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#111
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Richard Clark wrote:
W5DXP wrote: The forward part and re-reflected part from the source are coherent and traveling in the same direction so they cannot be separated for measurement purposes. That separation is unnecessary as it represents a sufficiently fixed value for every moment beyond the first millisecond for usual applications. So what part of the generated signal is actually generated and what part is merely re-reflected energy? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#112
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On Fri, 15 Aug 2003 15:58:08 -0500, W5DXP
wrote: Richard Clark wrote: W5DXP wrote: The forward part and re-reflected part from the source are coherent and traveling in the same direction so they cannot be separated for measurement purposes. That separation is unnecessary as it represents a sufficiently fixed value for every moment beyond the first millisecond for usual applications. So what part of the generated signal is actually generated and what part is merely re-reflected energy? Hi Cecil, Separation is unnecessary after the first millisecond. Impedance from that time on is sufficiently fixed to measure. You can answer your own question from the resultant, but it is of no particular interest in the determination. 73's Richard Clark, KB7QHC |
#113
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Richard Clark wrote:
Separation is unnecessary after the first millisecond. Impedance from that time on is sufficiently fixed to measure. You can answer your own question from the resultant, but it is of no particular interest in the determination. I don't have a question, Richard, I am trying to answer yours. What difference can it make in the SWR if "separation is unnecessary"? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#114
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Tarmo Tammaru wrote:
Try this out. You have an amplifier of unknown source impedance connected through a directional meter to a 1/4 wavelength line that is shorted at the far end. Without knowing about SWR, you know (because you are a ham radio operator) that the amp is driving an infinite impedance, and delivering 0 power. Now if you adjust the amp so the meter reads 100W in both directions, the amp is still delivering 0 power, and 100% of the reflected wave is rereflected. Where did the 100W come from? the amp delivered it during the first 1/2 cycle after it was turned on. It didn't "know" the line was shorted until the first reflection came back. How do you know that the amplifier is not "delivering" 100W of forward power and dissipating 100W of reflected power (as it would with a circulator+load)? How do you prove that the impedance looking back into the amp is zero, infinity, or purely reactive? Doesn't it have everything to do with the arbitrary definition of "delivered" which doesn't necessarily match reality? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#115
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![]() "W5DXP" wrote in message ... How do you know that the amplifier is not "delivering" 100W of forward power and dissipating 100W of reflected power (as it would with a circulator+load)? Aha, I will give you special dispensation. You are allowed to bias the amp for true class B, and measure the DC drain current. No way is the drain current going to be different from the case of a plain open circuit. Power (RF) can not be more than Power (DC) How do you prove that the impedance looking back into the amp is zero, infinity, or purely reactive? Use any RF impedance meter you want. Doesn't it have everything to do with the arbitrary definition of "delivered" which doesn't necessarily match reality? I think the only alternative in un nice; namely that there is no reflection in steady state Tam/WB2TT -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#116
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Richard Clark wrote:
In the scope of Z determination, I am wholly unconcerned with what precedes the first millisecond. Perhaps you should phrase your question along other lines. You theorized uncertainty because of reflections from all directions. You seem now to be "unconcerned" about that uncertainty. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#117
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Tarmo Tammaru wrote:
I think the only alternative in un nice; namely that there is no reflection in steady state There are an infinite number of possibilities between the rails of 100% re-reflection and zero re-reflection. I suspect a PA obeys the rules of the wave reflection model set forth in Ramo & Whinnery. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#118
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On Fri, 15 Aug 2003 21:19:19 -0500, W5DXP
wrote: Richard Clark wrote: In the scope of Z determination, I am wholly unconcerned with what precedes the first millisecond. Perhaps you should phrase your question along other lines. You theorized uncertainty because of reflections from all directions. You seem now to be "unconcerned" about that uncertainty. Hi Cecil, In the first millisecond, yes. Do you have a question about it following that point in time? 73's Richard Clark, KB7QHC |
#119
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Dr. Slick wrote:
Well, this is clearer than what you wrote earlier, as they have included the "on port 1" part, whereas you stated just "incident reflected", which told us nothing. I stated: If ..., PA's will always re-reflect 100% of the incident reflected power. That's obviously reflected power incident upon the PA. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#120
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Ok, I'll try once more.
Look again at what I wrote earlier: No, you won't see a change in the SWR at point 1 as you change the PA impedance. All the fiddling you do with your Smith chart just won't make it happen. Sorry. The SWR, voltage, current, impedance, power, reflection coefficient, waves, or anything else don't change in response to your Smith chart exercises. To which you replied: Absolutely incorrect. Time for you to review your Smith Chart again. Here's an experiment for you to try. On your workbench, measure the characteristic impedance of a cable, or connect it to a source or load and measure the SWR on it. Now go over to your desk, take out your grease pencil, and change the reference impedance of your Smith chart. Go back to the bench, check the SWR and the cable Z0. Has it changed? If the answer is yes, I'll admit having a serious shortcoming in my knowledge of the power of the Smith chart. If *you'll* review the Smith chart again, you'll find that *if* you set the reference impedance to the Z0 of the transmission line you're analyzing, then the SWR, impedances, and so forth that your read from the Smith chart are correct. If you set the reference impedance to some other value, an SWR read from the chart certainly isn't the SWR on the transmission line. Z0 in the equation you quote refers to the characteristic impedance of a transmission line. If you change the impedance of the transmission line, given the same load impedance Zl, you change the SWR, as the equation indicates. (Changing the reflection coefficient changes the SWR on the line.) But changing the reference value on your Smith chart doesn't change the characteristic impedance of the cable. Now let's see what you wrote this time: Dr. Slick wrote: . . . When you change Zo, you change the normalized center of the Smith, and therefore the Ref. Coeff. and SWR, looking into the same load. Yes. When you change the line's Z0, you should change the normalization of the Smith chart. But changing the normalization of the Smith chart doesn't magically change the cable dimensions to give it a correspondingly new Z0. (Or does it? Something I'm missing here?) The Smith Chart is an extremely powerful graphical RF tool, which has become part of the basis for communicating in the RF world, as well as a standard for displaying impedance on most RF measuring devices. You need to read up on this if you want to understand me. Thank you, although I'm not an expert at using the Smith chart, I know my way around the circle. But perhaps more study would reveal the mechanism by which changing the chart reference causes spontaneous redimensioning of the cable. Even when the other person is correct too? I think it IS an ego trip if you can't admit someone has a point, and are too scared to discuss it further for fear of looking weak or exposing a lack of knowledge about something. All right, I was scared to admit that you have a point, that all you have to do to change a line's SWR is to go over to the desk and change your Smith chart. But I've overcome my fear now, and am exposing my ignorance, or weakness as you say, for all to see. I'd like to learn more about the mechanism, though. When you renormalize your Smith chart, is the line's Z0 changed by a spontaneous change in inner conductor diameter, outer conductor diameter, dielectric permittivity, or some combination? Is it some sort of telekinesis, or perhaps something to do with Chi? I never could quite get the hang of Feng Shui, so maybe that's it. I can't find any reference to the phenomenon you're claiming in my engineering texts -- perhaps an occult or New Age bookstore would be more fruitful? From Pozar's Microwave Engineering: Reflection Coefficient = (Zl-Zo)/(Zl+Zo) Where Zl is a purely real load impedance, and Zo is the purely real characteristic impedance reference. When you change Zo, you change the normalized center of the Smith, and therefore the Ref. Coeff. and SWR, looking into the same load. Almost right, but a misplaced "therefore". The reflection coefficient and SWR don't change because you change the Smith chart normalization. They change because you've changed the cable's Z0. If you know how to use a Smith chart correctly, you can then go and renormalize your Smith chart to the new Z0 (as you've said), and from it you can read what the new reflection coefficient and SWR are. Or you can forget the Smith chart altogether and measure them, or calculate them from an equation. But if you normalize your Smith chart to some value other than the cable's Z0, you're no longer reading the transmission line impedances and SWR from it. It sure looks to me like you're confusing reality with what you read from your arbitrarily normalized Smith chart. They're not the same. Just like the reading on an SWR meter isn't the same as the SWR on a transmission line of a different impedance. And actually for exactly the same reason. Hm, maybe that provides even one more way to say it. Set up your source, cable, and SWR meter like you have it in your earlier posting. Replace the 50 ohm SWR meter with a 75 ohm SWR meter. Renormalize your Smith chart for 75 ohms. Presto! The SWR meter reads the same as the Smith chart! But y'know what? YOU DIDN'T CHANGE THE SWR ON THE TRANSMISSION LINE. Put the 50 ohm SWR meter back in just on the load side of the 75 ohm one. It reads just the same as it did before, and it's reading the actual SWR on the 50 ohm line between it and the load. Again, changing the Smith chart's normalization does not change a cable's Z0 or SWR. Feng Shui and voodoo notwithstanding. A Smith chart is simply (not to disparage in any way its ingeniousness or utility) a polar plot of reflection coefficient on a special scale. (The trick is, of course, generating the scale, an exercise in conformal mapping I recall doing in fields class.) Check it out -- measure the length of the vector from the center to any impedance point (with the chart radius equalling one), and the angle from the main axis (zero ohms being the positive direction), and you'll see you have the reflection coefficient. I can't figure out any more ways to say this. I am always interested in learning. I don't use a Smith chart a great deal, but I know Tom Bruhns, a regular poster here, does. I'll gladly defer to him on issues of Smith chart use, and hope he'll feel free to correct me on any errors I've made in the above discussion -- as he has a number of times in the past, and which I've greatly appreciated. Walt Maxwell, an occasional poster, is truly a Smith chart expert, and I'd also welcome any corrections or amplifications he'd care to make. Or any other knowledgeable Smith chart user. Roy Lewallen, W7EL |
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