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Jim Kelley wrote:
Tom Donaly wrote: Next, Cecil, you're going to be talking about a "current gradient" and a "scalar current field." Here's a question for you, Cecil, and Richard Harrison, and Yuri, too: how do you take the gradient of the current at a point on a transmission line, and, if were possible to do so, what is the physical significance of the result? 73, Tom Donaly, KA6RUH The standing wave current profile along, for example, a quarter wave radiator is a cosine function. The gradient then would be the derivative of the cosine function which is a -sine function. 73, ac6xg Jim, current, in a wire, is the total current density integrated across a cross section of the wire. It's a vector, as is the current density. Now tell me, how do you take the gradient of a vector? David K. Cheng, in his book Field and Wave Electromagnetics, defines the gradient operation this way: "We define the vector that represents both the magnitude and the direction of the maximum space rate of increase of a scalar as the gradient of that scalar." He wrote "scalar," not "vector," Jim. You and the rest of the boys are acting as if current had magnitude but no direction, whereas it has both. 73, Tom Donaly, KA6RUH |
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