| Home |
| Search |
| Today's Posts |
|
|
|
#2
September 11th 03, 07:45 AM
|
|||
|
|||
(Garvin) wrote in message om...
(Tom Bruhns) wrote in message om... .... If you want dissipated power in a TEM line, then P=Irms^2*R+Erms^2*G (at a particular frequency where R and G have fixed values). Since Irms and Erms are functions of position along the line, I would dissagree with this last statement. The root mean square is a type of averaging (not really just the average though), so how could it be a function of position?? Well, not surprising. You seem to dissssagree with just about everything... The RMS is of course an average, "the square root of the mean [average] squared value...," but it's a time average, not a position average. There is an RMS current associated with every point along the line, and because of standing waves, it's not the same everywhere. Similarly with RMS voltage. If you wish, you can use instantaneous current and voltage and integrate over time as well, but that's just performing the RMS function. Putting it another way that's even easier to see, would you expect the RMS current in my refrigerator power cord to be the same as in my blender power cord? Clearly, RMS current CAN be a function of location. And with standing waves, or with attenuation along the line, or both, it SHOULD be pretty clear that it can be a function of position along a TEM line. |
| Reply |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|
Hybrid Mode
