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#1
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Cecil,
It seems that you on purpose remove/ignore things that you don't like, but (you know) are true. A CLC pi filter doesn't know the difference between: 1. 100 Ohms lumped circuit load 2. RC = +0.33333 (for 50 Ohms reference) 3. VSWR = 3 (voltage minimum, for a 300 Ohms reference) It seems you don't want to notice that. That it is convenient to use transmission line theory to calculate the load as seen by a PA when transmission line sections are involved, is OK, I didn't deny that. That lumped circuit theory has limitations is fully understood. Frequently transmission line effects are modelled using parasitic L and C additions yielding accurate models valid up to GHz frequencies (depending on the size of the component). We are below 30 MHz (for this topic). Here the experience of the Engineer comes into play: when you can use a lumped circuit model and when you need to use transmission line models (the particle/wave issue is similar)? A helical inductor of an antenna no longer small w.r.t. wavelength may be better modelled with transmission line theory, but that is OT. Even the L of the CLC filter, you can model with a lumped circuit equivalent with more than sufficient accuracy. This is daily business for manufacturers of inductive components. Generally, converting results from transmission line models to impedance in combination with lumped circuit theory to calculate the load as seen by the active device, is daily practice. Especially here, as we are dealing with narrow band signals and don't have to model the behavior for harmonics. But for some reason you don't want to see that, and you elevate transmission line theory to a goal. So again, once you did the conversion to Z, you no longer have to worry about transmission line issues in the load or cabling (including reflection coefficient) when treating your PA's CLC pi filter. Now speed of light becomes important in a CLC pi filter for a HF PA, when becomes "Gaussian" of importance (and may lose all the readers of this topic)? With kind regards, Wim PA3DJS www.tetech.nl |
#2
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On May 16, 2:58*pm, Wimpie wrote:
A CLC pi filter doesn't know the difference between: 1. 100 Ohms lumped circuit load 2. RC = +0.33333 (for 50 Ohms reference) 3. VSWR = 3 (voltage minimum, for a 300 Ohms reference) It seems you don't want to notice that. It is not worth wasting my time to notice since *everyone* already knows that a CLC pi filter is not alive and doesn't have a brain so it must necessarily be dumb as a dead stump. You, OTOH, hopefully being smarter than the average CLC pi filter, should know that the conditions existing within a resistor are different from the conditions existing within an antenna with the same feedpoint impedance. Hint: If you don't know what is in the box, alleviate your ignorance by looking inside the box. If you put on the blinders and refuse to look, then you will make errors like you did earlier while measuring an s11 of zero when it was actually 0.3333. Even the L of the CLC filter, you can model with a lumped circuit equivalent with more than sufficient accuracy. When the task is to determine the exact delay through the inductor, how the heck can the lumped circuit model tell you that? -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK |
#3
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On May 16, 3:29*pm, Cecil Moore wrote:
When the task is to determine the exact delay through the inductor, how the heck can the lumped circuit model tell you that? Wim, I forgot to note that using your stated methods, W8JI "measured" a 3ns delay through a 10" long, 2" diameter, 100 turn, 100uh, 80m mobile loading coil. Doesn't a 4 MHz RF wave traveling the length of a large 100uH air-core 80m loading coil in 3 ns give you some pause for reconsidering your methods? Every wonder why computer manufacturers don't install 100uh coils in series with their computer bus lines to speed up their computers? :-) -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK |
#4
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On 16 mayo, 22:55, Cecil Moore wrote:
On May 16, 3:29*pm, Cecil Moore wrote: When the task is to determine the exact delay through the inductor, how the heck can the lumped circuit model tell you that? Wim, I forgot to note that using your stated methods, W8JI "measured" a 3ns delay through a 10" long, 2" diameter, 100 turn, 100uh, 80m mobile loading coil. Doesn't a 4 MHz RF wave traveling the length of a large 100uH air-core 80m loading coil in 3 ns give you some pause for reconsidering your methods? Every wonder why computer manufacturers don't install 100uh coils in series with their computer bus lines to speed up their computers? :-) -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK I am sorry Cecil, but for the current topic, the answer is no. Please stay to the topic, or start a new one. Wim PA3DJS www.tetech.nl |
#5
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On 16 mayo, 22:29, Cecil Moore wrote:
On May 16, 2:58*pm, Wimpie wrote: A CLC pi filter doesn't know the difference between: 1. 100 Ohms lumped circuit load 2. RC = +0.33333 (for 50 Ohms reference) 3. VSWR = 3 (voltage minimum, for a 300 Ohms reference) It seems you don't want to notice that. It is not worth wasting my time to notice since *everyone* already knows that a CLC pi filter is not alive and doesn't have a brain so it must necessarily be dumb as a dead stump. You, OTOH, hopefully being smarter than the average CLC pi filter, should know that the conditions existing within a resistor are different from the conditions existing within an antenna with the same feedpoint impedance. Hint: If you don't know what is in the box, alleviate your ignorance by looking inside the box. If you put on the blinders and refuse to look, then you will make errors like you did earlier while measuring an s11 of zero when it was actually 0.3333. Even the L of the CLC filter, you can model with a lumped circuit equivalent with more than sufficient accuracy. When the task is to determine the exact delay through the inductor, how the heck can the lumped circuit model tell you that? Just via the capacitance to ground (for example a CLC model of an inductor well below the first self resonance frequency). But when looking to a PA, there is often an additional capacitance left and right of the inductor that causes the most of the phase shift. I did some tesla coiling, so I am aware of the various models for single layer inductors. You are further drifting away from the main subject (PA output impedance and what mismatch will do). -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK Wim PA3DJS www.tetech.nl |
#6
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On May 16, 4:55*pm, Wimpie wrote:
You are further drifting away from the main subject Actually, you are further drifting away from basic fundamental EM physics and I am not in the mood to follow you. Since you do not understand the basic fundamentals of EM wave interference, you cannot possibly understand what is going on inside an active source with invading reflected energy. You might as well be arguing that God causes everything because your lack of the understanding of the basic physics of interference causes your concepts to resemble religion more than anything scientific. That's not an ad hominen attack, just an observation based on the technical ignorance of EM wave interference that you have presented here on this newsgroup. Sorry for being so blunt but anyone who chooses to be ignorant, when there is knowledge available, doesn't deserve much respect, IMO. Since you have failed to answer the simplest of questions about passive circuits, exactly what makes you an expert on active circuits? -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK |
#7
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On 17 mayo, 00:37, Cecil Moore wrote:
On May 16, 4:55*pm, Wimpie wrote: You are further drifting away from the main subject Actually, you are further drifting away from basic fundamental EM physics and I am not in the mood to follow you. Since you do not understand the basic fundamentals of EM wave interference, you cannot possibly understand what is going on inside an active source with invading reflected energy. You might as well be arguing that God causes everything because your lack of the understanding of the basic physics of interference causes your concepts to resemble religion more than anything scientific. That's not an ad hominen attack, just an observation based on the technical ignorance of EM wave interference that you have presented here on this newsgroup. Sorry for being so blunt but anyone who chooses to be ignorant, when there is knowledge available, doesn't deserve much respect, IMO. Since you have failed to answer the simplest of questions about passive circuits, exactly what makes you an expert on active circuits? -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK Cecil, For Walt I made an exception, but I normally don't do someone's homework. I also don't spend my time solving non-relevant problems; I have more interesting quests waiting. If you show up with a relevant quest, maybe I am willing to dive into it. I am not calling myself an expert, I just designed some PA's, ranging from kHz to GHz and from mW to kW, some of them with efficiencies to over 95%. Together with antenna design and consultancy it assures me that at the end of each month I have some money left. With kind regards, Wim PA3DJS |
#8
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On May 17, 4:49*am, Wimpie wrote:
If you show up with a relevant quest, maybe I am willing to dive into it. Wim, here is why my questions for you are more than just relevant. It is imperative that someone lecturing us on happenings inside that PA RF volcano be able to understand what is occurring during a passive event involving forward and reflected EM fields and waves occurring at an impedance discontinuity outside of a PA. Two of the physical quantities that must be conserved are energy and momentum. EM RF fields and waves contain both energy and momentum which must be conserved. I have asked you to tell us exactly what laws of physics govern the reversal of the momentum and direction of energy flow at a Z0-match at a passive impedance discontinuity in a transmission line. You have refused to do so and asserted that such is irrelevant. I contend that I could not have asked a more relevant question - thus the reluctance to provide an answer. The answer to the question is contained in my energy analysis article at: http://www.w5dxp.com/energy.htm A passive Z0-match relies on superposition of waves accompanied by interference effects to explain the reversal of reflected wave energy direction and momentum. Walter Maxwell has called the process a "virtual open-circuit" or a "virtual short". In my article, I explain how it is a two-step process involving normal reflections and interference patterns at the impedance discontinuity. It works exactly like non-reflective glass covering a picture with its 1/4WL thin-film coating where two sets of reflected light waves undergo destructive interference toward the viewer and, honoring the conservation of energy and momentum, reverse their direction and momentum and flow in the opposite direction toward the picture. This is a well-understood phenomenon from sophomore physics 201. Why most RF engineers don't understand this simple physical process involving EM wave interference is beyond belief. Here's the Florida State University web page again: micro.magnet.fsu.edu/primer/java/scienceopticsu/interference/ waveinteractions/index.html Set the java application for opposite phase and when the result is zero, scroll down to the bottom of the page to find out what happens to the energy components in the two waves that cancel to zero. Those energy components "are redistributed to regions that permit constructive interference" just as they are at a Z0-match in an RF transmission line where there are only two possible directions for RF energy flow. For every destructive interference event in one direction, there will be an equal magnitude constructive interference event in the opposite direction. At Walt's "virtual short", total destructive interference energy toward the source is redistributed as constructive interference energy back toward the load. I studied this subject in my EE courses at Texas A&M during the 1950's. The textbook was: "Fields and Waves in Modern Radio", by Ramo and Whinnery, (c) 1944, 1953. The subject is covered under "Quarter- Wave Coating for Eliminating Reflections" in the chapter titled: "Propagation and Reflection of Electromagnetic Waves". -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK |
#9
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On 17 mayo, 14:29, Cecil Moore wrote:
On May 17, 4:49*am, Wimpie wrote: If you show up with a relevant quest, maybe I am willing to dive into it. Wim, here is why my questions for you are more than just relevant. It is imperative that someone lecturing us on happenings inside that PA RF volcano be able to understand what is occurring during a passive event involving forward and reflected EM fields and waves occurring at an impedance discontinuity outside of a PA. Two of the physical quantities that must be conserved are energy and momentum. EM RF fields and waves contain both energy and momentum which must be conserved. I have asked you to tell us exactly what laws of physics govern the reversal of the momentum and direction of energy flow at a Z0-match at a passive impedance discontinuity in a transmission line. You have refused to do so and asserted that such is irrelevant. I contend that I could not have asked a more relevant question - thus the reluctance to provide an answer. The answer to the question is contained in my energy analysis article at:http://www.w5dxp.com/energy.htm A passive Z0-match relies on superposition of waves accompanied by interference effects to explain the reversal of reflected wave energy direction and momentum. Walter Maxwell has called the process a "virtual open-circuit" or a "virtual short". In my article, I explain how it is a two-step process involving normal reflections and interference patterns at the impedance discontinuity. It works exactly like non-reflective glass covering a picture with its 1/4WL thin-film coating where two sets of reflected light waves undergo destructive interference toward the viewer and, honoring the conservation of energy and momentum, reverse their direction and momentum and flow in the opposite direction toward the picture. This is a well-understood phenomenon from sophomore physics 201. Why most RF engineers don't understand this simple physical process involving EM wave interference is beyond belief. Here's the Florida State University web page again: micro.magnet.fsu.edu/primer/java/scienceopticsu/interference/ waveinteractions/index.html Set the java application for opposite phase and when the result is zero, scroll down to the bottom of the page to find out what happens to the energy components in the two waves that cancel to zero. Those energy components "are redistributed to regions that permit constructive interference" just as they are at a Z0-match in an RF transmission line where there are only two possible directions for RF energy flow. For every destructive interference event in one direction, there will be an equal magnitude constructive interference event in the opposite direction. At Walt's "virtual short", total destructive interference energy toward the source is redistributed as constructive interference energy back toward the load. I studied this subject in my EE courses at Texas A&M during the 1950's. The textbook was: "Fields and Waves in Modern Radio", by Ramo and Whinnery, (c) 1944, 1953. The subject is covered under "Quarter- Wave Coating for Eliminating Reflections" in the chapter titled: "Propagation and Reflection of Electromagnetic Waves". -- 73, Cecil, w5dxp.com "Halitosis is better than no breath at all.", Don, KE6AJH/SK Hello Cecil, I am familiar with quarter wave (and multi layer) coatings to reduce reflection. I am not waiting for a lecture on (un)bounded wave propagation. If I don't have something present in my mind, I know where to find it. As mentioned earlier, you can convert all the wave phenomena in the coaxial feed line to impedance as seen by the PA. You are unnecessary complicating things, hence loosing more public that may have interest in this topic. Maybe you (and other people) should carry out the experiments I suggested in this thread (looking to forward power, net power and DC input power versus small load mismatch [normally referenced to 50 Ohms] ). With kind regards, Wim PA3DJS www.tetech.nl |
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