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#1
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![]() "Cecil Moore" wrote in message ... Richard Clark wrote: Rarely do we get any practical correlation from this "sky is falling" oops "current is dropping" argument. Asserting that the argument is about any practical correlation is a diversion of the issue. THE ARGUMENT IS ABOUT THE CURRENT IN A LOADING COIL, not about the radiation pattern. The radiation pattern is completely irrelevant to the argument. One side says the current is absolutely constant except for radiation. The other side says it is not constant (except for special cases). An electrical 1/4WL loaded mobile antenna is not one of the special cases. Sorry, this may sound dumb, I think I must have missed the point. Why are people arguing about current in a loading coil? NEC, and experiment, seem to provide the answer. 73, Frank |
#2
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![]() Sorry, this may sound dumb, I think I must have missed the point. Why are people arguing about current in a loading coil? NEC, and experiment, seem to provide the answer. 73, Frank If you didn't read the stuff on my web page, have a look, the story is there. http://www.k3bu.us/loadingcoils.htm 73 Yuri, K3BU.us |
#3
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Sorry, this may sound dumb, I think I must have missed the point. Why are
people arguing about current in a loading coil? NEC, and experiment, seem to provide the answer. 73, Frank If you didn't read the stuff on my web page, have a look, the story is there. http://www.k3bu.us/loadingcoils.htm 73 Yuri, K3BU.us Thanks for the link Yuri. Read the web page, and now understand what is going on. I have an Excel spreadsheet, complete with graph, prepared from a NEC2 model of an inductively loaded monopole. The graph clearly shows the current distribution across the coil. If you are interested I can e-mail it to you, or can post it on the NG. It is only about 50kB, but not sure if it is acceptable to post attachments on a NG. 73, Frank |
#4
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Knarf wrote:
Thanks for the link Yuri. Read the web page, and now understand what is going on. I have an Excel spreadsheet, complete with graph, prepared from a NEC2 model of an inductively loaded monopole. The graph clearly shows the current distribution across the coil. If you are interested I can e-mail it to you, or can post it on the NG. It is only about 50kB, but not sure if it is acceptable to post attachments on a NG. The netnews rules prohibit posting binary files. If you don't have a web page, you could post it to alt.binary and point to it from here. Modeling a helical loading coil in EZNEC and putting loads at the various segments also clearly illustrates the current taper. All real-world air-core loading coils are distributed networks. In a distributed network with reflections, the standing-wave currents are tapered within a sinusoidal envelope. Here's an unanswered question: If the loading coil occupies zero degrees, how can the remaining eight feet of the antenna occupy the entire 90 electrical degrees? Wouldn't the coil have to change the frequency for that to happen? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#5
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Cecil,
In a simple monopole with one inductor, let L1 be the distance from the base of an antenna to the bottom of the loading coil in meters, L2 the length of the loading coil, L3 the distance from the top of the loading coil to the top of the antenna. I is the base current, L the inductance value and F the frequency. You can assume the antenna is very thin. Since your theory is so elegant and well developed, and you've had such an excellent education at Texas A&M, it shouldn't be difficult at all for you to write a couple of simple equations which give the currents at the two ends of the coil. In the time-honored methods of science, your equations can then be tested against modeled and measured results to prove the validity of your theory. Roy Lewallen, W7EL |
#6
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Roy Lewallen wrote:
Cecil, In a simple monopole with one inductor, let L1 be the distance from the base of an antenna to the bottom of the loading coil in meters, L2 the length of the loading coil, L3 the distance from the top of the loading coil to the top of the antenna. I is the base current, L the inductance value and F the frequency. You can assume the antenna is very thin. Since your theory is so elegant and well developed, and you've had such an excellent education at Texas A&M, it shouldn't be difficult at all for you to write a couple of simple equations which give the currents at the two ends of the coil. In the time-honored methods of science, your equations can then be tested against modeled and measured results to prove the validity of your theory. Sorry, Roy, my theory is not elegant and/or well developed. Equations may be possible in the future, but not right now. At the present time, the theory is qualitative, not quantitative. We are out on the edge of what has been published so far and are in the process of discovery. It is hard for me to believe that this material hasn't been covered some time, somewhere, in a Master's thesis or a PhD dissertation or somewhere in the IEEE proceedings. I regret that I don't have access to such. The coil has an 'L' and a 'C' and thus can be regarded as a short piece of transmission line. For a mental picture, consider two pieces of helix material, side by side, being used as a balanced transmission line. They would certainly possess a high velocity factor as does a bugcatcher coil. Here is the equivalent of 1/2 of a typical loaded dipole using horizontal #16 wire at a height of 24 feet where Z0=138*sqrt(4h/d). Feedpoint---Z0=600 ohms---x---coil---y---Z0=600 ohms--- The Z0 of the coil is presently unknown but I am working on getting a ballpark value for it. In any case since Z0=sqrt(L/C), the Z0 of the loading coil will be very high. That means, in addition to the reflections at the tip of the antenna, there will also be reflections at 'x' and 'y', both ways. That situation is pretty complicated but the result is apparently to put the forward voltage out of phase with the forward current at the feedpoint. It also apparently puts the reflected voltage out of phase with the reflected current at the feedpoint. The only requirement is that Vf+Vr be in phase with If+Ir at the feedpoint. I hope you can appreciate the complexity of that situation, stop asking for a "simple equation", and assist us in the apparently complicated solution. When someone doesn't understand the topic, one asks for a "simple equation" and when none is forthcoming, one rationalizes that the new information is not worth knowing. How about working with me instead of against me on this complicated problem for which neither one of us has the complete answer (yet)? P.S. If you had demanded a "simple equation" from Maxwell, you would have been disappointed also. :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#7
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Cecil Moore wrote:
For a mental picture, consider two pieces of helix material, side by side, being used as a balanced transmission line. They would certainly possess a high velocity factor as does a bugcatcher coil. ^^^^ Sorry, this should have been a *LOW* velocity factor. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#8
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Cecil Moore wrote:
Sorry, Roy, my theory is not elegant and/or well developed. Equations may be possible in the future, but not right now. At the present time, the theory is qualitative, not quantitative. . . Somehow I expected this. Roy Lewallen, W7EL |
#9
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Cecil,
I decided to take a look at the question you asked below, and I came up with a really simple modeling experiment. Set up a simple quarter-wave vertical in EZNEC, resonant at 7 MHz. Run the source and current functions and save the data. Now change the frequency to 3.5 MHz and repeat the source and current functions. Do not scale the antenna or change anything else. I believe most people would now view this antenna as one-eighth wave at the new frequency, or perhaps representative of a whip above a loading coil (at 3.5 MHz). This experiment demonstrates what happens to the "remaining eight feet" when confronted with the conflict between the "need" for 90 degrees and the availability of only 45 degrees. My computer did not blow up, and I suspect yours will survive as well. Any number of permutations can be tried. Change the length instead of the frequency, scale up, scale down, and so on. The current always starts at 1.0, and it always goes to 0.0 at the tip. The reactance and driving voltage can be awesome, but the current remained unfazed (or is that unphased?). This is not a revelation. Antenna books point out that the current in a short antenna decreases in a straight line, not a sine curve, from the feed point to the tip. (E.g. Kraus, 2nd Ed. page 216) Since your traveling wave model seems to be based on a 90 degree requirement, you may want to consider incorporating this additional information before submitting your new model for publication. 73, Gene W4SZ (The "eight feet" is taken from your message. In this experiment the whip length is quite a bit larger, of course. Rescale the entire experiment if you like.) Cecil Moore wrote: Here's an unanswered question: If the loading coil occupies zero degrees, how can the remaining eight feet of the antenna occupy the entire 90 electrical degrees? Wouldn't the coil have to change the frequency for that to happen? |
#10
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Gene Fuller wrote:
Antenna books point out that the current in a short antenna decreases in a straight line, not a sine curve, from the feed point to the tip. (E.g. Kraus, 2nd Ed. page 216) Isn't that simply because the slope of a sine wave near the zero crossing closely approximates that of a straight line? 73, Jim AC6XG |
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