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#21
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On 08/03/15 12:24, Roger Hayter wrote:
I suspect that the sort of precision with which one can measure signal strength. plus very local variations of surface wave intensity due to varying ground conditions, mean that it would be hard to know if the signal level resulted from, say, one, five or fifty percent of the transmitted power. So I suspect your question has never been answered. But somebody must have done the research, somewhere... An opportunity for some collaborative research between local amateurs? No-one wants to run verticals...too difficult.... A 160m vertical aerial feeding a webSDR, located somewhere near the centre of England, would, using surface (redacted) have a fair-to-considerable percentage coverage of the UK Amateur population and be very useful as a test-bed. Sadly, I don't live near Coventry, although I've been sent there once or twice. The usual webSDRs seem to run on horizontals, unsurprisingly, so not a lot of use for this sort of thing. -- Spike "Hard cases, it has frequently been observed, are apt to introduce bad law". Judge Rolfe |
#22
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On 08/03/15 14:22, Ralph Mowery wrote:
I think that Jeff may be on to something. What you need to do is download one of the antenna modeling programs. Set it up for the antenna type you want. Then you can look at the patten and see the take off angle. The take off angle is what determins the ammount of power you have the differant types of propogation. That's an interesting thought, and one that had crossed my mind. However, modelling is only as good as the modeller, and if things are set up to model only the sky-wave component, I might not get the sort of information I'm looking for. BICBW, as I've no experience of this. However, I've just recalled that while researching the topic some time ago, I came across some polar diagrams for cross-field antenna trials in Egypt, which showed the ground/surface wave components as well as the sky wave, the idea being for the MF broadcast band to maximise the former and minimise that latter. Sadly, I didn't keep the url, but it looks like it might be possible to determine some measure of the relative power/field strengths. I'll see if I can find those diagrams, the model used might have been mentioned. -- Spike "Hard cases, it has frequently been observed, are apt to introduce bad law". Judge Rolfe |
#23
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"Spike" wrote in message
... However, I've just recalled that while researching the topic some time ago, I came across some polar diagrams for cross-field antenna trials in Egypt, Take them with a pinch of salt for the trials were discredited because they were conducted withing the near field of a broadcasting mast, ISTR |
#24
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Spike wrote:
On 08/03/15 09:33, Jeff wrote: Spike wrote I think you are coming at this from the wrong view point. Perhaps the question that you should be asking is what take-off angles are required to produce maximum ground wave, and how do you maximize that for a MF mobile installation. I'm really after figures for the proportions of the RF power fed to that antenna, that finish up in whatever 'they' are called (the use of the well-known word 'waves' seem to upset people despite their having been used for the specifics I mentioned, for about 100 years). Yes, there is wide use of the word "waves", but not as you are using it. To answer your question, all you have to know is the frequency, antenna pattern, the current state of the ionosphere, ground conductivity, terrain roughness and the dielectric constant in the area in question. I'm aware that reconfiguring the set-up might affect these proportions, but I did refer the original query to a typical /M (mobile) set-up of a short rod antenna not connected to ground and operating over average conductivity in the MF/low-HF bands. Well, to start with, you get little to no surface wave propagation above about 3 MHz. For example, does 40% power the sky (redacted), another 40% power the space (redacted), and the other 20% power the surface (redacted)? Clearly, 100% of the RF power goes somewhere, and the various parts of it must add up to 100% - so what are the proportions? Once again, all you have to know is the frequency, antenna pattern, the current state of the ionosphere, ground conductivity, terrain roughness and the dielectric constant in the area in question. If the /M (mobile) set-up was changed to a /P (portable) one with a 5/8 lambda ground-mounted antenna, the sky (redacted) proportion would lower and the surface/space (redacted) would increase - but from what to what? I'm beginning to think that this topic is either so simple or so complex that most Amateurs have either forgotten it or have never heard of it. No, you simply do not understand how propagation works. First read all of this: http://en.wikipedia.org/wiki/Radio_propagation Read the section on Modes very carefully. Follow the links under Modes and read them: http://en.wikipedia.org/wiki/Surface_wave http://en.wikipedia.org/wiki/Skywave http://en.wikipedia.org/wiki/Line-of-sight_propagation http://en.wikipedia.org/wiki/Sporadic_E_propagation http://en.wikipedia.org/wiki/Tropospheric_propagation -- Jim Pennino |
#25
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Roger Hayter wrote:
snip I suspect that the sort of precision with which one can measure signal strength. plus very local variations of surface wave intensity due to varying ground conditions, mean that it would be hard to know if the signal level resulted from, say, one, five or fifty percent of the transmitted power. So I suspect your question has never been answered. An opportunity for some collaborative research between local amateurs? The answer would apply only to one specific antenna at one specfic frequency at one specific location at one specific point in time. The biggest variable in all this is at one point in time. The general approximate answer is: To maximize skywave propagation the antenna main lobe should have an elevation angle of around 20 to 30 degrees and the frequency has to be less than the maximum frequency the ionosphere is currently capable of reflecting. To maximize line of site propagation the antenna main lobe should have an elevation angle as close to zero as possible assuming both ends of the communication are on the Earth. To maximize surface wave propagation the antenna main lobe should have an elevation angle as close to zero as possible and the frequency should be less than 3 MHz. -- Jim Pennino |
#26
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Spike wrote:
On 08/03/15 12:24, Roger Hayter wrote: I suspect that the sort of precision with which one can measure signal strength. plus very local variations of surface wave intensity due to varying ground conditions, mean that it would be hard to know if the signal level resulted from, say, one, five or fifty percent of the transmitted power. So I suspect your question has never been answered. But somebody must have done the research, somewhere... Thoroughly researched for well over 100 years but you refuse to read the research which says your question in the form it is being asked is meaningless. An opportunity for some collaborative research between local amateurs? No-one wants to run verticals...too difficult.... Vertical antennas have little to nothing to do with the essence of your question. -- Jim Pennino |
#27
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Spike wrote:
On 08/03/15 14:22, Ralph Mowery wrote: I think that Jeff may be on to something. What you need to do is download one of the antenna modeling programs. Set it up for the antenna type you want. Then you can look at the patten and see the take off angle. The take off angle is what determins the ammount of power you have the differant types of propogation. That's an interesting thought, and one that had crossed my mind. However, modelling is only as good as the modeller, and if things are set up to model only the sky-wave component, I might not get the sort of information I'm looking for. BICBW, as I've no experience of this. It is obvious you have no experience. Antenna modeling programs DO NOT MODEL PROPAGATION. Antennas have little to no direct relationship to propagation modes other than putting a main lobe where some particular propagation mode may or may not exist at some particular frequency at some particular point in time. -- Jim Pennino |
#28
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On Sunday, March 8, 2015 at 3:40:21 AM UTC-5, Spike wrote:
On 08/03/15 00:17, wrote: True ground wave, which to me, is the same as the surface wave, actually can follow the curvature of the earth, which a space wave cannot do. But true ground or surface waves are generally only taken advantage of on the lower frequencies such as MW, or LW. That's true, which is a shame as useful ground-wave/surface wave can be had on 28 MHz; a maximum range figure for a path over ground of average conductivity might be 25 miles, and considerably more if the path is over water (especially sea-water). That's space wave on 10m. Even seeing a surface wave on 40m is a bit of a stretch from the norm. As I mentioned in my 2nd post, the reason I saw farther than expected from space wave operation on 40m, could well have been due to refraction of the space wave, and due to the fact that the radio horizon is farther than the visual horizon. I used to work local 10m all the time back in the 80's, early 90's.. 25 miles is fairly easy with any decent antenna, at a decent height above ground. I used to work a good bit farther than that fairly often, when using an antenna at 35-45 feet up. The reason I think so, is because the distances I could work with it were a good bit farther than what I would expect with the space wave alone. Maximum surface wave over ground with average conductivity might be 40 to 45 miles on 40m; if you were getting ranges over this, then your ground conductivity might have been enhanced, or due to the height of your ground-plane, you could have experienced refraction of the space wave. If your location was on a hill-top or other high ground, this could have helped the space wave refraction as well. The ground is good here, and the ground plane was full size at 36 ft at the base of the antenna. But it may well have been an enhanced space wave. I was often working well over 100 miles away in such a case. I believe that the availability 24/7/365 of the space-wave and surface-wave is one of Amateur Radio's undervalued assets. On 160m the surface wave might reach over 100 miles, including behind hills and into valleys, which here in the UK would enable a station to reach a significant proportion of the UK Amateur population. Unfortunately, people dismiss verticals in favour of horizontals of one form or another, the usefulness of which drops to zero when the sky wave disappears (apart from any vertically-polarized radiation from a mismatched feeder or unbalanced elements). Well, not everyone does. I know many on 160m who favor verticals. Not only for ground wave, but better DX. The ground wave is pretty good on 160m if using a vertical. Nearly as good as on the MW AM broadcast band, being the two bands are right next door to each other, so to speak. |
#29
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Spike wrote:
On 08/03/15 09:33, Jeff wrote: Spike wrote I think you are coming at this from the wrong view point. Perhaps the question that you should be asking is what take-off angles are required to produce maximum ground wave, and how do you maximize that for a MF mobile installation. I'm really after figures for the proportions of the RF power fed to that antenna, that finish up in whatever 'they' are called (the use of the well-known word 'waves' seem to upset people despite their having been used for the specifics I mentioned, for about 100 years). I'm aware that reconfiguring the set-up might affect these proportions, but I did refer the original query to a typical /M (mobile) set-up of a short rod antenna not connected to ground and operating over average conductivity in the MF/low-HF bands. For example, does 40% power the sky (redacted), another 40% power the space (redacted), and the other 20% power the surface (redacted)? Clearly, 100% of the RF power goes somewhere, and the various parts of it must add up to 100% - so what are the proportions? If the /M (mobile) set-up was changed to a /P (portable) one with a 5/8 lambda ground-mounted antenna, the sky (redacted) proportion would lower and the surface/space (redacted) would increase - but from what to what? I'm beginning to think that this topic is either so simple or so complex that most Amateurs have either forgotten it or have never heard of it. Spike, you're a gormless ****. Seriously, you're giving Gareth Alun Evans G4SDW a run for his money here. -- STC // M0TEY // twitter.com/ukradioamateur |
#30
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On Sun, 08 Mar 2015 10:56:58 +0000, Spike wrote:
I'm really after figures for the proportions of the RF power fed to that antenna, that finish up in whatever 'they' are called (the use of the well-known word 'waves' seem to upset people despite their having been used for the specifics I mentioned, for about 100 years). You're digging a deep hole here, Burt. Perhaps it would be better for you to KYGS? |
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