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#1
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"W5DXP" wrote in message ... Tarmo Tammaru wrote: There was no actual power generated by the source. How do you know? Was it 100% efficient and consumed no power? -- 73, Cecil http://www.qsl.net/w5dxp The output rose to the open circuit value. Actually, I had thought of building a very efficient class C amplifier and calibrating the output power in terms of DC collector current, but think it is a waste of time. Tam/WB2TT -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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#2
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Tarmo Tammaru wrote:
The output rose to the open circuit value. Assuming you are talking about voltage, for a Norton equivalent, that's a very lossy situation. What was your source? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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#3
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"Cecil Moore" wrote in message ... Tarmo Tammaru wrote: The output rose to the open circuit value. Assuming you are talking about voltage, for a Norton equivalent, that's a very lossy situation. What was your source? -- 73, Cecil http://www.qsl.net/w5dxp The source was an MFJ269, and as I mentioned, the external series resistor was 75 Ohms. I should try it with something like 1K. Coax was ~100 feet of 9913. My scope is only good to 100 MHz; so, I have to keep the frequency down. BTW, I have met Ed Norton. Tam/WB2TT |
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