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"Dr. Slick" wrote in message om... "Tarmo Tammaru" wrote in message ... "Dr. Slick" wrote in message om... But they never explain WHY a lossy line can INCREASE the reflected power! The lossless line would not attenuate the reflected wave at all! I don't trust their claims on this. If you get more power reflected than you send into a passive network, you are getting energy from nowhere, and are thus violating conservation of energy. But the reflection coefficient is for Voltage. I think the clew lies in "The main point of interest lies in the fact that we cannot, in general, superpose the average powers carried by incident and reflected waves on a dissipative line, although we could do so on a lossless line" A/C/F . I don't see the problem. 100 /_30 degrees divided by 2/_5 degrees is 50/_15 degrees. Different phase angle. By general case they mean not the lossless case. I believe you mean 50 @ 25 degrees. Yeah, I started typing this line before I had decided what numbers to use. Also, they go from equation 5.12 to 5.13 without showing us how they got there. They use the identity e**jx = cos x + jsin x Yes? And? How did they get the Zo=(Zn-1)/(Zn+1) from this? I think the math is the same as for a lossless line As I said out front. The book is copyrighted 1960. There is a certain life to these things. Tam But it seems to be out of print, perhaps with good reason... Slick The "print file" for a book used to be stored on hundreds of tin or lead plates. Two N pages per plate. After printing some number of books, these plates would have been recycled. I don't know that there was not a newer edition. Tam/WB2TT |
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#2
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"Tarmo Tammaru" wrote in message ...
But they never explain WHY a lossy line can INCREASE the reflected power! The lossless line would not attenuate the reflected wave at all! I don't trust their claims on this. If you get more power reflected than you send into a passive network, you are getting energy from nowhere, and are thus violating conservation of energy. But the reflection coefficient is for Voltage. I think the clew lies in "The main point of interest lies in the fact that we cannot, in general, superpose the average powers carried by incident and reflected waves on a dissipative line, although we could do so on a lossless line" A/C/F But the square of the MAGNITUDE of the Voltage RC is the power RC. They never tell us why, and i don't think a lossy line will increase your chances of getting rho1. In fact, i don't believe this is possible with a passive network. Also, they go from equation 5.12 to 5.13 without showing us how they got there. They use the identity e**jx = cos x + jsin x Yes? And? How did they get the Zo=(Zn-1)/(Zn+1) from this? I think the math is the same as for a lossless line What is not understood is how one gets from: Voltage R. C.= (Vr/Vi)e**(2*y*z) where y=sqrt((R+j*omega*L)(G+j*omega*C)) and z= distance from load To: Voltage RC=(Z1-Z0)/(Z1+Z0) for purely real Zo or Voltage RC=(Z1-Z0*)/(Z1+Z0) And i have NO problems with the normalized formula, AS LONG AS Zo IS PURELY REAL. If Zo is complex, then Zo*/Zo is certainly NOT equal to one! I don't really trust this book too much, maybe that's why it is out of print. The "print file" for a book used to be stored on hundreds of tin or lead plates. Two N pages per plate. After printing some number of books, these plates would have been recycled. I don't know that there was not a newer edition. Tam/WB2TT A book can always be reprinted if there is a demand. Possibly no one bought the book because it's incorrect? Slick |
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