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Old September 3rd 04, 09:16 PM
Another Voice
 
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"Richard Harrison"
Just how short can a transmission line be
and still enforce its Zo?


The whole thing is perfectly clear if one imagines applying a step function
(rising edge) to any short, even VERY short, length of transmission line.
The current in the short line will be equal to V/Zo - at least until the
reflections (if any) start arriving back at the input. If the line happen
to be terminated with Zo, then no reflections and I=V/Zo is the steady
state.

The only issue of shortness is that a very short line means very short time
until the reflections arrive.

The step function makes things a lot easier to understand than RF. It
'enforces' the distinction between the transient period and steady state.




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Old September 3rd 04, 09:46 PM
Walter Maxwell
 
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On Fri, 3 Sep 2004 17:16:48 -0300, "Another Voice" wrote:

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"Richard Harrison"
Just how short can a transmission line be
and still enforce its Zo?


The whole thing is perfectly clear if one imagines applying a step function
(rising edge) to any short, even VERY short, length of transmission line.
The current in the short line will be equal to V/Zo - at least until the
reflections (if any) start arriving back at the input. If the line happen
to be terminated with Zo, then no reflections and I=V/Zo is the steady
state.

The only issue of shortness is that a very short line means very short time
until the reflections arrive.

The step function makes things a lot easier to understand than RF. It
'enforces' the distinction between the transient period and steady state.

IMO, the length of the line is irrelevant when using a device such as the Bruene
bridge or a Bird 43. Each of those instruments are designed or adjusted to
indicate the forward or reflected power, based on three things: 1) ratio of the
foward and reflected voltages, the voltage reflection coefficient 2) the scale
numbered from 0 to 1, where 0 indicates the reflection is zero, and 1 equals
total reflection, but the significant point is that a 3:1 mismatch gives a
reflection coefficient of 0.5, which then means that the half-scale reading of
0.5 indicates the 3:1 mismatch, or a 3:1 SWR, and 3) the device is so designed
or adjusted so that the voltage ratios indicate the correct value because it's
inherent characteristic impedance, Zo, is 50 ohms.

Thus, no transmission line is necessary. For example, the device can be
connected directly to the antenna terminals, or any other device you desire to
determine the mismatch, and power it directly from the signal source--no
transmission line is needed on either port for the device to indicate the degree
of mismatch.

Walt, W2DU
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Old September 4th 04, 09:40 PM
Tam/WB2TT
 
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"Walter Maxwell" wrote in message
...
On Fri, 3 Sep 2004 17:16:48 -0300, "Another Voice"

wrote:

**** Post for FREE via your newsreader at post.usenet.com ****

"Richard Harrison"
Just how short can a transmission line be
and still enforce its Zo?


The whole thing is perfectly clear if one imagines applying a step

function
(rising edge) to any short, even VERY short, length of transmission line.
The current in the short line will be equal to V/Zo - at least until the
reflections (if any) start arriving back at the input. If the line

happen
to be terminated with Zo, then no reflections and I=V/Zo is the steady
state.

The only issue of shortness is that a very short line means very short

time
until the reflections arrive.

The step function makes things a lot easier to understand than RF. It
'enforces' the distinction between the transient period and steady state.

IMO, the length of the line is irrelevant when using a device such as the

Bruene
bridge or a Bird 43. Each of those instruments are designed or adjusted to
indicate the forward or reflected power, based on three things: 1) ratio

of the
foward and reflected voltages, the voltage reflection coefficient 2) the

scale
numbered from 0 to 1, where 0 indicates the reflection is zero, and 1

equals
total reflection, but the significant point is that a 3:1 mismatch gives a
reflection coefficient of 0.5, which then means that the half-scale

reading of
0.5 indicates the 3:1 mismatch, or a 3:1 SWR, and 3) the device is so

designed
or adjusted so that the voltage ratios indicate the correct value because

it's
inherent characteristic impedance, Zo, is 50 ohms.

Thus, no transmission line is necessary. For example, the device can be
connected directly to the antenna terminals, or any other device you

desire to
determine the mismatch, and power it directly from the signal source--no
transmission line is needed on either port for the device to indicate the

degree
of mismatch.

Walt, W2DU


Walt,

I hope people are listening to what you are saying. I built up a Bruene
meter in SWCAD using 0% tolerance components and other ideal parts. Works
exactly like Bird claims their meter does, except that the error only
depends on the PC floating point arithmetic. Transmission line or not makes
no difference. BTW, it is kind of neat to see the directional coupler
properties, by driving the two sides with different signals, and then being
able to separate them.

Tam/WB2TT


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Old September 6th 04, 05:07 PM
Cecil Moore
 
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Walter Maxwell wrote:
Thus, no transmission line is necessary. For example, the device can be
connected directly to the antenna terminals, or any other device you desire to
determine the mismatch, and power it directly from the signal source--no
transmission line is needed on either port for the device to indicate the degree
of mismatch.


Assume a 100+j100 ohm load and a 100-j100 ohm transmitter
directly connected with no transmission line. The system
is matched. Are there any reflections? Now install a
transmission line. Will an SWR meter read the same thing
in both cases?
--
73, Cecil http://www.qsl.net/w5dxp


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Old September 8th 04, 03:42 AM
Dave Shrader
 
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Cecil Moore wrote:

Walter Maxwell wrote:

Thus, no transmission line is necessary. For example, the device can be
connected directly to the antenna terminals, or any other device you
desire to
determine the mismatch, and power it directly from the signal source--no
transmission line is needed on either port for the device to indicate
the degree
of mismatch.



Assume a 100+j100 ohm load and a 100-j100 ohm transmitter
directly connected with no transmission line. The system
is matched. Are there any reflections? Now install a
transmission line. Will an SWR meter read the same thing
in both cases?


What's the Zo of the transmission line? Is it sufficiently long to act
as a transmission line?

Cecil, methinks you posed an incomplete question :-)



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Old September 8th 04, 04:29 AM
Richard Clark
 
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On Wed, 08 Sep 2004 02:42:21 GMT, Dave Shrader
wrote:
Cecil, methinks you posed an incomplete question :-)


WHAT!!? NEVER! Well hardly ever (apologies to G&S).
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Old September 8th 04, 01:17 PM
Cecil Moore
 
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Dave Shrader wrote:

Cecil Moore wrote:
Assume a 100+j100 ohm load and a 100-j100 ohm transmitter
directly connected with no transmission line. The system
is matched. Are there any reflections? Now install a
transmission line. Will an SWR meter read the same thing
in both cases?


What's the Zo of the transmission line? Is it sufficiently long to act
as a transmission line?

Cecil, methinks you posed an incomplete question :-)


Yep, a deliberate act to get you to consider all possibilities.
What Z0 did you assume? For what Z0 is your SWR meter calibrated?
--
73, Cecil http://www.qsl.net/w5dxp


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Old September 8th 04, 04:38 PM
Richard Clark
 
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On Wed, 08 Sep 2004 07:17:03 -0500, Cecil Moore
wrote:
What Z0 did you assume?

He hardly ever says a BIG BIG Z! ...well give three cheers and three
cheers more... (further apologies to G&S)
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