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#1
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On Mon, 4 Oct 2004 19:30:19 -0500, "John Smith"
wrote: 400 5.1 + 1.3i Reference Measurement Freq A1 B1 ?1 A2 B2 ?2 400 1 0.79 180 1.08 0.695 177 Hi John, Well, from the two results above, and referencing my copy of Appl. Note 77-3, Page 7, section "Measuring Rho 100 to 1000 MHz," there are a number of issues here. Your B1/A1 is quite off the mark (but certainly correctable, afterall, that is the purpose of its measurement). |Rho| = B2·A1/A2·B1 = 0.695·1/1.08·0.79 = 0.815 Casting the magnitude and angle onto a Smith Chart would suggest your 5.1 + 1.3i Ohms is close enough given your data. The only kicker is port tracking, but I have a hunch that probably is not an issue. This bears further consideration. Too bad Kraus did not choose to elaborate. 73's Richard Clark, KB7QHC |
#2
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![]() "Richard Clark" wrote in message ... On Mon, 4 Oct 2004 19:30:19 -0500, "John Smith" wrote: 400 5.1 + 1.3i Reference Measurement Freq A1 B1 ?1 A2 B2 ?2 400 1 0.79 180 1.08 0.695 177 Hi John, Well, from the two results above, and referencing my copy of Appl. Note 77-3, Page 7, section "Measuring Rho 100 to 1000 MHz," there are a number of issues here. Your B1/A1 is quite off the mark (but certainly correctable, afterall, that is the purpose of its measurement). |Rho| = B2·A1/A2·B1 = 0.695·1/1.08·0.79 = 0.815 Casting the magnitude and angle onto a Smith Chart would suggest your 5.1 + 1.3i Ohms is close enough given your data. The only kicker is port tracking, but I have a hunch that probably is not an issue. This bears further consideration. Too bad Kraus did not choose to elaborate. 73's Richard Clark, KB7QHC I don't understand. Please enumerate the issues. What do you mean B1/A1 is off the mark? If they are off the mark, how can the Z be close enough? Are you saying that I have calculated the Z correctly from the data and you think port tracking is not at fault? What further consideration? You're right. Too bad Kraus didn't tell the feedpoint impedance. I suspect I would not have embarked on this folly if he had. The antenna may have its uses elsewhere, but I don't need the headaches of matching 5 Ohms at 440 MHz. John |
#3
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On Tue, 5 Oct 2004 09:10:19 -0500, "John Smith"
wrote: I don't understand. Please enumerate the issues. What do you mean B1/A1 is off the mark? Hi John, You should get 1.0 @ 180° (the definition of a short). If they are off the mark, how can the Z be close enough? Because what you DID measure, was used as a correction factor per: |Rho| = B2·A1/A2·B1 = 0.695·1/1.08·0.79 = 0.815 (or you skipped that step) Are you saying that I have calculated the Z correctly from the data and you think port tracking is not at fault? Well, that is really your job to confirm or deny. There is very little I can accomplish short of that. What further consideration? I suppose I could visit my Engineering Library. I will be on campus for my Nanotechnology seminar today anyway. 73's Richard Clark, KB7QHC |
#4
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![]() "Richard Clark" wrote in message ... On Tue, 5 Oct 2004 09:10:19 -0500, "John Smith" wrote: I don't understand. Please enumerate the issues. What do you mean B1/A1 is off the mark? Hi John, You should get 1.0 @ 180° (the definition of a short). Well, that's not possible when feeding a length of RG58 at 400 MHz, is it? Remember, I said that there was about a 5 foot length of RG58 between the directional coupler and the load. How can one get 1.0 reflected to the coupler when the load is a short? That requires zero loss coax. If they are off the mark, how can the Z be close enough? Because what you DID measure, was used as a correction factor per: |Rho| = B2·A1/A2·B1 = 0.695·1/1.08·0.79 = 0.815 (or you skipped that step) I did that. As far as I can determine, I did it like the HP application note said to do it. Thanks for your comments. John |
#5
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On Tue, 5 Oct 2004 12:26:06 -0500, "John Smith"
wrote: You should get 1.0 @ 180° (the definition of a short). Well, that's not possible when feeding a length of RG58 at 400 MHz, is it? Remember, I said that there was about a 5 foot length of RG58 between the directional coupler and the load. How can one get 1.0 reflected to the coupler when the load is a short? That requires zero loss coax. Hi John, As Wes suggests, butt up the load against the directional coupler output and eliminate this arbitrary loss of the 5 foot RG58. It should also shift the readings too (you are simply walking around the circle of constant SWR). One question that would be obviated in this process (but I have to ask anyway) is WHERE was this short you applied? At the output port of the coupler, or at the end of this 5 foot RG58? (Same question applies to the calibrated load). The other measurements that you reported in response to Wes indicate you have tracking ports (even if they are off by 4dB). As I said, it seemed unlikely this would be a problem and it confirms the out-of-octave specification. 73's Richard Clark, KB7QHC |
#6
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![]() "Richard Clark" wrote in message news ![]() On Tue, 5 Oct 2004 12:26:06 -0500, "John Smith" wrote: You should get 1.0 @ 180° (the definition of a short). Well, that's not possible when feeding a length of RG58 at 400 MHz, is it? Remember, I said that there was about a 5 foot length of RG58 between the directional coupler and the load. How can one get 1.0 reflected to the coupler when the load is a short? That requires zero loss coax. Hi John, As Wes suggests, butt up the load against the directional coupler output and eliminate this arbitrary loss of the 5 foot RG58. It should also shift the readings too (you are simply walking around the circle of constant SWR). One question that would be obviated in this process (but I have to ask anyway) is WHERE was this short you applied? At the output port of the coupler, or at the end of this 5 foot RG58? (Same question applies to the calibrated load). I used a 66 inch piece of RG58 between the directional coupler and the load. It was at the load end of this piece of coax that I calibrated with a short and made the load measurements. The other measurements that you reported in response to Wes indicate you have tracking ports (even if they are off by 4dB). As I said, it seemed unlikely this would be a problem and it confirms the out-of-octave specification. 73's Richard Clark, KB7QHC |
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