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#1
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Short antennae - a reprise
If short antennae radiate all the power that is fed to them, then why would
anyone use long antennae, because the first part of such an antenna, the short part, would radiate all the power, and then there'd be nothing left for the extra bit, making up the rest of the long antenna, to do? The answer is, of course, because it is more difficult to feed a short antenna because of its reactance. So, whence does this reactance arise? Simple. It is the power that has NOT been all radiated by the short antenna arriving back at the feed point with an awkward phase relationship with the incident power. What happens to that power that has not ALL been radiated when it arrives back at the feed point? Simple. It passes back into the matching network, which, together with the short bit, form the resonant artefact, where much of it disappears as heat in the matching network before being fed back to the short antenna to start all over again. Now, Stephen Thomas Cole, that well-respected font of all technical knowledge over in uk.radio.amateur is saying that all you Yanks are a bunch of dopes if you do not understand the above, so take it up with him over there. |
#2
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Short antennae - a reprise
In rec.radio.amateur.antenna gareth wrote:
If short antennae radiate all the power that is fed to them, then why would anyone use long antennae, because the first part of such an antenna, the short part, would radiate all the power, and then there'd be nothing left for the extra bit, making up the rest of the long antenna, to do? An antenna radiates as a whole, not as parts. The answer is, of course, because it is more difficult to feed a short antenna because of its reactance. Nope, the reactance is fairly easily canceled. The answer is because the radiation resistance is measured in milliohms and a matching network to match 50 Ohms to milliohms has huge resistive losses. So, whence does this reactance arise? As your base assumtion is nonsense, this is rather irrelevant. Simple. It is the power that has NOT been all radiated by the short antenna arriving back at the feed point with an awkward phase relationship with the incident power. What happens to that power that has not ALL been radiated when it arrives back at the feed point? Simple. It passes back into the matching network, which, together with the short bit, form the resonant artefact, where much of it disappears as heat in the matching network before being fed back to the short antenna to start all over again. Now, Stephen Thomas Cole, that well-respected font of all technical knowledge over in uk.radio.amateur is saying that all you Yanks are a bunch of dopes if you do not understand the above, so take it up with him over there. Babbling nonsense based on yet another false assumption. -- Jim Pennino |
#3
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Short antennae - a reprise
wrote in message
... The answer is because the radiation resistance is measured in milliohms and a matching network to match 50 Ohms to milliohms has huge resistive losses. Afraid you've just shot yourself in the foot, there, Old Chap, because the reason that the apparent radiation resistance is so low is because so little is radiated! |
#4
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Short antennae - a reprise
On 04/11/14 18:57, gareth wrote:
wrote in message ... The answer is because the radiation resistance is measured in milliohms and a matching network to match 50 Ohms to milliohms has huge resistive losses. Afraid you've just shot yourself in the foot, there, Old Chap, because the reason that the apparent radiation resistance is so low is because so little is radiated! I despair, and I don't think I'm alone in doing so. -- ;-) .. 73 de Frank Turner-Smith G3VKI - mine's a pint. .. http://turner-smith.co.uk .. Ubuntu 12.04 Thunderbirds are go. |
#5
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Short antennae - a reprise
gareth wrote:
wrote in message ... The answer is because the radiation resistance is measured in milliohms and a matching network to match 50 Ohms to milliohms has huge resistive losses. Afraid you've just shot yourself in the foot, there, Old Chap, because the reason that the apparent radiation resistance is so low is because so little is radiated! Cart, horse, reversed. And it is not the "apparent radiation resistance " it is the real, calculable, and measurably radiation resistance, you gas bag. -- Jim Pennino |
#6
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Short antennae - a reprise
On 11/4/2014 12:48 PM, gareth wrote:
If short antennae radiate all the power that is fed to them, then why would anyone use long antennae, because the first part of such an antenna, the short part, would radiate all the power, and then there'd be nothing left for the extra bit, making up the rest of the long antenna, to do? The answer is, of course, because it is more difficult to feed a short antenna because of its reactance. So, whence does this reactance arise? Simple. It is the power that has NOT been all radiated by the short antenna arriving back at the feed point with an awkward phase relationship with the incident power. What happens to that power that has not ALL been radiated when it arrives back at the feed point? Simple. It passes back into the matching network, which, together with the short bit, form the resonant artefact, where much of it disappears as heat in the matching network before being fed back to the short antenna to start all over again. Now, Stephen Thomas Cole, that well-respected font of all technical knowledge over in uk.radio.amateur is saying that all you Yanks are a bunch of dopes if you do not understand the above, so take it up with him over there. It is so amazing how a simple post of nonsense will make all the gullible members of this group dance like puppets on a string. -- Rick |
#7
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Short antennae - a reprise
It is so amazing how a simple post of nonsense will make all the gullible members of this group dance like puppets on a string. Rick got him in one ... |
#8
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Short antennae - a reprise
On 04/11/2014 17:48, gareth wrote:
Simple. You should find any of these easy then: http://www.redlinegroup.com/job/rf-a...ampaign=Indeed http://www.technojobs.co.uk/job.phtm...ampaign=indeed http://cobham.taleo.net/careersectio...0&src=JB-10240 http://jobview.monster.co.uk/RF-ANTE...feed_indeed_UK http://www.new-employment.eu/detail....7d03de7b40d615 http://www.jobsite.co.uk/job/das-des...387&tmp l=dis |
#9
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Short antennae - a reprise
wrote in message
... gareth wrote: wrote in message ... The answer is because the radiation resistance is measured in milliohms and a matching network to match 50 Ohms to milliohms has huge resistive losses. Afraid you've just shot yourself in the foot, there, Old Chap, because the reason that the apparent radiation resistance is so low is because so little is radiated! And it is not the "apparent radiation resistance " it is the real, calculable, and measurably radiation resistance, you gas bag. Why do you have this compulsion to shout out insults in the manner of a 5-year-old? There are two major ways in which the power is dissipated. One is radiation, and the other is the i2r losses in the metal. It is easier for us to model things as though they were resistances, even if they were not. (By the same token is the BJT modelled as a combination of resistances, capacitances and current generators) So, the power that is dissipated as radiation is modelled as though it is a resisitance, although it is not a resistance, but a mechanism by which power is dissipated. In terms of the resistance model, that so-called radiation resistance behaves as though it is a resistance in series with the resistance of the wire, and it matters not what current you manage to force into the antenna, as the antenna shortens, and the apparent radiation resistance decreases, the i2r losses start to dominate, and therefore the short antenna is a poor radiator in not radiating all the power fed to it. |
#10
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Short antennae - a reprise
wrote in message
... And it is not the "apparent radiation resistance " it is the real, calculable, and measurably radiation resistance, you gas bag. Lo! And behold! When you calculate it, one of the terms is the ratio between antenna length and wavelength QED |
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