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On 5/16/2011 2:55 PM, Cecil Moore wrote:
On May 16, 2:42 pm, John wrote: But I have no need of reflections. The fact that a 200 ohm load appears as a 50 ohm load at the input of a 1/4WL 100 ohm line takes care of all that for me. There's no argument/discussion about that. The question is: Exactly what happens at the 50 ohm Z0-match to reverse the direction and momentum of the reflected wave resulting in no reflections on the 50 ohm line? Hint: it is exactly what happens with non-reflective glass where the 1/4WL thin-film coating cancels the reflections through destructive interference. Why not alleviate ignorance by taking advantage of those well understood facts of EM wave physics from the field of optics? micro.magnet.fsu.edu/primer/java/scienceopticsu/interference/ waveinteractions/index.html -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK By the way, what is the impedance of a constant 100W source looking back into its short piece of internal 50 ohm line? John |
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