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Thanks for the analogy.
One can mathematically and conceptually conceive two opposite-traveling waves that add up to the observed standing wave, and that's fine. The problem comes with assigning power or energy to the waves. Then you run into the problem of how one wave got the energy over the barrier into the pocket and the other wave took the same amount back out, without transfering any air molecules across the barrier in the process. The average power analysis looks to me something like this. Suppose you have two batteries each with exactly 2 volts potential and zero internal resistance, with a 2 ohm resistor connected between their positive terminals. The negative terminals are connected together. You replace the battery on the left with a short (turning it off), and observe that the current through the resistor is one amp to the left. Then you hook the left hand battery back up and turn the right hand battery "off" by replacing it with a short. You observe that there's one amp now flowing through the resistor to the right. Finally, turn both batteries "on" by putting them both in place. You can use superposition to conclude, correctly, that there's zero current flowing in the resistor. But it's silly to insist that there's a forward two watt "power wave" flowing to the right, and another two watt wave flowing to the left. You subtract one from the other and, sure enough, get zero. But are the "power waves" real? Studying and analyzing these imaginary waves is surely a lot more interesting than simply looking at the circuit and noting that the "boring" (as Cecil calls it) net power is zero. But aren't you studying ghosts? Even more risky is adding the things. This time hook two one volt batteries in series with the 2 ohm resistor and energize one at a time. With the upper one on and the lower one "off" (replaced with a short) you get 1/2 amp. You've got a "power wave" of I^2 * R = 1/2 watt. Turn the lower one on and the upper one "off", and you get another "power wave" of 1/2 watt, in the same direction. Turn them both on, and you have a power flow of, um, 2 watts. Welcome to the new math. Roy Lewallen, W7EL Jack Smith wrote: Roy: Interesting point and I don't recall reading or hearing it elsewhere. The following is dashed off without fully thinking it through, so no warranty on its accuracy. If you think of a sound wave (longitudinal transmission, of course) in a lossless acoustic transmission line terminated with a short, the individual air molecules within each 1/4 wave section are likewise trapped since at the 1/4 wave points there is zero sound pressure. This may be a useful analogy for the electromagnetic transverse propagating T-line. Jack K8ZOA |
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