| Home |
| Search |
| Today's Posts |
|
#29
|
|||
|
|||
|
"Jim Kelley" wrote in message ... H. Adam Stevens, NQ5H wrote: "Jim Kelley" wrote in message ... deletia.... I have a question. If a loading coil only makes a physically short antenna look like it's an electrical quarter wavelength reactively, why does its position along the radiator make such an apparent difference in performance? 73, Jim AC6XG My first reaction is to point out that this was (is?) a question on the Extra exam. I think you may be right. Now how can I explain qualitatively why this is? Start with the answer to the exam question? :-) Consider an end-fed wire antenna. An electromagnetic wave goes through the conduction electrons down to the end and reflects back. At 1/4 wavelength, the reflected wave is exactly in phase with the source so the load looks minimal and resistive, loss plus radiation. As the antenna gets shorter the radiation resistance gets lower and the reflected wave gets back to the feed point sooner (becomes capacitive). We need to add inductance to slow down the wave so it gets back in phase. Is that the controversial phase shift? We cannot, alas, raise the radiation resistance; this is a short antenna. If I place the inductor at the feed point all the current must flow through it, maximizing loss. If I place it at the top little current flows through it, minimizing effectiveness. If I distribute it the antenna's resonance is broader, but at what cost? Lower Q. The signal strength is less. So I make the coil as short as I can, put it in the middle and it's juuust right. 73, H. NQ5H Sounds like you're describing a sort of 'current drop'. Is I^2R loss entirely responsible for this drop? It seems that the phase shift you described earlier would have to cause a change in the standing wave pattern along the radiator. If the loading coil was at the feedpoint, then the maximum current would appear only at the feedpoint. Above the coil, the currents would be out of phase, as you described, because of the shortened radiator, and the maximum available current would not flow along any point on the radiator. Moving the coil higher would allow maximum current to flow along at least the lower portion of the radiator. Loss is certainly a factor, but I can't see how it is the entire explanation for the rather pronounced effect. Hence my question. 73, Jim AC6XG Hi Jim Clearly an entire explanation would require a rigorous solution to Maxwell's equations, but you state it better than I did. The current below the loading coil is as if the antenna were full length, max power radiated; the voltage above the loading coil is as if the antenna were full length. And you're right, moving the coil away from the current max (feed point) reduces I^2R losses in the coil. Are there E^2/R losses in the coil if we mount it at the top? Looks like if we make the boundary conditions at the ends of the antenna as if it were full-length it works best. Remember the boundary conditions; the current is max at the feedpoint and zero at the end (can't go anywhere). The empirical fact is a lumped L in the center of the antenna works best and one can "sort of" intuitively see why placing the coil at either end has problems. Hence I use a 4 foot screwdriver and a 4 foot whip. The antenna at resonance on 40 and 80 is about 20 ohms which I match with a toroidal autoformer. Then 2 feet of coax to the TS480HX. 73, H. NQ5H |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| Lumped Load Models v. Distributed Coils | Antenna | |||
| Current in antenna loading coils controversy | Antenna | |||
| Eznec modeling loading coils? | Antenna | |||