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Rho = (Zload-Zo*)/(Zload+Zo), for complex Zo

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September 18th 03, 03:20 AM

Dr. Slick

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Its not. Its 3.8 volts, which is entirely consistent with circuit
theory and 'classic' rho. Not only is it higher than the incident
voltage, it is higher than the source voltage.

Ok, now take the capacitor off, and measure the voltage at the end
of the inductor. What do you get?

And the reflected power can never be greater than the incident.

Classic rho does seem to produce all the proper voltages.
And using the equations implemented in a directional voltmeter,
we get back the expected Vfwd and Vrev.

Using revised rho does not produce the voltages computed with
circuit theory, nor those measured on the bench.
So revised rho does not seem to be the answer to the power
dilemma.

...Keith

Not really. A rho= -1 means something else with a complex
Zo.

Hint: What is the center of the Smith Chart when it is normalized
to Zo=50+j50?

Slick

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