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#1
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**** Post for FREE via your newsreader at post.usenet.com ****
"Richard Harrison" Just how short can a transmission line be and still enforce its Zo? The whole thing is perfectly clear if one imagines applying a step function (rising edge) to any short, even VERY short, length of transmission line. The current in the short line will be equal to V/Zo - at least until the reflections (if any) start arriving back at the input. If the line happen to be terminated with Zo, then no reflections and I=V/Zo is the steady state. The only issue of shortness is that a very short line means very short time until the reflections arrive. The step function makes things a lot easier to understand than RF. It 'enforces' the distinction between the transient period and steady state. -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= *** Usenet.com - The #1 Usenet Newsgroup Service on The Planet! *** http://www.usenet.com Unlimited Download - 19 Seperate Servers - 90,000 groups - Uncensored -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= |
#2
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On Fri, 3 Sep 2004 17:16:48 -0300, "Another Voice" wrote:
**** Post for FREE via your newsreader at post.usenet.com **** "Richard Harrison" Just how short can a transmission line be and still enforce its Zo? The whole thing is perfectly clear if one imagines applying a step function (rising edge) to any short, even VERY short, length of transmission line. The current in the short line will be equal to V/Zo - at least until the reflections (if any) start arriving back at the input. If the line happen to be terminated with Zo, then no reflections and I=V/Zo is the steady state. The only issue of shortness is that a very short line means very short time until the reflections arrive. The step function makes things a lot easier to understand than RF. It 'enforces' the distinction between the transient period and steady state. IMO, the length of the line is irrelevant when using a device such as the Bruene bridge or a Bird 43. Each of those instruments are designed or adjusted to indicate the forward or reflected power, based on three things: 1) ratio of the foward and reflected voltages, the voltage reflection coefficient 2) the scale numbered from 0 to 1, where 0 indicates the reflection is zero, and 1 equals total reflection, but the significant point is that a 3:1 mismatch gives a reflection coefficient of 0.5, which then means that the half-scale reading of 0.5 indicates the 3:1 mismatch, or a 3:1 SWR, and 3) the device is so designed or adjusted so that the voltage ratios indicate the correct value because it's inherent characteristic impedance, Zo, is 50 ohms. Thus, no transmission line is necessary. For example, the device can be connected directly to the antenna terminals, or any other device you desire to determine the mismatch, and power it directly from the signal source--no transmission line is needed on either port for the device to indicate the degree of mismatch. Walt, W2DU |
#3
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![]() "Walter Maxwell" wrote in message ... On Fri, 3 Sep 2004 17:16:48 -0300, "Another Voice" wrote: **** Post for FREE via your newsreader at post.usenet.com **** "Richard Harrison" Just how short can a transmission line be and still enforce its Zo? The whole thing is perfectly clear if one imagines applying a step function (rising edge) to any short, even VERY short, length of transmission line. The current in the short line will be equal to V/Zo - at least until the reflections (if any) start arriving back at the input. If the line happen to be terminated with Zo, then no reflections and I=V/Zo is the steady state. The only issue of shortness is that a very short line means very short time until the reflections arrive. The step function makes things a lot easier to understand than RF. It 'enforces' the distinction between the transient period and steady state. IMO, the length of the line is irrelevant when using a device such as the Bruene bridge or a Bird 43. Each of those instruments are designed or adjusted to indicate the forward or reflected power, based on three things: 1) ratio of the foward and reflected voltages, the voltage reflection coefficient 2) the scale numbered from 0 to 1, where 0 indicates the reflection is zero, and 1 equals total reflection, but the significant point is that a 3:1 mismatch gives a reflection coefficient of 0.5, which then means that the half-scale reading of 0.5 indicates the 3:1 mismatch, or a 3:1 SWR, and 3) the device is so designed or adjusted so that the voltage ratios indicate the correct value because it's inherent characteristic impedance, Zo, is 50 ohms. Thus, no transmission line is necessary. For example, the device can be connected directly to the antenna terminals, or any other device you desire to determine the mismatch, and power it directly from the signal source--no transmission line is needed on either port for the device to indicate the degree of mismatch. Walt, W2DU Walt, I hope people are listening to what you are saying. I built up a Bruene meter in SWCAD using 0% tolerance components and other ideal parts. Works exactly like Bird claims their meter does, except that the error only depends on the PC floating point arithmetic. Transmission line or not makes no difference. BTW, it is kind of neat to see the directional coupler properties, by driving the two sides with different signals, and then being able to separate them. Tam/WB2TT |
#4
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Walter Maxwell wrote:
Thus, no transmission line is necessary. For example, the device can be connected directly to the antenna terminals, or any other device you desire to determine the mismatch, and power it directly from the signal source--no transmission line is needed on either port for the device to indicate the degree of mismatch. Assume a 100+j100 ohm load and a 100-j100 ohm transmitter directly connected with no transmission line. The system is matched. Are there any reflections? Now install a transmission line. Will an SWR meter read the same thing in both cases? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#5
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Cecil Moore wrote:
Walter Maxwell wrote: Thus, no transmission line is necessary. For example, the device can be connected directly to the antenna terminals, or any other device you desire to determine the mismatch, and power it directly from the signal source--no transmission line is needed on either port for the device to indicate the degree of mismatch. Assume a 100+j100 ohm load and a 100-j100 ohm transmitter directly connected with no transmission line. The system is matched. Are there any reflections? Now install a transmission line. Will an SWR meter read the same thing in both cases? What's the Zo of the transmission line? Is it sufficiently long to act as a transmission line? Cecil, methinks you posed an incomplete question :-) |
#6
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On Wed, 08 Sep 2004 02:42:21 GMT, Dave Shrader
wrote: Cecil, methinks you posed an incomplete question :-) WHAT!!? NEVER! Well hardly ever (apologies to G&S). |
#7
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Dave Shrader wrote:
Cecil Moore wrote: Assume a 100+j100 ohm load and a 100-j100 ohm transmitter directly connected with no transmission line. The system is matched. Are there any reflections? Now install a transmission line. Will an SWR meter read the same thing in both cases? What's the Zo of the transmission line? Is it sufficiently long to act as a transmission line? Cecil, methinks you posed an incomplete question :-) Yep, a deliberate act to get you to consider all possibilities. What Z0 did you assume? For what Z0 is your SWR meter calibrated? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#8
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On Wed, 08 Sep 2004 07:17:03 -0500, Cecil Moore
wrote: What Z0 did you assume? He hardly ever says a BIG BIG Z! ...well give three cheers and three cheers more... (further apologies to G&S) |
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