Walter Maxwell wrote:
Cecil, let's take it one step further and include current, forward current, that
is, Ifwd.

Ifwd = Isouce x sqrt[1/(1 - rho^2)]

This equation for voltage was wrong. Perhaps, we should resolve that
problem first.

Forward current can be calculated from the square root of (forward
power divided by Z0). So IF2 = SQRT(133.33W/150ohms) = 0.943 amps

Funny thing is that 141.4v*0.943a = 133.33 watts, the known forward
power on the 150 ohm line.
--
73, Cecil http://www.qsl.net/w5dxp



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