On 6/29/2011 11:04 AM, Cecil Moore wrote:
On Jun 25, 5:25 pm, John wrote:
But, it does. First, it causes the 50 ohms line (looking into the 291.4
ohms line to see a match due to the reflection. Second, the
re-reflection from that discontinuity is half of what maintains the
circulating energy on the line. The other half is the discontinuity of
the non-virtual load.

You are confusing reflection with wave cancellation (destructive
interference). I suggest that you study the separate sections on
reflections vs interference in "Optics", by Hecht. Nowhere does any
optical textbook indicate that superposition and reflection are the
same thing (and they are indeed NOT the same thing).

You always fall back on the optics thing, don't you?