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But to be on the safe side, allow for a dissipation of 1 watt per foot
length of dipole wire which will then get warm in the centre, somewhat above ambient, when in a slight breeze. But the current distribution isn't linear, and the loss is I^2R, so I would think you'd have to know the max current, and work it that way. -- KC6ETE Dave's Engineering Page, www.dvanhorn.org Microcontroller Consultant, specializing in Atmel AVR |
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