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Rho = (Zload-Zo*)/(Zload+Zo), for complex Zo

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September 21st 03, 02:59 PM

pez

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| wrote:
| ...
| As has been aptly demonstrated in another thread, it does
| not work for lines with complex Z0.
| ...

Dear Keith,

Could you tell me please
in which thread?

Sincerely,

pez
SV7BAX

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