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#1
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John wrote:
I didn't know I could model loops in EZNEC. But now I see that it has problems only with small loops. I guess a 1/4-wave loop is not considered small. I'll go back and try it. . . . Because EZNEC uses NEC-2 for calculations, it has the same problems with small loops that NEC-2 does. It's able to model any kind of antenna that NEC-2 can, within its segment limitation. Roy Lewallen, W7EL |
#2
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![]() "Roy Lewallen" wrote in message ... John wrote: I didn't know I could model loops in EZNEC. But now I see that it has problems only with small loops. I guess a 1/4-wave loop is not considered small. I'll go back and try it. . . . Because EZNEC uses NEC-2 for calculations, it has the same problems with small loops that NEC-2 does. It's able to model any kind of antenna that NEC-2 can, within its segment limitation. Roy Lewallen, W7EL I don't know what NEC-2 is able to do. Does this mean I can model folded monopoles? John |
#3
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John wrote:
I don't know what NEC-2 is able to do. Does this mean I can model folded monopoles? John Sure. But you can't accurately model ones made with twinlead or window line, since NEC-2 or EZNEC can't account for the effect of the dielectric. Roy Lewallen, W7EL |
#4
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![]() "Roy Lewallen" wrote in message ... John wrote: I don't know what NEC-2 is able to do. Does this mean I can model folded monopoles? John Sure. But you can't accurately model ones made with twinlead or window line, since NEC-2 or EZNEC can't account for the effect of the dielectric. Roy Lewallen, W7EL Okay, great! I modeled a folded monopole at 434 MHz. Varying the length down from resonance, the element showed the terminal impedance getting lower in resistance and become increasingly capacitive just like the unfolded monopole. I thought it was supposed to be backwards from the usual unfolded monopole such that it would go up in resistance and become inductive.?. John |
#5
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![]() "John" wrote in message ... "Roy Lewallen" wrote in message ... John wrote: I don't know what NEC-2 is able to do. Does this mean I can model folded monopoles? John Sure. But you can't accurately model ones made with twinlead or window line, since NEC-2 or EZNEC can't account for the effect of the dielectric. Roy Lewallen, W7EL Okay, great! I modeled a folded monopole at 434 MHz. Varying the length down from resonance, the element showed the terminal impedance getting lower in resistance and become increasingly capacitive just like the unfolded monopole. I thought it was supposed to be backwards from the usual unfolded monopole such that it would go up in resistance and become inductive.?. John Did you go down to 217 MHz and below? If not, check it out. Should hit another resonance at something like 50,000 +j0, and stay inductive below that. Tam/WB2TT |
#6
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John wrote:
. . . I thought it was supposed to be backwards from the usual unfolded monopole such that it would go up in resistance and become inductive.?. Why would it do that? Roy Lewallen, W7EL |
#7
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![]() "Roy Lewallen" wrote in message ... John wrote: . . . I thought it was supposed to be backwards from the usual unfolded monopole such that it would go up in resistance and become inductive.?. Why would it do that? Roy Lewallen, W7EL Well, you said earlier that the folded monopole could be modeled as an unfolded monopole with a shorted transmission line in parallel. I thought I understood. When I modeled the unfolded monopole, I saw it do as usual when the element was varied in length. But when I included the shorted section of transmission line and varied it directly with the element, I thought I saw the terminal reactance go inductive as the length was decreased below 1/4-wave resonance and I thought the terminal resistance went up. So, I was expecting the same from EZNEC by modeling the folded version. I guess I'm really lost here. John |
#8
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I'll once again separate the "antenna" from the "transmission line" to
make it easier to see what's happening. If you're dealing with an air-dielectric folded dipole, the transmission line stub is nearly a quarter wavelength long. So at resonance, its impedance is high and it doesn't have much effect on the feedpoint impedance. As you lower the frequency or shorten the antenna, the resistance of the antenna (as opposed to the transmission line) drops fairly slowly, and the reactance becomes negative relatively quickly. This is in parallel with the transmission line, whose reactance becomes more positive as the line gets electrically shorter. If you look at the net result of this parallel combination, you get a feedpoint impedance that has a rising resistance as frequency drops or the antenna shortens, and a reactance that gets more negative. At some frequency below resonance, the increasing positive reactance of the transmission line equals the negative reactance of the antenna, creating a parallel resonant (sometimes called anti-resonant) circuit. Just before this happens, the resistance skyrockets and the feedpoint reactance heads positive. Exactly at parallel resonance, the reactance is zero (by definition of resonance) and the resistance is very high. And just below that frequency, the reactance heads rapidly to a high positive value, then begins decreasing as the frequency drops below that. The frequency or length where you hit anti-resonance depends on the impedance of the transmission line. I fished up a model of a 17.56 foot high folded monopole with #12 conductors spaced 6 inches apart which I had lying around. It's resonant at about 13.25 MHz., where its feedpoint impedance is 143 ohms. It hits anti-resonance at about 8.5 MHz, where its feedpoint resistance is about 15k ohms. Below that, the feedpoint reactance is positive, and decreases as the frequency is lowered. If you want to model a folded monopole as a separate unfolded monopole and transmission line (which is a way to model one made from twinlead, since you can separately adjust the transmission line length to account for the reduced velocity factor of the transmission line mode), here's what you have to do. First, make the unfolded monopole from two wires, connected in parallel at the bottom and top, or from a single wire of equivalent diameter. Next, choose the impedance of the transmission line to be 1/4 the impedance of the actual line. You have to use a transmission line model for this, not a transmission line made from wires. Make sure it's in parallel, not series, with the source at the base of the monopole. In EZNEC, a transmission line is connected in parallel with a source if they're on the same segment. Finally, multiply the reported feedpoint impedance by four to find the Z of the actual folded monopole. Roy Lewallen, W7EL John wrote: "Roy Lewallen" wrote in message ... John wrote: . . . I thought it was supposed to be backwards from the usual unfolded monopole such that it would go up in resistance and become inductive.?. Why would it do that? Roy Lewallen, W7EL Well, you said earlier that the folded monopole could be modeled as an unfolded monopole with a shorted transmission line in parallel. I thought I understood. When I modeled the unfolded monopole, I saw it do as usual when the element was varied in length. But when I included the shorted section of transmission line and varied it directly with the element, I thought I saw the terminal reactance go inductive as the length was decreased below 1/4-wave resonance and I thought the terminal resistance went up. So, I was expecting the same from EZNEC by modeling the folded version. I guess I'm really lost here. John |
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