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On 7/1/2015 4:23 PM, Jerry Stuckle wrote:
On 7/1/2015 12:26 PM, Jeff Liebermann wrote: On Tue, 30 Jun 2015 15:13:55 -0400, Jerry Stuckle wrote: Yes, it's most effective to match the feedline to the antenna at the antenna connection. But it's also important to match the transmitter to the feedline. This latter piece is often ignored because people will use a feedline who's characteristic impedance matches the transmitter already (i.e. 50 ohm line for a 50 ohm transmitter). However, there are exceptions. For instance, if you're feeding a 75 ohm antenna (i.e. a dipole) with 75 ohm coax, a 1:1 balun at the antenna will provide a good match (ideally, 1:1). But there will be a 1.5:1 mismatch to a 50 ohm transmitter. In this case it would be better to have the matching network at the transmitter. We may have had this discussion before. Matching a 75 ohm load to a 50 ohm source might be academically interesting, but the actual loss is almost negligible. for a VSWR of 1.5, the return loss is 14dB and the load mismatch attenuation is 0.177dB. That's about what I would expect to lose in two coax connector pairs. You could also feed the antenna with 50 ohm feedline and place the matching network at the antenna. The effect would still be a 1:1 SWR, but the lower impedance of the coax would create higher i^2R losses; not important if you're talking a short line, but a longer one would lower output at the antenna. True, but for roughly equivalent sizes of coax cables, the 75 ohm cable has less loss and the equivalent 50 ohm cable. If you want to handle high power, use 50 ohms. If you want low loss, use 75 ohms: http://www.belden.com/blog/broadcastav/50-Ohms-The-Forgotten-Impedance.cfm Note that these are for air dielectric cables. Things are not so neat if we consider the dielectric. See the bottom paragraph and graphs: http://www.microwaves101.com/encyclopedias/why-fifty-ohms Dielectric Dielectric const Minimum loss impedance solid PTFE 2.2 50 ohms foam PTFE 1.43 60 air 1.0 75 RG-6/u CATV 75 ohm foam coax still has slightly less loss than the equivalent 50 ohm cable, but not as much as I've previously claimed. This is cute: http://cablesondemandblog.com/wordpress1/2014/03/06/whats-the-difference-between-50-ohm-and-75-ohm-coaxial-cable/ "A good rule of thumb is that if the device being connected via coaxial cable is a receiver of some kind, 75 Ohm Coax is ideal." Jeff, do you always miss the forest for the trees? That was an EXAMPLE. The same would be true if you were feeding a 300 ohm yagi with 300 ohm twinlead and a transmitter with a 10 ohm output impedance. Transmitter output impedance does not determine SWR. And BTW - when calculating, you forgot about the transmitters which cut back power to protect the finals. Many will do so even with a 1.5:1 SWR. |
#2
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On 7/2/2015 6:31 AM, John S wrote:
On 7/1/2015 4:23 PM, Jerry Stuckle wrote: On 7/1/2015 12:26 PM, Jeff Liebermann wrote: On Tue, 30 Jun 2015 15:13:55 -0400, Jerry Stuckle wrote: Yes, it's most effective to match the feedline to the antenna at the antenna connection. But it's also important to match the transmitter to the feedline. This latter piece is often ignored because people will use a feedline who's characteristic impedance matches the transmitter already (i.e. 50 ohm line for a 50 ohm transmitter). However, there are exceptions. For instance, if you're feeding a 75 ohm antenna (i.e. a dipole) with 75 ohm coax, a 1:1 balun at the antenna will provide a good match (ideally, 1:1). But there will be a 1.5:1 mismatch to a 50 ohm transmitter. In this case it would be better to have the matching network at the transmitter. We may have had this discussion before. Matching a 75 ohm load to a 50 ohm source might be academically interesting, but the actual loss is almost negligible. for a VSWR of 1.5, the return loss is 14dB and the load mismatch attenuation is 0.177dB. That's about what I would expect to lose in two coax connector pairs. You could also feed the antenna with 50 ohm feedline and place the matching network at the antenna. The effect would still be a 1:1 SWR, but the lower impedance of the coax would create higher i^2R losses; not important if you're talking a short line, but a longer one would lower output at the antenna. True, but for roughly equivalent sizes of coax cables, the 75 ohm cable has less loss and the equivalent 50 ohm cable. If you want to handle high power, use 50 ohms. If you want low loss, use 75 ohms: http://www.belden.com/blog/broadcastav/50-Ohms-The-Forgotten-Impedance.cfm Note that these are for air dielectric cables. Things are not so neat if we consider the dielectric. See the bottom paragraph and graphs: http://www.microwaves101.com/encyclopedias/why-fifty-ohms Dielectric Dielectric const Minimum loss impedance solid PTFE 2.2 50 ohms foam PTFE 1.43 60 air 1.0 75 RG-6/u CATV 75 ohm foam coax still has slightly less loss than the equivalent 50 ohm cable, but not as much as I've previously claimed. This is cute: http://cablesondemandblog.com/wordpress1/2014/03/06/whats-the-difference-between-50-ohm-and-75-ohm-coaxial-cable/ "A good rule of thumb is that if the device being connected via coaxial cable is a receiver of some kind, 75 Ohm Coax is ideal." Jeff, do you always miss the forest for the trees? That was an EXAMPLE. The same would be true if you were feeding a 300 ohm yagi with 300 ohm twinlead and a transmitter with a 10 ohm output impedance. Transmitter output impedance does not determine SWR. Transmitter output impedance vs. feedline impedance does determine SWR at one end of the system. If you have a mismatch, you will have a non-1:1 SWR. And BTW - when calculating, you forgot about the transmitters which cut back power to protect the finals. Many will do so even with a 1.5:1 SWR. -- ================== Remove the "x" from my email address Jerry, AI0K ================== |
#3
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On 7/2/2015 8:14 AM, Jerry Stuckle wrote:
On 7/2/2015 6:31 AM, John S wrote: On 7/1/2015 4:23 PM, Jerry Stuckle wrote: On 7/1/2015 12:26 PM, Jeff Liebermann wrote: On Tue, 30 Jun 2015 15:13:55 -0400, Jerry Stuckle wrote: Yes, it's most effective to match the feedline to the antenna at the antenna connection. But it's also important to match the transmitter to the feedline. This latter piece is often ignored because people will use a feedline who's characteristic impedance matches the transmitter already (i.e. 50 ohm line for a 50 ohm transmitter). However, there are exceptions. For instance, if you're feeding a 75 ohm antenna (i.e. a dipole) with 75 ohm coax, a 1:1 balun at the antenna will provide a good match (ideally, 1:1). But there will be a 1.5:1 mismatch to a 50 ohm transmitter. In this case it would be better to have the matching network at the transmitter. We may have had this discussion before. Matching a 75 ohm load to a 50 ohm source might be academically interesting, but the actual loss is almost negligible. for a VSWR of 1.5, the return loss is 14dB and the load mismatch attenuation is 0.177dB. That's about what I would expect to lose in two coax connector pairs. You could also feed the antenna with 50 ohm feedline and place the matching network at the antenna. The effect would still be a 1:1 SWR, but the lower impedance of the coax would create higher i^2R losses; not important if you're talking a short line, but a longer one would lower output at the antenna. True, but for roughly equivalent sizes of coax cables, the 75 ohm cable has less loss and the equivalent 50 ohm cable. If you want to handle high power, use 50 ohms. If you want low loss, use 75 ohms: http://www.belden.com/blog/broadcastav/50-Ohms-The-Forgotten-Impedance.cfm Note that these are for air dielectric cables. Things are not so neat if we consider the dielectric. See the bottom paragraph and graphs: http://www.microwaves101.com/encyclopedias/why-fifty-ohms Dielectric Dielectric const Minimum loss impedance solid PTFE 2.2 50 ohms foam PTFE 1.43 60 air 1.0 75 RG-6/u CATV 75 ohm foam coax still has slightly less loss than the equivalent 50 ohm cable, but not as much as I've previously claimed. This is cute: http://cablesondemandblog.com/wordpress1/2014/03/06/whats-the-difference-between-50-ohm-and-75-ohm-coaxial-cable/ "A good rule of thumb is that if the device being connected via coaxial cable is a receiver of some kind, 75 Ohm Coax is ideal." Jeff, do you always miss the forest for the trees? That was an EXAMPLE. The same would be true if you were feeding a 300 ohm yagi with 300 ohm twinlead and a transmitter with a 10 ohm output impedance. Transmitter output impedance does not determine SWR. Transmitter output impedance vs. feedline impedance does determine SWR at one end of the system. If you have a mismatch, you will have a non-1:1 SWR. And BTW - when calculating, you forgot about the transmitters which cut back power to protect the finals. Many will do so even with a 1.5:1 SWR. Not true. Post some links to support your position, please. |
#4
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On 7/2/2015 11:07 AM, John S wrote:
On 7/2/2015 8:14 AM, Jerry Stuckle wrote: On 7/2/2015 6:31 AM, John S wrote: On 7/1/2015 4:23 PM, Jerry Stuckle wrote: On 7/1/2015 12:26 PM, Jeff Liebermann wrote: On Tue, 30 Jun 2015 15:13:55 -0400, Jerry Stuckle wrote: Yes, it's most effective to match the feedline to the antenna at the antenna connection. But it's also important to match the transmitter to the feedline. This latter piece is often ignored because people will use a feedline who's characteristic impedance matches the transmitter already (i.e. 50 ohm line for a 50 ohm transmitter). However, there are exceptions. For instance, if you're feeding a 75 ohm antenna (i.e. a dipole) with 75 ohm coax, a 1:1 balun at the antenna will provide a good match (ideally, 1:1). But there will be a 1.5:1 mismatch to a 50 ohm transmitter. In this case it would be better to have the matching network at the transmitter. We may have had this discussion before. Matching a 75 ohm load to a 50 ohm source might be academically interesting, but the actual loss is almost negligible. for a VSWR of 1.5, the return loss is 14dB and the load mismatch attenuation is 0.177dB. That's about what I would expect to lose in two coax connector pairs. You could also feed the antenna with 50 ohm feedline and place the matching network at the antenna. The effect would still be a 1:1 SWR, but the lower impedance of the coax would create higher i^2R losses; not important if you're talking a short line, but a longer one would lower output at the antenna. True, but for roughly equivalent sizes of coax cables, the 75 ohm cable has less loss and the equivalent 50 ohm cable. If you want to handle high power, use 50 ohms. If you want low loss, use 75 ohms: http://www.belden.com/blog/broadcastav/50-Ohms-The-Forgotten-Impedance.cfm Note that these are for air dielectric cables. Things are not so neat if we consider the dielectric. See the bottom paragraph and graphs: http://www.microwaves101.com/encyclopedias/why-fifty-ohms Dielectric Dielectric const Minimum loss impedance solid PTFE 2.2 50 ohms foam PTFE 1.43 60 air 1.0 75 RG-6/u CATV 75 ohm foam coax still has slightly less loss than the equivalent 50 ohm cable, but not as much as I've previously claimed. This is cute: http://cablesondemandblog.com/wordpress1/2014/03/06/whats-the-difference-between-50-ohm-and-75-ohm-coaxial-cable/ "A good rule of thumb is that if the device being connected via coaxial cable is a receiver of some kind, 75 Ohm Coax is ideal." Jeff, do you always miss the forest for the trees? That was an EXAMPLE. The same would be true if you were feeding a 300 ohm yagi with 300 ohm twinlead and a transmitter with a 10 ohm output impedance. Transmitter output impedance does not determine SWR. Transmitter output impedance vs. feedline impedance does determine SWR at one end of the system. If you have a mismatch, you will have a non-1:1 SWR. And BTW - when calculating, you forgot about the transmitters which cut back power to protect the finals. Many will do so even with a 1.5:1 SWR. Not true. Post some links to support your position, please. Basic physics that anyone with even an inkling of AC theory should understand. Any time you have an impedance mismatch in a system - in this case, whether at the antenna or the transmitter end of a feedline - you will not have perfect power transfer. What is not transferred will be reflected. This causes an SWR greater than 1:1. Try this - connect the output of an HF transmitter to an SWR bridge. Now connect a piece of 75 ohm coax such as RG-59 to the output of the SWR meter, and connect that to a 75 ohm resistive load. Do you think the SWR bridge will show a 1:1 SWR? Not a chance. It will be 1.5:1. -- ================== Remove the "x" from my email address Jerry, AI0K ================== |
#5
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![]() "Jerry Stuckle" wrote in message ... Try this - connect the output of an HF transmitter to an SWR bridge. Now connect a piece of 75 ohm coax such as RG-59 to the output of the SWR meter, and connect that to a 75 ohm resistive load. Do you think the SWR bridge will show a 1:1 SWR? Not a chance. It will be 1.5:1. What you have described is a case of using the wrong swr bridge. You are trying to use a 50 ohm bridge on a 75 ohm system. If a 75 ohm bridge is used it will show a 1:1 SWR. The real SWR is 1:1. With a 75 ohm line and 75 ohm load there is no reflected power. |
#6
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On 7/2/2015 1:56 PM, Ralph Mowery wrote:
"Jerry Stuckle" wrote in message ... Try this - connect the output of an HF transmitter to an SWR bridge. Now connect a piece of 75 ohm coax such as RG-59 to the output of the SWR meter, and connect that to a 75 ohm resistive load. Do you think the SWR bridge will show a 1:1 SWR? Not a chance. It will be 1.5:1. What you have described is a case of using the wrong swr bridge. You are trying to use a 50 ohm bridge on a 75 ohm system. If a 75 ohm bridge is used it will show a 1:1 SWR. The real SWR is 1:1. With a 75 ohm line and 75 ohm load there is no reflected power. My knowledge of antenna systems is limited, but I do know that this is correct, there will be no reflection from the antenna. If the transmitter output is 50 ohms there will be a loss in this matching that will result in less power being delivered to the feed line, but that will not result in reflections in the feed line. I calculate the loss to be -0.177 dB or 4%. How much loss would be expected in the feed line itself if it is a moderate length? -- Rick |
#7
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On 7/2/2015 1:38 PM, rickman wrote:
On 7/2/2015 1:56 PM, Ralph Mowery wrote: "Jerry Stuckle" wrote in message ... Try this - connect the output of an HF transmitter to an SWR bridge. Now connect a piece of 75 ohm coax such as RG-59 to the output of the SWR meter, and connect that to a 75 ohm resistive load. Do you think the SWR bridge will show a 1:1 SWR? Not a chance. It will be 1.5:1. What you have described is a case of using the wrong swr bridge. You are trying to use a 50 ohm bridge on a 75 ohm system. If a 75 ohm bridge is used it will show a 1:1 SWR. The real SWR is 1:1. With a 75 ohm line and 75 ohm load there is no reflected power. My knowledge of antenna systems is limited, but I do know that this is correct, there will be no reflection from the antenna. If there is no reflections from the antenna, how can there be a loss in the source end? There is NO power returned according to your own statement. If the transmitter output is 50 ohms there will be a loss in this matching that will result in less power being delivered to the feed line, but that will not result in reflections in the feed line. Why? What causes the loss? The transmitter output resistance? So that would mean that one can never achieve more that 50% efficiency at the transmitter's OUTPUT! And that would mean that a 1000W transmitter is dissipating 500 watts under the BEST circumstances. Good luck on getting that to work to your satisfaction. |
#8
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On 7/2/2015 1:56 PM, Ralph Mowery wrote:
"Jerry Stuckle" wrote in message ... Try this - connect the output of an HF transmitter to an SWR bridge. Now connect a piece of 75 ohm coax such as RG-59 to the output of the SWR meter, and connect that to a 75 ohm resistive load. Do you think the SWR bridge will show a 1:1 SWR? Not a chance. It will be 1.5:1. What you have described is a case of using the wrong swr bridge. You are trying to use a 50 ohm bridge on a 75 ohm system. If a 75 ohm bridge is used it will show a 1:1 SWR. The real SWR is 1:1. With a 75 ohm line and 75 ohm load there is no reflected power. No, the SWR bridge is correct. The output of the transmitter is 50 ohms. You are correct in that if a 75 ohm bridge is used, the indicated SWR would be 1:1, because everything from that point on is 75 ohms. However, the mismatch (and reflection) occurs on the transmitter side of the bridge, not the antenna side. So the bridge will never see it. But an accurate bridge will show lower power output due to the mismatch. A mismatch is a mismatch, no matter where in the system it occurs. And any mismatch will cause less than 100% power to be transferred. The rest is reflected. Just look at the specs of any amateur transceiver. They show an impedance of 50 ohms. So a load of 50 ohms provides for maximum power transfer; any other impedance causes a mismatch. -- ================== Remove the "x" from my email address Jerry, AI0K ================== |
#9
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![]() "Jerry Stuckle" wrote in message ... On 7/2/2015 1:56 PM, Ralph Mowery wrote: "Jerry Stuckle" wrote in message ... You are correct in that if a 75 ohm bridge is used, the indicated SWR would be 1:1, because everything from that point on is 75 ohms. However, the mismatch (and reflection) occurs on the transmitter side of the bridge, not the antenna side. So the bridge will never see it. But an accurate bridge will show lower power output due to the mismatch. A mismatch is a mismatch, no matter where in the system it occurs. And any mismatch will cause less than 100% power to be transferred. The rest is reflected. Just look at the specs of any amateur transceiver. They show an impedance of 50 ohms. So a load of 50 ohms provides for maximum power transfer; any other impedance causes a mismatch. -- The real impedance of the transmitter is not 50 ohms. It is whatever the device is used in the final stage and the poewr level. For a 100 watt transmitter it is in the thousand ohm range and for solid state devices it is very low. The matching circuit is often fixed to be 50 ohms,but could be made for most any impedance. The older tube circuits were adjustable by the user for a range of somewhat bleow 50 ohms to around 200 ohms. Could be more or less depending on the design. The mismatch you are counting on for a 50 ohm transmitter and a 75 ohm feedline and 75 ohm antenna is in the tuned circuits/matching circuit in the transmitter. Whatever power comes out of the transmitter will make it to the antenna minus the loss of the coax, but not additional loss due to swr. The power comming out of a 50 ohm transmitter will be less due to mismatch, but not because of swr of the antenna system which is 1:1. |
#10
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On Thu, 02 Jul 2015 14:55:53 -0400, Jerry Stuckle
wrote: It's easy enough to demonstrate that you're wrong. 1. Setup your favorite HF xmitter and attach a Tee connector to the antenna connector, your favorite VSWR meter, a length of 50 ohm coax, and a 50 ohm load. 2. Transmit and convince yourself that the VSWR is 1:1. Make sure the transmitter is not into ALC. 3. Now, take another 50 ohm dummy load and connect it to the Tee connector. The transmitter now sees 25 ohms, so the PA stage has half the normal gain. You may need to increase the drive level to obtain the same RF power as before. 4. Measure the VSWR again. It should also be 1:1. Looking back towards the transmitter, the 50 ohm coax cable sees a 2:1 mismatch of 25 ohms (the alleged 50 ohms from radio in parallel with another 50 ohms from the extra dummy load). I know this part works because I've demonstrated it twice to the local non-believers. Now, we go into uncharted territory and do it again with a 75 ohm coax and a 75 ohm dummy load at the far end (antenna end) of the coax. Same procedure. 1. Check the VSWR and it should be 1.5:1. 2. Connect a 50 ohm dummy load to the Tee connector, and measure the VSWR again. It should still be 1.5:1. Looking back towards the transmitter, the 75 ohm coax cable sees the same 2:1 mismatch of 25 ohms. If you want to go further, I think it can be demonstrated that almost any number of extra dummy loads at the Tee connector will still produce the same 1.5:1 VSWR. I'll try it on the bench, but I have other plans for the holiday weekend. If I find time, and manage to get all the junk off my workbench, I'll give try it. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
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