I'll make it a little easier for you, Cecil. I' ll give you two ways to
determine Vfwd.

Way 1. Vfwd = sqrt(Power fwd x Zo)

Way 2. Vfwd = Vsource x sqrt[1/(1- rho^2)]

Now plug rho = 0.5 into the expression for Way 2 and see what comes up.

Walt

Cecil, let's take it one step further and include current, forward current, that
is, Ifwd.

Ifwd = Isouce x sqrt[1/(1 - rho^2)]

Now let's see what happens with a souce voltage of 70.71 v at 100 w on a 50-ohm
line. The source current is 1.414 a.

Now find Ifwd x Vfwd and see what comes up.

Walt

Walter Maxwell wrote:
Cecil, let's take it one step further and include current, forward current, that
is, Ifwd.

Ifwd = Isouce x sqrt[1/(1 - rho^2)]

This equation for voltage was wrong. Perhaps, we should resolve that
problem first.

Forward current can be calculated from the square root of (forward
power divided by Z0). So IF2 = SQRT(133.33W/150ohms) = 0.943 amps

Funny thing is that 141.4v*0.943a = 133.33 watts, the known forward
power on the 150 ohm line.
--
73, Cecil http://www.qsl.net/w5dxp



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