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Corrections:
The *magnitude* of the reflection coefficient for horizontally polarized waves is very close to one. But the angle is 180 degrees. That is, there's a phase reversal when the wave reflects. I was also incorrect in saying that the difference in distances for a 30 degree elevation angle for the half wave high antenna is exactly a wavelength. The distance from the antenna to the reflection point is one wavelength, but the difference in distances the rays travel to a distant point is exactly 1/2 wavelength. This can be seen by drawing a line perpendicular to the direct and reflected rays as I suggested in my earlier posting, and looking at the total distances traveled by both rays from their intersection with it. Combined with the phase reversal, the 1/2 wavelength difference in distances results in complete reinforcement at a distant point. I apologize for the errors. Many thanks to John Farr for reminding me of the phase reversal of the reflection. Roy Lewallen, W7EL Roy Lewallen wrote: . . . For example, if the antenna is a half wavelength high, you'll find that at an elevation angle of 30 degrees, the reflected ray travels exactly one wavelength farther than the direct ray, so the two rays will exactly add in phase. . . . You do also have to include a factor for the reflection coefficient of the reflected ray from the ground. But for horizontally polarized waves at moderate to low angles, it's very close to one. . . . |
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