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On Feb 28, 3:52*am, "Szczepan Bialek" wrote:
A loop is like a short circuit. What do a Electromagnetic pulse in a loop? It simply travel *trough the loop and looks like the "reflected with the opposite polarity ". Why am I wrong and D. Russell is right? What you are missing is that the loop is an antenna, not a transmission line. On a transmission line, the currents are differential, i.e. 180 degrees out of phase and a short-circuit is possible. At the antenna feedpoint the left differential current takes a 90 degree turn to the left. The right differential current takes a 90 degree turn to the right. *That puts the antenna currents in phase*, i.e. in common-mode, so a short circuit on an antenna 40 feet in the air is not possible. The fields that are 180 degrees out of phase no longer cancel because of the physical distance between them. From the feedpoint of the antenna, there is no such thing as waves launched in opposite directions on the wire *at the same time*. What you are missing is there is no short-circuit half way around a loop because there is no impedance discontinuity at that point. Forward waves continue traveling forward and reflected waves continue to travel backwards at that point because there is no impedance discontinuity at that point. It takes an impedance discontinuity to cause a reflection. Assuming a circular horizontal loop (for the sake of conceptual simplicity) the only impedance discontinuity is at the feedpoint. -- 73, Cecil, w5dxp.com |
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