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dBW in S-unit and power strenght
Hi,
A question about dBW and power at receive. Among scales used in power measurement, there is the signal strength or noise level estimation, also known as the "dB below W" (dBW or SDBW). Its relation is dBW = 10 Log P, where P is the power expressed in watt : That means that 100 W is 20 dBW into 50 ohms. But usually, in propagation program (VOACAP, etc), the power strength at receive expressed in dBW is far below such values. I read somewhere the next equivalences : - (minus) 93 ~ S9+10, -103 = S9, -127 = S5, -151 = S1. With -93 dBW for a S9+10 signal at receive, that 'd mean that the power 'd be only P(W) = 10^ (dBW/10) = 0.7 watt ? IMHO this power is much to low... What is wrong in this relations (or in my interpretation) ? Thanks in advance Thierry, ON4SKY http://www.astrosurf.com/lombry |
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