| Home |
| Search |
| Today's Posts |
|
#11
|
|||
|
|||
|
50 watts is entering the line, and 25 watts is exiting. The line loss is
3 dB. Surely you're able to make this calculation yourself. I don't feel a need for a definition of a "power ratio". What you've defined is indeed the ratio of two powers, but it escapes me of what use it is except perhaps to cause confusion. Roy Lewallen, W7EL Cecil Moore wrote: Roy Lewallen wrote: Cecil Moore wrote: Why is it so hard to get a straight answer to this simple question? The answer is simple. 25 watts. That was a given, Roy. The question is: what is the feedline loss in dB? What do you think about Jim's definition of the power ratio being (feedline losses)/(feedline losses + load power)? -- 73, Cecil http://www.qsl.net/w5dxp |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Forum | |||
| Current in antenna loading coils controversy - new measurement | Antenna | |||
| Complex line Z0: A numerical example | Antenna | |||
| A Subtle Detail of Reflection Coefficients (but important to know) | Antenna | |||
| Re-Normalizing the Smith Chart (Changing the SWR into the same load) | Antenna | |||