On Feb 20, 8:59*am, "Szczepan Bialek" wrote:
"tom" napisal w wiadomoscinews:4d606204$0$87583$8046368a@newsreade r.iphouse.net...



On 2/19/2011 11:41 AM, Szczepan Bialek wrote:

http://www.qsl.net/vk5br/UwaterComms.htm

I don't see where you explained anything about the electrons. *The article
doesn't, either.

I'll repeat the question in case you forgot it again.

"so how do the electrons get through the salt water?"

And of course then we have the problem of RF communications with people
who are in caves.

How do the electrons get through the dirt? *Which seems to be even less
likely than salt water.

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.
S*

but then why can't i measure dc current from my antenna? and why do
my oscillations look so symmetric?

"K1TTT" napisal w wiadomosci
...
On Feb 20, 8:59 am, "Szczepan Bialek" wrote:

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.

but then why can't i measure dc current from my antenna? and why do
my oscillations look so symmetric?

To measure it you must have an equipment and good will.
The last is more important.

Look at the original Hertz apparatus:
http://people.seas.harvard.edu/~jone...ertz/S_p11.gif

To have one portion of radiation it is enough to charge one half of the
dipole. Charging is made with DC.
After some time you can repeat it.

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

In damped waves each amplitude is smaller than the previous. So in one cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

On Feb 21, 9:41*am, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 20, 8:59 am, "Szczepan Bialek" wrote:

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.

but then why can't i measure dc current from my antenna? *and why do

my oscillations look so symmetric?

To measure it you must have an equipment and good will.
The last is more important.

Look at the original Hertz apparatus:http://people.seas.harvard.edu/~jone...res/lecture6/h...

To have one portion of radiation it is enough to charge one half of the
dipole. Charging is made with DC.
After some time you can repeat it.

The radiation is in form of *the damped wave:http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

In damped waves each amplitude is smaller than the previous. So in one cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

"K1TTT" napisal w wiadomosci
...
On Feb 21, 9:41 am, "Szczepan Bialek" wrote:

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

? In damped waves each amplitude is smaller than the previous. So in one
cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

If electrons jump off from antennas it will be easy to measure in klystron:
http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

On Feb 21, 6:07*pm, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 21, 9:41 am, "Szczepan Bialek" wrote:

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

? In damped waves each amplitude is smaller than the previous. So in one
cycle

no symmetry.

It is obvious. But you can try to detect it.
S*
can't detect it here, my waves look like perfectly symmetric sine

waves and i can not measure dc on antenna. *how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

feedpoint is 50 ohms, and 99% efficient... how much now?



If electrons jump off from antennas it will be easy to measure in klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

i have worked with klystrons... the current in equals the current out,
all electrons are accounted for.

"K1TTT" napisal w wiadomosci
...
On Feb 21, 6:07 pm, "Szczepan Bialek" wrote:

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

feedpoint is 50 ohms, and 99% efficient... how much now?

And peak voltage at the end?


If electrons jump off from antennas it will be easy to measure in
klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

i have worked with klystrons... the current in equals the current out,
all electrons are accounted for.

So in your area the field emission do not work.
S*

On Feb 22, 8:44*am, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 21, 6:07 pm, "Szczepan Bialek" wrote:



can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.
feedpoint is 50 ohms, and 99% efficient... how much now?

And peak voltage at the end?



If electrons jump off from antennas it will be easy to measure in
klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*
i have worked with klystrons... the current in equals the current out,

all electrons are accounted for.

So in your area the field emission do not work.
S*

i don't have any electrons jumping off my antennas... but i still talk
around the world. your theory must be wrong.