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#1
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On Sun, 06 Jun 2004 23:18:37 -0500, Cecil Moore
wrote: Walter Maxwell wrote: voltage is NOT the forward voltage. If you can't come to realize this is the key to the problem I'm going to have to give up. I'm sorry, Walt, Your belief that V2 is a reflected wave is the root of the misunderstanding. V2 is a re-reflected wave Another way of saying "You are right, Walt, you are wrong." Let's see, you two have passed this SAME thing back and forth 39 times, cannot agree about what each thinks about ONE particular, and each of you insist you know what a third party meant. Well, I'm off to Foggy Bottom (D.C.) again to where they do this kind of thing for a living and call it law. ;-) Let's see if a week improves this chowder. 73's Richard Clark, KB7QHC |
#2
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Richard Clark wrote,
Let's see, you two have passed this SAME thing back and forth 39 times, cannot agree about what each thinks about ONE particular, and each of you insist you know what a third party meant. Well, I'm off to Foggy Bottom (D.C.) again to where they do this kind of thing for a living and call it law. ;-) Let's see if a week improves this chowder. 73's Richard Clark, KB7QHC The triumph of hope over experience. 73, Tom Donaly, KA6RUH |
#3
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#4
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SNIP
Backfin lumps, OM? 73, Dave, N3HE chowder to confirm your observation (makes me glad I abandoned that metaphor for excellent Chesapeake Crab Cakes). SNIP Richard Clark, KB7QHC |
#5
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On Sun, 13 Jun 2004 05:34:16 -0400, "David J Windisch"
wrote: Backfin lumps, OM? chowder to confirm your observation (makes me glad I abandoned that metaphor for excellent Chesapeake Crab Cakes). Hi Dave, Sorry, but that was too terse. I wasn't in D.C. but for a short event. It was not long enough to sample the full gustatorial offerings of the region - if that was the implication. Also managed to run across a bottle of my favorite Rhum St. James. (Should'a brought a bottle of that back to read this thread through its bottom.) 73's Richard Clark, KB7QHC |
#6
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Hi, Richard:
The very best crab cakes are made from backfin lumps. Sorta like "tuna" and "albacore tuna". As for terse-ness, I'm a silent mic. 73, Dave, N3HE "Richard Clark" wrote in message ... On Sun, 13 Jun 2004 05:34:16 -0400, "David J Windisch" wrote: Backfin lumps, OM? chowder to confirm your observation (makes me glad I abandoned that metaphor for excellent Chesapeake Crab Cakes). Hi Dave, Sorry, but that was too terse. I wasn't in D.C. but for a short event. It was not long enough to sample the full gustatorial offerings of the region - if that was the implication. Also managed to run across a bottle of my favorite Rhum St. James. (Should'a brought a bottle of that back to read this thread through its bottom.) 73's Richard Clark, KB7QHC |
#7
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Richard Clark wrote:
On Sun, 06 Jun 2004 23:18:37 -0500, Cecil Moore wrote: I'm sorry, Walt, Your belief that V2 is a reflected wave is the root of the misunderstanding. V2 is a re-reflected wave Another way of saying "You are right, Walt, you are wrong." It's a very minor mistake, Richard, and one easily made. If you have a copy of Dr. Best's QEX article, please feel free to express your take on this discussion. Let's see if I can present superposition in ASCII graphics. rho is the voltage reflection coefficient and tau is the voltage transmission coefficient. Assume VF1 has a phase angle of zero degrees. Phase angles are important in the following but since the system is matched, all phase angles are either at zero degrees or at 180 degrees at the match point. So a sign change is equivalent to a 180 degree phase shift. 100W XMTR---50 ohm line---x---1/2WL 150 ohm line---50 ohm load VF1=70.7V-- VF2=141.4V-- --VR1=0V --VR2=70.7V According to the rules of superposition, the two voltages incident upon 'x', VF1 and VR2, can be considered separately and then added. ---------------------------------------------------------------- Breaking VF1 down into its two superposition components yields: x | VF1=70.7V (100W)--| |-- V1=106.06V (75W) V3=35.35V (25W)--| | VF1 = 70.7V at zero degrees (100W) V1 = VF1(forward-tau) = 70.7(1.5) = 106.06V at zero degrees (75W) V3 = VF1(forward-rho) = 70.7(0.5) = 35.35V at zero degrees (25W) Note that PF1 = 100W = P1 + P3 = 75W + 25W ----------------------------------------------------------------- Breaking VR2 down into its two superposition components yields. x | |-- VR2=70.7V (33.33W) V4=35.35V (25W)--| |-- V2=35.35V (8.33W) | VR2 = 70.7V at 180 degrees (33.33W) V2 = VR2(reverse-rho) = 70.7(-0.5) = 35.35V at zero degrees (8.33W) V4 = VR2(reverse-tau) = 70.7(0.5) = 35.35V at 180 degrees (25W) Note that PR2 = 33.33W = P2 + P4 = 25W + 8.33W ----------------------------------------------------------------- Now, following the rules of superposition: To get the total forward voltage, add V1 + V2 VF2 = V1 + V2 = 106.06V + 35.35V = 141.4V (133.33W) To get the total reflected voltage, add V3 and V4 VR1 = V3 + V4 = 35.35V - 35.35V = zero volts (0W) Note: Dr. Best neglected to mention P3 and P4 in his QEX article. P3+P4 is the interference joules/sec. They are scalar values. All voltages are consistent and all powers are consistent. So, in this matched system, all reflected power is re-reflected: PF2 = 133.33W = P1 + P2 + P3 + P4 = 75W + 8.33W + 25W + 25W PF2 = P1 + P2 + (complete constructive interference) = 133.33W PR1 = P3 + P4 - (complete destructive interference) = zero watts Note that the voltage forward-rho = (150-50)/(150+50) = +0.5 reverse-rho = (50-150)/(50+150) = -0.5 (180 deg phase shift) -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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