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#1
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Ron wrote:
Can someone explain how a transmission line starts radiating as the separation between the center conductor and ground plane becomes greater and greater. Assume you out start with a wire over an infinite copper ground plane that forms a 50 ohm Zo transmission line. Then increase the distance between the wire and the ground plane until the wire becomes an end fed antenna. What happens to cause radiation to begin? Electrons shed excess energy by emitting photons. If those photons are absorbed by electrons, they don't radiate. If they are not absorbed, they radiate (at the speed of light). This is one area where quantum electrodynamics is actually easier to understand, from a conceptual standpoint, than Maxwell's equations. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#2
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A slightly different way of looking at it from what Gary wrote...but
quite similar. It's better to think of a two-wire transmission line, probably. If you want to think of the ground plane, just realize that it's identical to the situation with two conductors driven out of phase: you can insert the ground plane without any effect on the fields at all. Then each wire does radiate, but to the extent that their currents are coincident in space and in opposite directions, those radiations cancel. Net field at any point in space is the linear combination of all the fields arriving at that point, at that instant in time. As the wires become more separated, the radiations observed at a distance no longer cancel. You're not the same distance from each wire, and more importantly, the phase you see differs. Consider what you see if the wires are separated by half a wavelength, and you are in the plane the wires are in...and what you see if you are in a plane perpendicular to the plane the wires are in and passing between them. If you observe the fields close to one of the wires, of course the cancellation is not good there, either, though that's energy propagating in the direction of the line. Note that there's no radiation from coaxial line, so long as the net currents in the inner and outer are exactly out of phase and the current distribution is uniform around the outer conductor (assuming the conductors are exactly coaxial), even if the outer conductor is not very thick. I'll (once again) recommend the "Antennas" chapter of King, Mimno and Wing, "Transmission Lines, Antennas and Waveguides." You'll find it in the antennas chapter rather than the transmission lines chapter because it's radiation rather than energy propagation along the line, I suppose. The introductory material in that chapter bears on this topic, and later in the chapter there's very specific mention of radiation from transmission lines, including what seem some non-intuitive results about amount of radiation versus line length. Cheers, Tom Ron wrote in message .com... Can someone explain how a transmission line starts radiating as the separation between the center conductor and ground plane becomes greater and greater. Assume you out start with a wire over an infinite copper ground plane that forms a 50 ohm Zo transmission line. Then increase the distance between the wire and the ground plane until the wire becomes an end fed antenna. What happens to cause radiation to begin? Ron |
#3
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According to Kraus' "Antennas" 92nd edition, chapter 2)....
An electric charge traveling at a uniform radiation along a straight wire does not radiate. When the charge reaches the end of a wire and reverse direction, it undergoes acceleration (and deceleration) and radiates. AN electric charge moving at uniform velocity along a curved or bent wire is 'accelerated' and radiates. An electric charge moving back and forth in simple harmonic motion (that is, sine wave) has periodic acceleration and radiates. If you have two parallel wires, one carrying a positive charge and the other carrying a negative charge, it will not radiate. If the two wires are bent away from each other, the charges radiate. Kraus goes into more detail on all of this. Get yourself a copy of the book or find one at the library. If they do not have one, they can get one on interlibrary loan. -- Jim N8EE to email directly, send to my call sign at arrl dot net "Ron" wrote in message . com... Can someone explain how a transmission line starts radiating as the separation between the center conductor and ground plane becomes greater and greater. Assume you out start with a wire over an infinite copper ground plane that forms a 50 ohm Zo transmission line. Then increase the distance between the wire and the ground plane until the wire becomes an end fed antenna. What happens to cause radiation to begin? Ron |
#4
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JLB wrote:
An electric charge traveling at a uniform radiation along a straight wire does not radiate. Should that be "uniform velocity"? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#5
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oops. You're right. Uniform velocity.
-- Jim N8EE to email directly, send to my call sign at arrl dot net "Cecil Moore" wrote in message ... JLB wrote: An electric charge traveling at a uniform radiation along a straight wire does not radiate. Should that be "uniform velocity"? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#6
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It is misleading to think that a feedline can radiate seperately from an
antenna. When a feedline becomes unbalanced with respect to an antenna it becomes PART of yet another antenna - which radiates. The two TOGETHER form a resulting radiation pattern which is different to either. ---- Reg, G4FGQ |
#7
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Ron Wrote:
"What happens to cause radiation to begin?" Ronold W.P. King wrote in "Transmission Lines, Antennas, and Wave Guides, by King, Mimno, and Wing on page 224: "Any closed loop of wire that is not confined to the near zone (shielded) and that does not carry equal and opposite currents very close together (adjacent and perfectly balanced though opposite) radiates at least a fraction of the power supplied at its terminals." Radiation is a phenomenon. Energy tries to spread out from where it is to elsewhere. Unless it encounters barriers it just continues to spread. Electromagnetic wave radiation is sustained by perpetual regeneration from mutual stimulation. The electric wave contains all the energy for an instant. The growth and decline of the electric field creates a magnetic field which in turn creates an electric field and so on. These fields can exchange their energies in a vacuum devoid of electrons or electricity. They continue through the vacuum at the speed of light. The waves go so far so fast that much energy escapes the attraction of its source to recall it. Terman says in his 1937 edition on page 700: "A concentric transmission line radiates no energy under ordinary conditions because the outer conductor acts as a substantially perfect shield. The power radiated from a non-resonant two-wire line: Power radiated=160Isqd(pi a/lambda)sqd watts I= line current a/lambda= spacing in wavelengths"" In a resonant line, radiation is increased by about the ratio of peak current to load current. Best regards, Richard Harrison, KB5WZI |
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