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#1
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#2
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![]() W5DXP wrote: wrote: There is certainly no power at the zero crossings. There is no NET power at the zero crossings. I think you mean there's no instantaneous power at the zero crossings. 73, ac6xg |
#3
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Jim Kelley wrote:
W5DXP wrote: There is no NET power at the zero crossings. I think you mean there's no instantaneous power at the zero crossings. Well, since the NET voltage is always zero at a voltage node when the forward power and reflected power are equal, the instantaneous voltage is always zero, i.e. the steady-state voltage is always zero. If we have equal power flow vectors in opposite directions, the NET power is zero at all points up and down the line. -- 73, Cecil, W5DXP |
#4
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![]() W5DXP wrote: Jim Kelley wrote: W5DXP wrote: There is no NET power at the zero crossings. I think you mean there's no instantaneous power at the zero crossings. Well, since the NET voltage is always zero at a voltage node when the forward power and reflected power are equal, the instantaneous voltage is always zero, i.e. the steady-state voltage is always zero. I've never actually seen the voltage at a node in a standing wave pattern referred to as an instantaneous voltage - especially considering that it doesn't vary with time. Instantaneous usually means the solution to a function f(t) at time t (not f(x) and position x.) Nodes and zero crossings aren't necessarily the same thing. 73, Jim AC6XG |
#5
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Jim Kelley wrote:
Nodes and zero crossings aren't necessarily the same thing. They are for standing waves on lossless unterminated lines, by definition. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#6
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W5DXP wrote:
Jim Kelley wrote: Nodes and zero crossings aren't necessarily the same thing. They are for standing waves on lossless unterminated lines, by definition. I think not. Standing waves are spatial. At certain points on the line the (NET) voltage is always zero: nodes. At other points on the line, the (NET) voltage is sinusoidal and has 2 zero crossings per cycle. The amplitude of these sinusoids varies spatially along the line resulting in the standing wave. In an ideal line terminated by Zo, no matter where you attach your oscillograph to the line, you will observe a sinusoid of the same amplitude. This sinusoid will have zero crossings and power at the time of these zero crossings will be zero; no energy will be flowing at the time of the zero crossing. And going back to the comment that started this sub-thread, it is this cyclical variation in energy flow which prompted the power dudes to invent three phase lines in which the energy flow does not vary cyclically; power is constant. ....Keith |
#7
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wrote:
W5DXP wrote: Jim Kelley wrote: Nodes and zero crossings aren't necessarily the same thing. They are for standing waves on lossless unterminated lines, by definition. I think not. Standing waves are spatial. At certain points on the line the (NET) voltage is always zero: nodes. For the infinite number of times a snapshot of the voltage is not zero, the node *IS* a zero-crossing point. That is more than obvious from the JAVA applets on this web page. http://www.gmi.edu/~drussell/Demos/s....html#standing In an ideal line terminated by Zo, ... That configuration is not covered by my statement above which applies only to standing waves on lossless unterminated lines. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#8
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Keith wrote:
"---it is this cyclical variation in energy flow which prompted power dudes to invent three phase lines in which energy flow does not vary cycillaly, power is constant." It`s true the wires are shared by multiple phases which peak 120-degrees apart in the 3-phase case. This distributes power flow more evenly with respect to time and reduces peak loads since the phases never coicide. Tesla figured this out 100 years ago. Coincidences of incident and reflected waves are very different from the cyclical variations of a-c. Incident and reflected waves have cyclical voltages and currents. As the reflected wave is just a delayed incident wave, the period is the same for both. In those line spots where the total reflected voltage is 180-degrees different in phase from the incident wave, the net voltage is always zero during the cycle if the reflection is complete on a lossless line. The power is not zero at points where the voltage is always zero because the voltages that add to zero are not zero. In the lossless line, these voltages are full strength, as are the currents at a current null, some 90-degrees away in space from the voltage null on the line. Fact is, both the forward power and the reflected power would measure the same at any point along the line. The wave action has been observed and documented for more than a century. The explanations withstand all arguments, so far. Something new will be needed to replace the ancient wave theory to win acceptance. Keith`s zero power at zero null spots won`t persuade. The power appearing to null is not the whole story when there are forward and reflected powers, each having electric and magnetic fields with phase differences all around. Best regards, Richard Harrison, KB5WZI |
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