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"Reg Edwards" wrote in message ...
When the line is not lossless, ie., it has appreciable attenuation in dB per 1/4-wavelength, then the ratio is 'distorted' and has a phase angle. So negative values of indicated SWR can be expected at some values of | Vmax | / | Vmin | What are you talking about? If it have losses, and they are dissipative losses, the amplitude of the voltage will decrease due to voltage drops. That would be moving AWAY from having a greater reflected voltage than an incident one. But, that's impossible anyways with a passive network. The concept of Negative SWRs is rubbish. SWR is calculated from the square of | rho |. As I've said before, immediately | rho | is squared, half the information it contains is junked. Any discussion/argument about power waves following rho-squared on a lossy (a real ) line is meaningless piffle. Anybody who writes books about power waves, selling them to make a living, is obtaining money under false pretences. On the other hand we should be kind to otherwise unemployed Ph.D's. They too have wive's and kid's to clothe, feed and provide a roof over their heads. That's life! --- Reg. Remind me not to be YOUR book when it comes out! The ratio Pref/Pfwd is directly related to the ratio [rho]. Pref/Pfwd = [rho]**2 Absolute value brackets are a must! Consider that after the absolute value brackets, the phase information is gone. But since we are going to a ratio of average (RMS) values OR peak values of power, it doesn't matter. In other words, if you use V**2/R, the "V" can be either peak or RMS, it doesn't matter, because it is a ratio. And of course, the "R" doesn't matter either. And of course, the phase information is gone with the absolute value brackets. If you agree that the Pref/Pfwd ratio cannot be greater than 1 for a passive network, then neither can the [Vref/Vfwd]= rho be greater than 1 either. Some people wanna rewrite some books here. Slick |
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If the loss per unit wavelength is large enough, and you produced a plot of
voltage vs. distance x. The voltage maximum would be at the source, and the voltage minimum at the load. Try a thousand miles or so of RG58 at 60 Hz. I suspect that to see anything that looks like a standing wave you would have to look at dV/dx. Remember, I can always define a lossier line. Tam/WB2TT |
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