On Fri, 03 Oct 2003 14:48:38 -0500, Cecil Moore
wrote:

Jim Kelley wrote:
As I said, the reflection coefficient at '+' can be calculated
accurately using just the characteristic impedances, as shown by Born
and Wolf.

Why is this so hard for you to understand? What is the rho
of the following?

source---50 ohm feedline---+---150 ohm feedline---load150

"Just the characteristic impedances" are given. You say you
can "calculate rho accurately" from just that. So prove your
statement. (load150 means the load is not equal to 150 ohms)


Howzabout (as a variation of another posting):
source50---50 ohm feedline---+---150 ohm feedline---load150

If it is so easy for you, and difficult for Jim, this should be a
slam-dunk.... But I won't hold my breath for either of my posts to
find a literal, numeric answer.

I also promise no more follow-up responses to either thread where no
solution (a numeric one, not a philosophical treatise) is presented.
;-)

73's
Richard Clark, KB7QHC

Richard Clark wrote:
Howzabout (as a variation of another posting):
source50---50 ohm feedline---+---150 ohm feedline---load150

If it is so easy for you, and difficult for Jim, this should be a
slam-dunk....

It is not easy for me or anyone else. It is impossible to accurately
calculate rho just from the above information. Jim is the one who
says it's easy. I say it's impossible. Did you read Roy's thoughts
on the subject?
--
73, Cecil, W5DXP