Dr. Slick wrote:

"Peter O. Brackett" wrote:
There will always reflections at such an impedance
discontinuity where an impedance faces its' conjugate.

I disagree completely. The theoretical impedance of a resonant
series L and C (which is lossless) is zero. So in a conjugate
match, where they cancel out, in an ideal loss-less world, it
would be equivalent to the series C and L not being there at all,
with the source and load 50 ohms free to pass max. power delivered to
the load.

Better be careful. Did you just assert that you can change
the SWR on a feedline by forming a conjugate match at the source?
All Peter is saying is that the VSWR on the feedline will not be 1:1
if Z-complex-load differs from the purely resistive Z0 of a lossless
line. For a lossless line, there is nothing you can do at the source
to change the SWR at the load.

However, if the line is lossless, you can achieve maximum power
transfer anyway even in the face of a high SWR.
--
73, Cecil http://www.qsl.net/w5dxp



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Cecil Moore wrote in message ...

I disagree completely. The theoretical impedance of a resonant
series L and C (which is lossless) is zero. So in a conjugate
match, where they cancel out, in an ideal loss-less world, it
would be equivalent to the series C and L not being there at all,
with the source and load 50 ohms free to pass max. power delivered to
the load.

Better be careful. Did you just assert that you can change
the SWR on a feedline by forming a conjugate match at the source?
All Peter is saying is that the VSWR on the feedline will not be 1:1
if Z-complex-load differs from the purely resistive Z0 of a lossless
line. For a lossless line, there is nothing you can do at the source
to change the SWR at the load.


As usual, your sentences don't make too much sense, which is probably
why you go one with your record-breaking threads.
Maybe you actually agree with people when you argue with them...
well, we could all be accused of that one.

However, if the line is lossless, you can achieve maximum power
transfer anyway even in the face of a high SWR.


If Zo=50-j5 and Zload=50+j5, you will have a conjugate match,
and max power delivered to the load.


Slick