in the shorted turns of the coil. -- 73, Cecil, w5dxp.com that doesn't really 'solve' it, that just provides a single big shorted turn instead of many turns. |
#3
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On Oct 17, 9:52*am, K1TTT wrote:
that doesn't really 'solve' it, that just provides a single big shorted turn instead of many turns. Maybe the single big shorted turn IS the solution? :-) When there are no actual shorted turns, i.e. all of the coil is exposed, does the bottom section of aluminum tubing become that same single big shorted turn? In any case, one very conductive and very wide shorted turn is a lot less lossy than a number of small shorted turns. -- 73, Cecil, w5dxp.com |
#4
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On Oct 17, 3:09*pm, Cecil Moore wrote:
On Oct 17, 9:52*am, K1TTT wrote: that doesn't really 'solve' it, that just provides a single big shorted turn instead of many turns. Maybe the single big shorted turn IS the solution? :-) When there are no actual shorted turns, i.e. all of the coil is exposed, does the bottom section of aluminum tubing become that same single big shorted turn? no, it becomes a very small diameter and long shorted turn... but yes, it is a shorted turn. you don't see as much effect because it is smaller in diameter so the self inductance is smaller and it only intercepts a fraction of the flux from the end of the coil. you get more of an effect if you place an air core coil with its end near the side or bottom of a metallic enclosure, the plate looks like a shorted coil and can have large circulating currents. In any case, one very conductive and very wide shorted turn is a lot less lossy than a number of small shorted turns. -- 73, Cecil, w5dxp.com that is why they get away with it, the losses in the big fat thing are low enough that it causes less trouble than shorting turns with a switch or relays. |
#5
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Cecil Moore wrote:
On Oct 17, 6:42 am, Alejandro Lieber alejan...@Use-Author-Supplied- Address.invalid wrote: It appears to me that in the short circuited turns, a very big current must be circulating, adding heat losses and lowering the Q of the circuit. For a screwdriver antenna, the problem is solved by a conductive sleeve over the outside of the shorted turns that keeps most of the RF on the conductive sleeve instead of in the shorted turns of the coil. -- 73, Cecil, w5dxp.com But, isn't that conductive sleeve itself a shorted turn? It's conductive, coaxial with the rest of the inductor above the sleeve, so the magnetic field certainly passes through it. I think the real answer is that everything is a tradeoff. |
#6
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On Oct 18, 11:04*am, Jim Lux wrote:
But, isn't that conductive sleeve itself a shorted turn? Yes, but that particular low-loss shorted turn solves the problem that needs solving. Nobody said it was a perfect solution. -- 73, Cecil, w5dxp.com |
#7
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On Oct 18, 9:57*pm, Cecil Moore wrote:
On Oct 18, 11:04*am, Jim Lux wrote: But, isn't that conductive sleeve itself a shorted turn? Yes, but that particular low-loss shorted turn solves the problem that needs solving. Nobody said it was a perfect solution. -- 73, Cecil, w5dxp.com well, if its not the perfect solution then the problem is not completely solved... so there must be a better solution to really solve the problem. |
#8
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On Oct 18, 5:13*pm, K1TTT wrote:
well, if its not the perfect solution then the problem is not completely solved... so there must be a better solution to really solve the problem. The problem of transmission line losses can be solved with a perfect lossless transmission line. Have you seen such or does reality force us to settle for a reasonable non-perfect solution? -- 73, Cecil, w5dxp.com |
#9
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K1TTT wrote:
On Oct 18, 9:57 pm, Cecil Moore wrote: On Oct 18, 11:04 am, Jim Lux wrote: But, isn't that conductive sleeve itself a shorted turn? Yes, but that particular low-loss shorted turn solves the problem that needs solving. Nobody said it was a perfect solution. -- 73, Cecil, w5dxp.com well, if its not the perfect solution then the problem is not completely solved... so there must be a better solution to really solve the problem. one could simply slit the tube (and finger stock at top). Consider that the lower tube is serving two purposes: mechanical support and a movable contact on the inductor. |
#10
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On 10/18/10 12:04 PM, Jim Lux wrote:
Cecil Moore wrote: On Oct 17, 6:42 am, Alejandro Lieber alejan...@Use-Author-Supplied- Address.invalid wrote: It appears to me that in the short circuited turns, a very big current must be circulating, adding heat losses and lowering the Q of the circuit. For a screwdriver antenna, the problem is solved by a conductive sleeve over the outside of the shorted turns that keeps most of the RF on the conductive sleeve instead of in the shorted turns of the coil. -- 73, Cecil, w5dxp.com But, isn't that conductive sleeve itself a shorted turn? It's conductive, coaxial with the rest of the inductor above the sleeve, so the magnetic field certainly passes through it. Whic of course means that everything everywhere is a shorted turn. 8^) I think the real answer is that everything is a tradeoff. That's a pretty good answer. |
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