Home |
Search |
Today's Posts |
#11
![]() |
|||
|
|||
![]()
On 5/18/2011 5:58 PM, Cecil Moore wrote:
On May 18, 5:42 pm, John wrote: So, we are saying that the load at the line input can be viewed as a lumped circuit. So now we have a transmitter loaded with a lumped circuit for further analysis. It doesn't quite work that well. I gave an earlier example where Wim got the the s11 parameter wrong by an infinite percentage. The s- parameter equations for a lumped circuit vs an impedance discontinuity are nothing alike. Even the IEEE definitions for the two different types of impedances are different. The interference conditions at the impedance discontinuity can be proven to be different than for the lumped circuit replacement. That's all. It's simple. Quoting Einstein again: "Everything should be made as simple as possible, but no simpler." :-) When you switch to the lumped-circuit model, you are agreeing to faster than light signal speeds, NO superposition of signals, zero interference, zero phase shifts through coils, identical current everywhere, etc. How the heck can you assert and prove there is zero interference inside a source when reflected energy is flowing through it? -- 73, Cecil, w5dxp.com So, you're saying that the Smith chart is wrong? |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Transmitter Output Impedance | Antenna | |||
Transmitter Output Impedance | Antenna | |||
Transmitter Output Impedance | Antenna | |||
Transmitter Output Impedance | Antenna | |||
Transmitter Output Impedance | Antenna |