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Old May 12th 04, 12:17 PM
Larry D
 
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Default 5/8 wave ground plane

I want to construct a 5/8 wave ground plane for 24 MHz.
I am OK with the dimensions, but I can't get a grip on what
the impedance at the feedpoint will be. Even the ARRL
antenna book hasn't been much help.

Can anyone tell me the impedance I can expect to see,
also any tips on matching it? Thanks!

Larry DiGioia N8KU
N8KU at longwire.com
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Old May 12th 04, 02:07 PM
Reg Edwards
 
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For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10 mm. -

Base feedpoint resistance = 110 ohms
Base feedpoint reactance = -j386 ohms
Base loading coil inductance = 2.6 uH
Coil diameter = 25 mm
Coil length = 33 mm
Number of spaced turns = 13
Wire = 14 awg = 1.64 mm diameter.

For other heights, frequencies and coil dimensions download in a few seconds
program BOTLOAD for immediate answers.
----
.................................................. ..........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. ..........


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Old May 12th 04, 03:53 PM
JLB
 
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Kraus (2nd edition, p. 375) gives a different answer.

Interpolating from the diagram on p. 375 (assuming length/diameter = 472) it
is about 90-j250.

Why the difference?

--
Jim
N8EE

to email directly, send to my call sign at arrl dot net
"Reg Edwards" wrote in message
...
For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10

mm. -

Base feedpoint resistance = 110 ohms
Base feedpoint reactance = -j386 ohms
Base loading coil inductance = 2.6 uH
Coil diameter = 25 mm
Coil length = 33 mm
Number of spaced turns = 13
Wire = 14 awg = 1.64 mm diameter.

For other heights, frequencies and coil dimensions download in a few

seconds
program BOTLOAD for immediate answers.
----
.................................................. .........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. .........





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Old May 12th 04, 05:44 PM
Reg Edwards
 
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Kraus (2nd edition, p. 375) gives a different answer.

Interpolating from the diagram on p. 375 (assuming length/diameter = 472)

it
is about 90-j250.

Why the difference?

==============================

The program takes into account antenna diameter. Does Kraus? And is he on
the same band? Is he at the same height above ground? What sort of ground
or radial system does he have? Have you interpolated correctly? Have you
understood what Kraus is saying? Is the loading coil in the same location?
Is the feedpoint at the same place. Are you comparing like with like?
Spend more time thinking about it.

Is Kraus infallible? Could be he's wrong again.

Who's Kraus anyway? ;o)
----
Reg


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Old May 12th 04, 08:36 PM
JLB
 
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Default



"Reg Edwards" wrote in message
...
The program takes into account antenna diameter. Does Kraus?


Yes. My post said length/diameter = 472 (One thing I don't like about the
way Kraus wrote his book is that he gives the formula for only one part of
the feed impedance (R or X) and a diagram for the complex impedance. He
then refers you to someones paper somewhere for the 'complete' formula.. I
have it around here but it would take 2 days to find it.)


And is he on the same band?


In the diagram I was interpolating from the dimensions are in wavelengths.

Is he at the same height above ground? What sort of ground or radial

system does he have?

It is an infinite perfect ground plane---ground mounted. (We are talking
about a 5/8 wave vertical remember).

Have you interpolated correctly?


Probably not.


Have you understood what Kraus is saying?


Yes.

Is the loading coil in the same location?


No 'loading coil' in the Kraus example. He is discussing the feed point
impedance. A loading coil would be either across or in series with the feed
point.

Is the feedpoint at the same place.


Since the original post concerned a 5/8 wave vertical, I assumed it is at
the bottom, which is what Kraus is discussing.

Are you comparing like with like?


Hence my question. Are we? I recall that a 5/8 wave vertical was 'close' to
50 ohms at the feed point and could be 'adjusted' with an inductance across
the feed point (with the feedline at a tap perhaps?). That is the whole
point is using such a 'magic number' as 5/8 wavelength. If you look at the
impedance curves, though, you find that they are quite steep at this point,
so a small error in length causes a large error in impedance, and some
tuning will be needed. The 5/8 wave is not a 'build it and go' antenna!

Spend more time thinking about it.

I have, which is why I looked it up.


Is Kraus infallible? Could be he's wrong again.


=8o Oh no!!! Kraus wrong!?

Who's Kraus anyway? ;o)


Oh, I don't know. Just some guy that signed my Master's Thesis 16 years
ago.


----
Reg



--
Jim
N8EE

to email directly, send to my call sign at arrl dot net





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Old May 13th 04, 10:10 PM
Ken Fowler
 
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On 12-May-2004, "JLB" wrote:

Hence my question. Are we? I recall that a 5/8 wave vertical was 'close' to
50 ohms at the feed point and could be 'adjusted' with an inductance across
the feed point (with the feedline at a tap perhaps?). That is the whole
point is using such a 'magic number' as 5/8 wavelength.


The resistive part of the Z of a 5/8 wave will closer to 50 ohms than it will be for a 1/2 wave, but
in most cases will be higher than 50. You may be thinking of a vertical close to 3/8 wave which
will be 50 -jx. The -jx (capacitance) can be resonated with a +jx in series for a 50 ohm feedpoint.

Ken Fowler
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Old May 12th 04, 09:59 PM
Tom Bruhns
 
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Partly because you used a conductor diameter about 16.5mm and Reg's
was 10mm. (Don't think I'd want to make a self-supporting element
that long and that thin, myself. Maybe 50mm at the base and tapering
to 25 or so?) That probably does not account for the whole
difference. Did you both use the same sort of "ground plane"? Height
above earth has only a slight effect.

Cheers,
Tom


"JLB" wrote in message ...
Kraus (2nd edition, p. 375) gives a different answer.

Interpolating from the diagram on p. 375 (assuming length/diameter = 472) it
is about 90-j250.

Why the difference?

--
Jim
N8EE

to email directly, send to my call sign at arrl dot net
"Reg Edwards" wrote in message
...
For a 5/8-wave vertical above ground at 24 MHz, conductor diameter 10

mm. -

Base feedpoint resistance = 110 ohms
Base feedpoint reactance = -j386 ohms
Base loading coil inductance = 2.6 uH
Coil diameter = 25 mm
Coil length = 33 mm
Number of spaced turns = 13
Wire = 14 awg = 1.64 mm diameter.

For other heights, frequencies and coil dimensions download in a few

seconds
program BOTLOAD for immediate answers.
----
.................................................. .........
Regards from Reg, G4FGQ
For Free Radio Design Software go to
http://www.btinternet.com/~g4fgq.regp
.................................................. .........


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Old May 13th 04, 05:04 AM
Mark Keith
 
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JLB wrote:
Hence my question. Are we? I recall that a 5/8 wave vertical was
'close' to
50 ohms at the feed point and could be 'adjusted' with an inductance
across
the feed point (with the feedline at a tap perhaps?).

Tuned to an electrical 3/4 wave...Basically, just tuning out the
reactance..

That is the whole
point is using such a 'magic number' as 5/8 wavelength.

Huh? The point of the 5/8 radiator is pattern and gain related, not feed
impedance, or matching.

If you look at the
impedance curves, though, you find that they are quite steep at this
point,
so a small error in length causes a large error in impedance, and some
tuning will be needed. The 5/8 wave is not a 'build it and go' antenna!

It's pretty close to it though. All you have to do is start off with a
"best guess" coil and test. If it's resonant low in freq, take turns
off. One at a time, if close. If it's high in freq, you need more
turns. Not really any more complicated than trimming a dipole for
resonance. After building a lot of those, I can guess the number of
turns needed in my head and come pretty close. Reg's guess of 13 turns
is pretty close if the form is 1-1.5 inch wide. Using my built in
guessing machine, I would have quoted appx 15-16-17 turns off the top of
my head , if the coil is made of #12 solid wire, and wound on a 7/8 inch
pipe former, "I use a piece of 7/8 inch copper tube as the former" and
then taken off the form. "On those type of coils, I make them self
supporting. The #12 wire is stiff enough to hold it's shape. Just
connect and clamp each end of the coil to hold it in place. MK

--
http://web.wt.net/~nm5k
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Old May 12th 04, 04:04 PM
Cecil Moore
 
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Default

Larry D wrote:
Can anyone tell me the impedance I can expect to see,
also any tips on matching it? Thanks!


The VERT1 vertical that comes with EZNEC is 1/4WL on 40m.
It will be 5/8WL on 17m. (7.2 * 2.5 = 18) EZNEC sez the
feedpoint impedance on 17m will be about 100-j470 ohms.

A loading coil is usually installed between the base of
the antenna and the radial system. The coax braid is
tied to the radial system and the coax center wire is
tapped down on the coil at the 50 ohm point.

Rad| coil
Gnd-------+-////////---------------5/8WL----------------
Rad| ^
|
XMTR-----------+

If you don't mind a relatively low SWR of 2:1-3:1, use good
coax, a standard base-loading coil, and your tuner at the
transmitter.

There is plenty of 5/8WL information for 2m antennas
in the ARRL publications and antennas are scalable.
--
73, Cecil http://www.qsl.net/w5dxp




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Old May 12th 04, 05:52 PM
Reg Edwards
 
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Default

There is plenty of 5/8WL information for 2m antennas
in the ARRL publications and antennas are scalable.
--
73, Cecil


===========================

The trouble with scaling (as from 2m down to 160m) is that antenna conductor
diameters are forgotten about which can cause appreciable errors.
---
Reg, G4FGQ




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