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Old September 3rd 03, 11:03 PM
Cecil Moore
 
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Roy Lewallen wrote:
Again, I welcome an alternate solution that accounts for all the
voltages, currents, and powers, including one that does it with rho 1.


It dawned on me, just now in the shower, what is happening here. When
you introduced the 'x' parameter, the distance from the load, you
introduced a 2-port network analysis, be it an s-, h-, y-, z-, or
whatever-parameter analysis. And of course there are four power
terms in a 2-port analysis. There a

1. The power reflected from the network input back toward the source. |s11|^2

2. The power transmitted through the network port toward the load. |s21|^2

3. The power re-reflected from the network output back toward the load. |s22|^2

4. The power transmitted through the network port toward the source. |s12|^2

These are the four powers you calculated and you consider only |s12|^2 to
be forward power. That is an error. |s22|^2 is also forward power. These
two forward power flow vectors have to be added to obtain the total
forward Poynting vector. I do believe that clears up the confusion.
--
73, Cecil http://www.qsl.net/w5dxp



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Old September 3rd 03, 11:32 PM
Roy Lewallen
 
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Clears up what confusion?

Nowhere in my analysis is s11, s12, or s22 mentioned. I don't consider
s12 or s22 to be anything at all, and don't make any claim whatsoevera
about what they are or aren't. Which step or steps of my analysis is/are
incorrect? And in terms of voltages, currents, and powers, why?

Roy Lewallen, W7EL

Cecil Moore wrote:
Roy Lewallen wrote:

Again, I welcome an alternate solution that accounts for all the
voltages, currents, and powers, including one that does it with rho 1.



It dawned on me, just now in the shower, what is happening here. When
you introduced the 'x' parameter, the distance from the load, you
introduced a 2-port network analysis, be it an s-, h-, y-, z-, or
whatever-parameter analysis. And of course there are four power
terms in a 2-port analysis. There a

1. The power reflected from the network input back toward the source.
|s11|^2

2. The power transmitted through the network port toward the load. |s21|^2

3. The power re-reflected from the network output back toward the load.
|s22|^2

4. The power transmitted through the network port toward the source.
|s12|^2

These are the four powers you calculated and you consider only |s12|^2 to
be forward power. That is an error. |s22|^2 is also forward power. These
two forward power flow vectors have to be added to obtain the total
forward Poynting vector. I do believe that clears up the confusion.


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Old September 4th 03, 12:39 AM
 
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Cecil Moore wrote:

1. The power reflected from the network input back toward the source. |s11|^2

2. The power transmitted through the network port toward the load. |s21|^2

3. The power re-reflected from the network output back toward the load. |s22|^2

4. The power transmitted through the network port toward the source. |s12|^2

These are the four powers you calculated and you consider only |s12|^2 to
be forward power. That is an error. |s22|^2 is also forward power. These
two forward power flow vectors have to be added to obtain the total
forward Poynting vector. I do believe that clears up the confusion.


Was not the discussion about powers on the source side?
Is not |s22|^2 on the load side?

....Keith
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Old September 4th 03, 12:57 AM
Cecil Moore
 
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wrote:

Cecil Moore wrote:

1. The power reflected from the network input back toward the source. |s11|^2

2. The power transmitted through the network port toward the load. |s21|^2

3. The power re-reflected from the network output back toward the load. |s22|^2

4. The power transmitted through the network port toward the source. |s12|^2

These are the four powers you calculated and you consider only |s12|^2 to
be forward power. That is an error. |s22|^2 is also forward power. These
two forward power flow vectors have to be added to obtain the total
forward Poynting vector. I do believe that clears up the confusion.


Was not the discussion about powers on the source side?
Is not |s22|^2 on the load side?


Roy apparently doesn't realize it, but when he introduced 'x' into his
equations, he introduced 2-port analysis terms so, in his math, there are
indeed two powers existing on the load side. That's what got him confused
and he forgot to include those terms in his forward power and reflected
power, i.e. his rP is not all of the reflected power and his fP
is not all of the forward power. It's an easy mistake to make. But to
compound his mistake, he then combined those two terms on the load side,
one reflected and one forward, into one term so it is difficult to determine
which way its power flow vector points.
--
73, Cecil
http://www.qsl.net/w5dxp



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