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#1
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Huh?
Humor me, in what way does that equation constitute proof? Where is the source impedance in that equation? An SWR meter will correctly indicate the SWR on a transmission line if the transmission line connected to its output equals the design impedance of the meter, regardless of the source impedance. If the transmission line connected to its output doesn't equal the design impedance of the meter, the meter won't correctly indicate the SWR on the the transmission line, again regardless of the source impedance. Why does this seem so complicated? Roy Lewallen, W7EL Reg Edwards wrote: Source impedance DOES affect the amount of energy moving in and sloshing around in a transmission line. It DOESN'T affect the ratio of forward to reflected waves, and therefore DOESN'T affect the SWR. =========================== But it DOES affect the indicated SWR and so the indicated SWR is incorrect. It is the meter which is at fault ! It is designed to indicate correctly only when the source is 50 ohms. Here's the proof - Rho = (50-Zt) / (50+Zt) - which you may have seen before. SWR, of course, is calculated from Rho and the meter scale is calibrated accordingly. If the source is not what the meter expects then it gives the wrong answers. And its faithful worshippers believe it! --- Reg, G4FGQ |
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#2
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Roy Lewallen wrote:
Why does this seem so complicated? The SWR bridge circuitry may not correctly display the actual SWR. Please see my latest response to Tarmo. The SWR bridge samples the current and voltage and performs a phasor addition and subtraction to get voltages proportional to the forward and reflected powers. If there is a high voltage caused by reactive components, it will be close to 90 degrees away from the current. But phasor adding these two values gives something slightly greater in magnitude than the high reactive voltage. That high voltage gets rectified and displayed as the forward power when it is not actually the forward power but reactive power flowing from one reactance to another. -- 73, Cecil, W5DXP |
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#3
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Cecil Moore wrote: The SWR bridge samples the current and voltage and performs a phasor addition and subtraction to get voltages proportional to the forward and reflected powers. If there is a high voltage caused by reactive components, it will be close to 90 degrees away from the current. But phasor adding these two values gives something slightly greater in magnitude than the high reactive voltage. That high voltage gets rectified and displayed as the forward power when it is not actually the forward power but reactive power flowing from one reactance to another. -- 73, Cecil, W5DXP The power flow fairy sure has a lot of warts. :-) 73, jk ac6xg |
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#4
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Cecil Moore wrote:
Roy Lewallen wrote: Why does this seem so complicated? The SWR bridge circuitry may not correctly display the actual SWR. Please see my latest response to Tarmo. The SWR bridge samples the current and voltage and performs a phasor addition and subtraction to get voltages proportional to the forward and reflected powers. If there is a high voltage caused by reactive components, it will be close to 90 degrees away from the current. But phasor adding these two values gives something slightly greater in magnitude than the high reactive voltage. That high voltage gets rectified and displayed as the forward power when it is not actually the forward power but reactive power flowing from one reactance to another. Even in this unusual situation, the behavior of the meter is completely predictable, including the incorrect power indication. Remember that the meter doesn't actually measure power - it is only *calibrated* to *indicate* power. When placed in a situation where its calibration is not valid, then of course it won't indicate power correctly. But even its wrong indication can be predicted if you know the detailed values to plug into a circuit model. There's really no mystery about it. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
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#5
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Ian White, G3SEK wrote:
Even in this unusual situation, the behavior of the meter is completely predictable, including the incorrect power indication. There's really no mystery about it. My point exactly! So, in the same vein, can the source impedance adversely affect the SWR meter reading? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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#6
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Cecil Moore wrote:
Ian White, G3SEK wrote: Even in this unusual situation, the behavior of the meter is completely predictable, including the incorrect power indication. There's really no mystery about it. My point exactly! So, in the same vein, can the source impedance adversely affect the SWR meter reading? It will affect both the forward and reverse readings, but in equal proportion, so it won't affect the indicated or calculated SWR (unless there are nonlinearities in the meter, or the meter is not being used correctly). -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
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#7
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Ian White, G3SEK wrote:
Cecil Moore wrote: My point exactly! So, in the same vein, can the source impedance adversely affect the SWR meter reading? It will affect both the forward and reverse readings, but in equal proportion, so it won't affect the indicated or calculated SWR (unless there are nonlinearities in the meter, or the meter is not being used correctly). How about what Chipman says? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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