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#1
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"Henry Kolesnik" wrote in message ...
I'm probably not the only one that is getting an adequate fill of facts, opinions and quotes. I have only one request. Does anyone have verifiable and repeatable evidence that a properly tuned pi network final amplifier without a tuner does or does not dissipate power when there are reflections? If they do can they please direct us to the source or give us an easliy understandable write up. If you read Chapter 13, "RF Power Amplifiers and Projects", in the 2004 ARRL Handbook, there are pages and pages of discussion of matching plate or transistor output impedances to 50 ohms output and not once do they ever refer to output networks dissipating or reflecting reflected power. Not once. It's always a matter of simply matching one impedance to another to provide the highest power output consistent with required linearity, while staying within the amplifiying device's ratings. Transmission lines have reflections; output matching networks and tuners don't. The reflections on transmission lines don't make it past the end of the transmission line -- that's where the reflections take place. Beyond the end of the transmission line, the reflections are seen as mere impedances created by standing waves, which are created by reflections, assuming mismatch. Al |
#2
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#3
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Richard said -
True, but only insofar as the tuner is adjusted to offer a conjugate. ================================ Richard, how many more times do I have to tell you? The impedance looking back into the tuner is NOT the conjugate of the impedance looking into the transmission line towards the antenna - not even when the tuner is adjusted for SWR = 1-to-1. You lead people astray. Or did you make the assertion just to irritate yours truly? ---- Reg, G4FGQ |
#4
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On Fri, 28 May 2004 05:37:07 +0000 (UTC), "Reg Edwards"
wrote: Richard said - True, but only insofar as the tuner is adjusted to offer a conjugate. ================================ Richard, how many more times do I have to tell you? One wonders how many more times indeed, must be love. You lead people astray. Jealous? Or did you make the assertion just to irritate yours truly? oooooo! 88's Richard Clark, KB7QHC Seriously, ducky, do you have any numbers, or is this the Brit version of foreplay? |
#5
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Reg Edwards wrote:
Richard said - True, but only insofar as the tuner is adjusted to offer a conjugate. Richard, how many more times do I have to tell you? The impedance looking back into the tuner is NOT the conjugate of the impedance looking into the transmission line towards the antenna - not even when the tuner is adjusted for SWR = 1-to-1. Would you guys please define "conjugate". The following system is matched. Is there a conjugate in there somewhere? To the right of the match point? XMTR---50 ohm feedline---x---1/4WL 75 ohm feedline---112.5 ohm load -- TNX & 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#6
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alhearn wrote:
If you read Chapter 13, "RF Power Amplifiers and Projects", in the 2004 ARRL Handbook, there are pages and pages of discussion of matching plate or transistor output impedances to 50 ohms output and not once do they ever refer to output networks dissipating or reflecting reflected power. Not once. It's always a matter of simply matching one impedance to another Sorry, that isn't correct. Maybe the Handbook doesn't emphasize the point clearly enough, but the design of output networks is specifically *not* about impedance "matching". The objective is to *transform* the impedance of the load at the amplifier's output socket (usually the design value of 50R) into the correct value of load impedance needed by the amplifier device. As Al says, the correct value of load impedance for the amplifying device is the one that will: provide the highest power output consistent with required linearity, while staying within the amplifiying device's ratings. The whole point is to understand that the output network is not trying to match any particular impedance. It's simply giving the amplifying device the load impedance it needs in order to function correctly. Those two objectives are not the same... and understanding the difference is vital for this whole discussion. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
#7
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alhearn wrote:
If you read Chapter 13, "RF Power Amplifiers and Projects", in the 2004 ARRL Handbook, there are pages and pages of discussion of matching plate or transistor output impedances to 50 ohms output and not once do they ever refer to output networks dissipating or reflecting reflected power. However, the 15th edition of the ARRL Antenna Book goes into great detail about how a match point reflects rearward-traveling waves. If you are designing RF Power Amps, you can simulate load conditions with lumped components. If you are trying to figure out what happens on a transmission line (distributed network) you need to take reflections into account. Transmission lines have reflections; output matching networks and tuners don't. The reflections on transmission lines don't make it past the end of the transmission line -- that's where the reflections take place. Beyond the end of the transmission line, the reflections are seen as mere impedances created by standing waves, which are created by reflections, assuming mismatch. Impedances created by standing waves are merely V/I ratios, i.e. virtual impedances. They are the result of standing waves and not the cause of anything. Physical impedance discontinuities are the cause of reflections that cause standing waves. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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