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#1
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I want to construct a 5/8 wave ground plane for 24 MHz.
I am OK with the dimensions, but I can't get a grip on what the impedance at the feedpoint will be. Even the ARRL antenna book hasn't been much help. Can anyone tell me the impedance I can expect to see, also any tips on matching it? Thanks! Larry DiGioia N8KU N8KU at longwire.com |
#2
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For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10 mm. -
Base feedpoint resistance = 110 ohms Base feedpoint reactance = -j386 ohms Base loading coil inductance = 2.6 uH Coil diameter = 25 mm Coil length = 33 mm Number of spaced turns = 13 Wire = 14 awg = 1.64 mm diameter. For other heights, frequencies and coil dimensions download in a few seconds program BOTLOAD for immediate answers. ---- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
#3
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Kraus (2nd edition, p. 375) gives a different answer.
Interpolating from the diagram on p. 375 (assuming length/diameter = 472) it is about 90-j250. Why the difference? -- Jim N8EE to email directly, send to my call sign at arrl dot net "Reg Edwards" wrote in message ... For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10 mm. - Base feedpoint resistance = 110 ohms Base feedpoint reactance = -j386 ohms Base loading coil inductance = 2.6 uH Coil diameter = 25 mm Coil length = 33 mm Number of spaced turns = 13 Wire = 14 awg = 1.64 mm diameter. For other heights, frequencies and coil dimensions download in a few seconds program BOTLOAD for immediate answers. ---- .................................................. ......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... |
#4
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Kraus (2nd edition, p. 375) gives a different answer.
Interpolating from the diagram on p. 375 (assuming length/diameter = 472) it is about 90-j250. Why the difference? ============================== The program takes into account antenna diameter. Does Kraus? And is he on the same band? Is he at the same height above ground? What sort of ground or radial system does he have? Have you interpolated correctly? Have you understood what Kraus is saying? Is the loading coil in the same location? Is the feedpoint at the same place. Are you comparing like with like? Spend more time thinking about it. Is Kraus infallible? Could be he's wrong again. Who's Kraus anyway? ;o) ---- Reg |
#5
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![]() "Reg Edwards" wrote in message ... The program takes into account antenna diameter. Does Kraus? Yes. My post said length/diameter = 472 (One thing I don't like about the way Kraus wrote his book is that he gives the formula for only one part of the feed impedance (R or X) and a diagram for the complex impedance. He then refers you to someones paper somewhere for the 'complete' formula.. I have it around here but it would take 2 days to find it.) And is he on the same band? In the diagram I was interpolating from the dimensions are in wavelengths. Is he at the same height above ground? What sort of ground or radial system does he have? It is an infinite perfect ground plane---ground mounted. (We are talking about a 5/8 wave vertical remember). Have you interpolated correctly? Probably not. Have you understood what Kraus is saying? Yes. Is the loading coil in the same location? No 'loading coil' in the Kraus example. He is discussing the feed point impedance. A loading coil would be either across or in series with the feed point. Is the feedpoint at the same place. Since the original post concerned a 5/8 wave vertical, I assumed it is at the bottom, which is what Kraus is discussing. Are you comparing like with like? Hence my question. Are we? I recall that a 5/8 wave vertical was 'close' to 50 ohms at the feed point and could be 'adjusted' with an inductance across the feed point (with the feedline at a tap perhaps?). That is the whole point is using such a 'magic number' as 5/8 wavelength. If you look at the impedance curves, though, you find that they are quite steep at this point, so a small error in length causes a large error in impedance, and some tuning will be needed. The 5/8 wave is not a 'build it and go' antenna! Spend more time thinking about it. I have, which is why I looked it up. Is Kraus infallible? Could be he's wrong again. =8o Oh no!!! Kraus wrong!? Who's Kraus anyway? ;o) Oh, I don't know. Just some guy that signed my Master's Thesis 16 years ago. ---- Reg -- Jim N8EE to email directly, send to my call sign at arrl dot net |
#6
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![]() On 12-May-2004, "JLB" wrote: Hence my question. Are we? I recall that a 5/8 wave vertical was 'close' to 50 ohms at the feed point and could be 'adjusted' with an inductance across the feed point (with the feedline at a tap perhaps?). That is the whole point is using such a 'magic number' as 5/8 wavelength. The resistive part of the Z of a 5/8 wave will closer to 50 ohms than it will be for a 1/2 wave, but in most cases will be higher than 50. You may be thinking of a vertical close to 3/8 wave which will be 50 -jx. The -jx (capacitance) can be resonated with a +jx in series for a 50 ohm feedpoint. Ken Fowler |
#7
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Partly because you used a conductor diameter about 16.5mm and Reg's
was 10mm. (Don't think I'd want to make a self-supporting element that long and that thin, myself. Maybe 50mm at the base and tapering to 25 or so?) That probably does not account for the whole difference. Did you both use the same sort of "ground plane"? Height above earth has only a slight effect. Cheers, Tom "JLB" wrote in message ... Kraus (2nd edition, p. 375) gives a different answer. Interpolating from the diagram on p. 375 (assuming length/diameter = 472) it is about 90-j250. Why the difference? -- Jim N8EE to email directly, send to my call sign at arrl dot net "Reg Edwards" wrote in message ... For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10 mm. - Base feedpoint resistance = 110 ohms Base feedpoint reactance = -j386 ohms Base loading coil inductance = 2.6 uH Coil diameter = 25 mm Coil length = 33 mm Number of spaced turns = 13 Wire = 14 awg = 1.64 mm diameter. For other heights, frequencies and coil dimensions download in a few seconds program BOTLOAD for immediate answers. ---- .................................................. ......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... |
#8
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JLB wrote:
Hence my question. Are we? I recall that a 5/8 wave vertical was 'close' to 50 ohms at the feed point and could be 'adjusted' with an inductance across the feed point (with the feedline at a tap perhaps?). Tuned to an electrical 3/4 wave...Basically, just tuning out the reactance.. That is the whole point is using such a 'magic number' as 5/8 wavelength. Huh? The point of the 5/8 radiator is pattern and gain related, not feed impedance, or matching. If you look at the impedance curves, though, you find that they are quite steep at this point, so a small error in length causes a large error in impedance, and some tuning will be needed. The 5/8 wave is not a 'build it and go' antenna! It's pretty close to it though. All you have to do is start off with a "best guess" coil and test. If it's resonant low in freq, take turns off. One at a time, if close. If it's high in freq, you need more turns. Not really any more complicated than trimming a dipole for resonance. After building a lot of those, I can guess the number of turns needed in my head and come pretty close. Reg's guess of 13 turns is pretty close if the form is 1-1.5 inch wide. Using my built in guessing machine, I would have quoted appx 15-16-17 turns off the top of my head , if the coil is made of #12 solid wire, and wound on a 7/8 inch pipe former, "I use a piece of 7/8 inch copper tube as the former" and then taken off the form. "On those type of coils, I make them self supporting. The #12 wire is stiff enough to hold it's shape. Just connect and clamp each end of the coil to hold it in place. MK -- http://web.wt.net/~nm5k |
#9
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Larry D wrote:
Can anyone tell me the impedance I can expect to see, also any tips on matching it? Thanks! The VERT1 vertical that comes with EZNEC is 1/4WL on 40m. It will be 5/8WL on 17m. (7.2 * 2.5 = 18) EZNEC sez the feedpoint impedance on 17m will be about 100-j470 ohms. A loading coil is usually installed between the base of the antenna and the radial system. The coax braid is tied to the radial system and the coax center wire is tapped down on the coil at the 50 ohm point. Rad| coil Gnd-------+-////////---------------5/8WL---------------- Rad| ^ | XMTR-----------+ If you don't mind a relatively low SWR of 2:1-3:1, use good coax, a standard base-loading coil, and your tuner at the transmitter. There is plenty of 5/8WL information for 2m antennas in the ARRL publications and antennas are scalable. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#10
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There is plenty of 5/8WL information for 2m antennas
in the ARRL publications and antennas are scalable. -- 73, Cecil =========================== The trouble with scaling (as from 2m down to 160m) is that antenna conductor diameters are forgotten about which can cause appreciable errors. --- Reg, G4FGQ |
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