Home |
Search |
Today's Posts |
|
#1
![]() |
|||
|
|||
![]()
Henry Kolesnik wrote:
You say my question has been answered but I haven't seen the answer, too old, too stupid, whatever but I still would like to understand. So, would you be kind enough to give me a better understanding of the "mechanism" in the transmitter final that can dissipate and transform yet it can't dissipate a reflection because there's some kind of one way device that acts like a checkvalve or diode that reflects. By definition, reflected energy dissipated in the source was never generated in the first place. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#2
![]() |
|||
|
|||
![]() "Cecil Moore" wrote in message ... Henry Kolesnik wrote: You say my question has been answered but I haven't seen the answer, too old, too stupid, whatever but I still would like to understand. So, would you be kind enough to give me a better understanding of the "mechanism" in the transmitter final that can dissipate and transform yet it can't dissipate a reflection because there's some kind of one way device that acts like a checkvalve or diode that reflects. By definition, reflected energy dissipated in the source was never generated in the first place. -- 73, Cecil http://www.qsl.net/w5dxp That's not a very good definition. Would you say that a rock, thrown vertically, never was thrown just because it returned to hit you on the head? Ed wb6wsn |
#3
![]() |
|||
|
|||
![]()
Ed Price wrote:
"Cecil Moore" wrote: By definition, reflected energy dissipated in the source was never generated in the first place. That's not a very good definition. Would you say that a rock, thrown vertically, never was thrown just because it returned to hit you on the head? Nope, I wouldn't. But that seems to be what some people are saying. I objected to that definition about 15 years ago. I was asked to prove otherwise and was unable to do so. The generated power is *defined* as the *net* steady-state output power of the source. That's why many of my examples involve signal generators equipped with a circulator and load, outputting a constant forward voltage in phase with a constant forward current. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#4
![]() |
|||
|
|||
![]() Ed Price wrote: By definition, reflected energy dissipated in the source was never generated in the first place. -- 73, Cecil http://www.qsl.net/w5dxp That's not a very good definition. Would you say that a rock, thrown vertically, never was thrown just because it returned to hit you on the head? Ed wb6wsn Electromagnetic waves can cancel, but rocks can't. Could that maybe make a difference? 73, Jim AC6XG |
#5
![]() |
|||
|
|||
![]()
On Tue, 25 May 2004 16:43:37 -0700, Jim Kelley
wrote: Would you say that a rock, thrown vertically, never was thrown just because it returned to hit you on the head? Ed wb6wsn Electromagnetic waves can cancel, but rocks can't. Could that maybe make a difference? Hi Jim, This is like mistaking electrons and charge displacement. Sound like Ed described two rocks hitting with an inelastic collision which results in power dissipation. 73's Richard Clark, KB7QHC |
#6
![]() |
|||
|
|||
![]()
Jim Kelley wrote:
Electromagnetic waves can cancel, but rocks can't. However, two EM waves have to exist before they can cancel. If they exist, they posses both energy and momentum. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#7
![]() |
|||
|
|||
![]() Cecil Moore wrote: Jim Kelley wrote: Electromagnetic waves can cancel, but rocks can't. However, two EM waves have to exist before they can cancel. And that makes rocks like waves? If they exist, they posses both energy and momentum. Bet ya can't prove it without first transfering it to something. 73, Jim AC6XG |
#8
![]() |
|||
|
|||
![]()
Jim Kelley wrote:
Cecil Moore wrote: However, two EM waves have to exist before they can cancel. And that makes rocks like waves? That makes real waves tangible like real rocks. The wave particles are just smaller. OTOH, "People who live in glass houses shouldn't throw stones." is an intangible. If they exist, they posses both energy and momentum. Bet ya can't prove it without first transfering it to something. _Optics_, by Hecht is good enough for me. "It is possible to compute the resulting (momentum) force via Electromagnetic Theory, whereupon Newton's Second Law suggests that the *wave itself carries momentum*. (all emphasis his, not mine) ... As Maxwell showed, the *radiation pressure* equals the energy density of the EM wave. ... When the surface under illumination is perfectly reflecting, the beam that entered with a velocity of +c will emerge with a velocity of -c. This corresponds to twice the change in momentum that occurs on absorption, ..." It's obvious that the energy in the TV ghosting wave makes a round- trip to the match-point and back to the RCVR. That's obviously a change in the direction of momentum of the reflected wave. It is twice the change in momentum than if it encountered a circulator/ load and was dissipated. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#9
![]() |
|||
|
|||
![]()
Cecil Moore wrote:
Jim Kelley wrote: Cecil Moore wrote: However, two EM waves have to exist before they can cancel. And that makes rocks like waves? That makes real waves tangible like real rocks. The wave particles are just smaller. OTOH, "People who live in glass houses shouldn't throw stones." is an intangible. If they exist, they posses both energy and momentum. Bet ya can't prove it without first transfering it to something. _Optics_, by Hecht is good enough for me. "It is possible to compute the resulting (momentum) force via Electromagnetic Theory, whereupon Newton's Second Law suggests that the *wave itself carries momentum*. (all emphasis his, not mine) ... As Excellent, now try and understand what is intended by _ALL_ of the words in the sentence. Maxwell showed, the *radiation pressure* equals the energy density of the EM wave. ... When the surface under illumination is perfectly reflecting, the beam that entered with a velocity of +c will emerge with a velocity of -c. This corresponds to twice the change in momentum that occurs on absorption, ..." Yes, I'm familiar with the subject. I've been familiar with it for a long time. However it is incorrect to infer that interactions between waves would be the same as interactions between waves and matter! It's obvious that the energy in the TV ghosting wave makes a round- trip to the match-point and back to the RCVR. It's obvious that the signal has taken multiple paths, at least. That's obviously a change in the direction of momentum of the reflected wave. Perhaps. You're describing back scattering, which should exhibit a Compton effect wavelength shift if true. But again, you're describing an interaction with matter. Photons don't interact with each other in the same way they interact with matter. 73, Jim AC6XG |
#10
![]() |
|||
|
|||
![]() Cecil Moore wrote: Jim Kelley wrote: Electromagnetic waves can cancel, but rocks can't. However, two EM waves have to exist before they can cancel. Yes, but what about the rock? :-) If they exist, they posses both energy and momentum. So if I "possess" an American Express card, do I "possess" money? No. I simply "possess" the potential to purchase something with it at a point of sale. 73, Jim AC6XG |
Reply |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Rho = (Zload-Zo*)/(Zload+Zo), for complex Zo | Antenna | |||
Derivation of the Reflection Coefficient? | Antenna | |||
Length of Coax Affecting Incident Power to Meter? | Antenna |