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#251
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Cecil,
I thought that we were considering steady state single frequency sine waves. The whole thing becomes so much more straight forward when talking about pulses..... Tam/WB2TT "Cecil Moore" wrote in message ... Tarmo Tammaru wrote: There are models for both lossy and non lossy transmission line. I have not used them, so it might take some learning. I can tell you though that given a load and transmission line, if you find the Z at the meter with an HP vector impedance meter, and then put a lumped impedance of that same value at the meter, you will get the same results. Not in reality, you won't. Any TV ghosting that exists because of reflections will disappear when you go to a lumped impedance. And the noise across the lumped impedance will not be identical to the noise associated with a long transmission line. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#252
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"Jim Kelley" wrote in message ... Tarmo's simulation results seem to conflict with Richard's interpretation of Chipman. Lately you've been leaning toward Richard's point of view. How does the story end? ;-) 73, Jim AC6XG Jim, It probably can't be proven, unless somebody comes up with an alternative definition for SWR. If you look at my simulator equations of a few listings back, I proved that what my model (and the Bird wattmeter) call SWR is RL/Z0. So, unless I screwed up, running any number of simulations is not going to disprove that. If you look at textbook examples where they transmit pulses, The source impedance determines what V+ is, and whether there is a second reflection from the source, but NOT what the reflection at the load end is. Lets delve on this for a second. It seems fair to say that if the source impedance determines V+, clearly it has an effect on V-. But, that does not mean it has anything to do with rho. Tam/WB2TT |
#253
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Tarmo Tammaru wrote:
Jim, It probably can't be proven, unless somebody comes up with an alternative definition for SWR. If you look at my simulator equations of a few listings back, I proved that what my model (and the Bird wattmeter) call SWR is RL/Z0. So, unless I screwed up, running any number of simulations is not going to disprove that. It's hard to imagine how Rs (Zs) could have any effect on that ratio. If you look at textbook examples where they transmit pulses, The source impedance determines what V+ is, and whether there is a second reflection from the source, but NOT what the reflection at the load end is. Unless I = 0, source impedance should certainly have an effect on source voltage. My car battery this morning comes to mind. Seemed to have developed a high internal resistance. It's doing some serious current limiting. Chipmans explanation re-reflection was eloquent I thought. Lets delve on this for a second. It seems fair to say that if the source impedance determines V+, clearly it has an effect on V-. But, that does not mean it has anything to do with rho. I don't know how else to look at it. The question that comes to mind is whether the argument is about the effect source impedance has on actual SWR, or the effect it has on measured SWR - considering the real world limitations of metering instruments. Perhaps people are talking about different things. 73, Jim AC6XG |
#254
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Tarmo Tammaru wrote:
It seems fair to say that if the source impedance determines V+, clearly it has an effect on V-. But, that does not mean it has anything to do with rho. Chipman seems to say that an SWR meter can be disturbed by a localized energy exchange between reactive values with opposite signs. The impedance of the source has an effect upon where in the transmission line those localized energy exchanges occur. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#255
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Jim Kelley wrote:
It's hard to imagine how Rs (Zs) could have any effect on that ratio. Consider a reactive load where energy can be locally exchanged between the load reactance and the impedance looking back into the feedline. Zs can certainly affect the impedance looking back into the feedline. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#256
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Jim Kelley wrote:
It's hard to imagine how Rs (Zs) could have any effect on that ratio. Here's an interesting quote from _Transmission_Lines_, by Chipman, page 175: "Equation (8.27) demonstrates explicitly that the shape of a standing wave pattern representing |V(d)| as a function of d on a transmission line is in no way affected by the quantities, Vs, Zs, and rho(s) at the source." -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#257
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Source impedance DOES affect the amount of energy moving in and sloshing
around in a transmission line. It DOESN'T affect the ratio of forward to reflected waves, and therefore DOESN'T affect the SWR. Once again, here's a way to see why. I'll restrict the discussion to a lossless line for simplicity. When you first turn the source on, a forward wave (voltage and current) travels toward the load. The source impedance does play a role in determining the size of this wave; it can be determined by analysis of a simple voltage divider circuit, with the source voltage dividing between the source impedance and the line Z0. A portion of the forward wave is reflected from the load unless the line is perfectly matched. The fraction which is reflected has nothing to do with the source impedance, and in fact it can easily be calculated from only the line and load impedances. That fraction (magnitude and angle) is known as the reflection coefficient -- you can find the formula in any transmission line text, or derive it yourself very easily. Take a look at the system just before the reflected wave returns to the source. At each point along the line we have a forward wave and a reflected wave, which vectorially add. These create standing waves and, if the line is long enough, we can calculate the SWR directly as the ratio of maximum to minimum voltage along the line. A little bit of algebra will show that the SWR is determined entirely by the ratio of forward to reflected waves -- their absolute values don't matter (except, of course, as it affects their ratio). Given a reflection coefficient, you can calculate the SWR. Ok, now suppose that some fraction of the returning wave reflects from the source and heads back toward the load. Say, X percent of it. When it reaches the load, exactly the same fraction of it is reflected as was the case for the original forward wave. That is, if the new forward wave is X percent of the original, then the new reflected wave is also X percent of the original reflected wave. If we add the new forward and reflected waves to the original ones, and take the ratio of forward to reverse, we find that the ratio of the new, combined forward wave to the new, combined reflected wave is exactly the same as it was for the first forward and reflected waves. It doesn't matter what X is -- no matter what fraction of the reflected wave bounces off the source, the same fraction of that new forward wave is reflected from the load. The SWR is the same as it was for the original pair of waves. Eventually, we build up a large number of pairs of forward and reflected waves. And the ratio of each forward wave to its corresponding reflected wave is always the same -- it's the reflection coefficient of the load. So when we add all the forward waves into a single forward wave and all the reflected waves into a single reflected wave, we get the same ratio. And that ratio doesn't depend in any way on the source impedance or what fraction of each returning wave is re-reflected from the source. One of the nice things about this way of looking at it is that it's entirely supported by the theory and equations describing transmission line operation which engineers have used to design working systems for the past hundred years or so. Roy Lewallen, W7EL Cecil Moore wrote: Jim Kelley wrote: It's hard to imagine how Rs (Zs) could have any effect on that ratio. Consider a reactive load where energy can be locally exchanged between the load reactance and the impedance looking back into the feedline. Zs can certainly affect the impedance looking back into the feedline. |
#258
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Holy mackrel, Mr. Science!
But gee, you can see that from even a casual glance at the equations you'll find in virtually any transmission line text. It's kind of like saying that wow, Terman concludes that resistance is voltage divided by current, so now we can believe it too. People who believe that SWR is affected by source impedance have either rejected established theory, or don't have the background or interest to read and understand what we consider to be very simple equations. So I'd hardly expect them to be impressed by someone pointing out what the equations and established theory say clearly and unambigously. You can't fight Ouija boards with math. Roy Lewallen, W7EL Cecil Moore wrote: Jim Kelley wrote: It's hard to imagine how Rs (Zs) could have any effect on that ratio. Here's an interesting quote from _Transmission_Lines_, by Chipman, page 175: "Equation (8.27) demonstrates explicitly that the shape of a standing wave pattern representing |V(d)| as a function of d on a transmission line is in no way affected by the quantities, Vs, Zs, and rho(s) at the source." |
#259
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Source impedance DOES affect the amount of energy moving in and sloshing
around in a transmission line. It DOESN'T affect the ratio of forward to reflected waves, and therefore DOESN'T affect the SWR. =========================== But it DOES affect the indicated SWR and so the indicated SWR is incorrect. It is the meter which is at fault ! It is designed to indicate correctly only when the source is 50 ohms. Here's the proof - Rho = (50-Zt) / (50+Zt) - which you may have seen before. SWR, of course, is calculated from Rho and the meter scale is calibrated accordingly. If the source is not what the meter expects then it gives the wrong answers. And its faithful worshippers believe it! --- Reg, G4FGQ |
#260
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Tarmo Tammaru wrote:
I thought that we were considering steady state single frequency sine waves. The whole thing becomes so much more straight forward when talking about pulses..... It is still straight forward when we take reality into account. :-) Pure steady state single frequency sine waves, sans noise and/or jitter, exist only in the human mind. -- 73, Cecil, W5DXP |
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