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#1
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On Mon, 6 Oct 2003 14:38:48 -0400, "Tarmo Tammaru" wrote:
"Walter Maxwell" wrote in message .. . This concept is foreign to me, so if I'm wrong I'd like to have some proof that the source impedance can have any influence on SWR. Walt Walt, I don't think the source impedance has any effect on SWR. In fact I have changed the source impedance and saw no change in SWR. But Since tha SWR meter is a really dumb bunny, I wonder of the meter can be mislead by a reactive source impedance that forces the current to be out of phase with the voltage. Perhaps a case where the source and load both are reactive? Tam/WB2TT Tam, I totally disagree with those who say SWR appearing on a mismatched transmission line is dependent on the source impedance. If I understand Richard C correctly, he claims with 'bullet-poof' certainty that SWR is dependent on the source impedance. And if I understand Reg's earlier statement correctly, he shares Richard's position. I asked Reg for clarification, but he has not yet responded. Richard C, you suggest we step up to the bench and perform your experiment that will prove you are correct. If you described this experiment to me earlier I invoke my Alzheimer's excuse for not remembering it. So would you please repeat it for my benefit? I'll be back at my Florida lab by Oct 22, and am anxious to perform it. And Richard H, thanks for the support. More than 50 years of lab and professional work on transmission lines have never shown the source impedance to have any effect on propagation along the line, other than to influence the magnitude of the signal as it enters and propagates along the line. Walt, W2DU |
#2
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On Mon, 06 Oct 2003 21:10:25 GMT, Walter Maxwell wrote:
Richard C, you suggest we step up to the bench and perform your experiment that will prove you are correct. Hi Walt, This is a misrepresentation of my work. I responded here that the appearance of poor criticism suggests that my work is bulletproof (among a spectrum of equal likelihoods) and my statement is a critique of that shoddy work being offered as rebut to my data. Further, I make no pretense that such an experiment will prove me correct and I have offered on more than one occasion that someone with care equal to mine could easily find data that refutes mine. I have no illusions to being "correct" and have freely admitted that everything I do contains error. However, I do, by training and experience, exhibit those bounds of accuracy where others simply caterwaul on that they need no lessons in the matter and further would never "change their mind." Now, if this appears to be backtracking, it is evident only to those who will never attempt anything at the bench and have no capacity to weigh their own sources of error - either of judgement or demonstrable skill. In conclusion, it is certainly an illusion to imagine that anything is ever concluded. The best I can achieve is a confluence of thought with one or several in educating rather exotic issues that lie outside of the experience of many. There is nothing inherently common about this, and is of interest to only those who aspire to accuracy, a very limited audience. The larger point that is germane to the whole of the audience is found in the conduct of analysis, its support or its refutation. The scientific community does not brook simple nay-saying and the shotgun approach to cut-and-paste arguments offered as rebuttal. I have described methods and results. My methods can be challenged, my results can be shown irreproducible. I have offered tangible, testable propositions, means, and results to which absolutely nothing of equal merit has been put forward to provide a meaningful assault. It is in that context that the appearance of a bulletproof presentation has been suggested by me. :-) The irony of my comments lies in the simple observation that this only takes two resistors and a hank of line for one such test. The magnitude of effort, as evidenced by those simple constraints suggests that my critics are seriously skill impaired to offer honest testing. I am content to stand above such midgets even if I have to stoop so as to not make it so overwhelmingly and embarrassingly obvious. 73's Richard Clark, KB7QHC |
#3
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![]() "Walter Maxwell" wrote in message ... Tam, I totally disagree with those who say SWR appearing on a mismatched transmission line is dependent on the source impedance. Walter, I agree with you. But I am making a distinction between SWR and *measured* SWR. People who think an SWR meter possesses magic properties should look inside one. It takes one instantaneous sample of the NET voltage V, and one instantaneous sample of the NET current I. It displays the vector sum of K(V + k2I) and K(V- k2I) where K is the sensitivity, and k2 is chosen to make the second equation equal to 0 for a 50 Ohm load. The approximations made in coming up with what is printed on the meter scale assumes that for the forward wave the voltage and current are in phase. I have seen descriptions of how these things work, but no equations to back these up. I suspect one would start with the two equations that I listed, but express I in terms of V and deltaZ, where deltaZ is the deviation from 50 Ohms. K can arbitrarily be 1. I also suspect that Bird, etc don't really want us to know that. Tam/WB2TT |
#4
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On Mon, 6 Oct 2003 20:52:24 -0400, "Tarmo Tammaru" wrote:
"Walter Maxwell" wrote in message .. . Tam, I totally disagree with those who say SWR appearing on a mismatched transmission line is dependent on the source impedance. Walter, I agree with you. But I am making a distinction between SWR and *measured* SWR. People who think an SWR meter possesses magic properties should look inside one. It takes one instantaneous sample of the NET voltage V, and one instantaneous sample of the NET current I. It displays the vector sum of K(V + k2I) and K(V- k2I) where K is the sensitivity, and k2 is chosen to make the second equation equal to 0 for a 50 Ohm load. The approximations made in coming up with what is printed on the meter scale assumes that for the forward wave the voltage and current are in phase. I have seen descriptions of how these things work, but no equations to back these up. I suspect one would start with the two equations that I listed, but express I in terms of V and deltaZ, where deltaZ is the deviation from 50 Ohms. K can arbitrarily be 1. I also suspect that Bird, etc don't really want us to know that. Tam/WB2TT Well, Tam, I agree with you also, but your comments only relate to accuracy, not whether the internal resistance of the source has any influence on the SWR. I'm well acquainted with the various types of swr meters, the Bruene lumped-constant directional coupler, for instance, or for a more professional example, the HP-778D dual directional coupler that I use with an HP-8405A Vector Voltmeter in my own lab. The value of the source resistance can be any value, and its reflection coefficient rho seen looking into the output can be any value from zero to one. If the value is zero it simply means any reflected power reaching the output is absorbed and if rho = 1all reflected power is re-reflected. With any combination of the above the SWR on a mismatched line is the same. The only effect these parameters have on the line is the magnitude of the signal being propagated. I know this from years of experience, beginning with slotted lines, and from the engineering literature. For example, Walter C. Johnson on Page 100 spells it out specifically. What I'd like to see is for those who say SWR is dependent on the source impedance to show how and why this what I call 'misconception' can occur. Walt, W2DU |
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